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easy one


flamebirde
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double the smaller number, add to the larger

7*8 = (2x7) + 8 = 22

That won't work, 'cause 4*9 would be 17 not 21.

A variation to that theme which would work is: if second number is smaller, then [first number] + twice [second number], else, [first number] + twice second number] - 1. That is quite inelegant, and does not solve for instance of both numbers the same. Back to thinking further outside cube.

Edited by Caliban27
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