Guest Posted November 2, 2011 Report Share Posted November 2, 2011 This is fun... http://www.drunkmenworkhere.org/170 Quote Link to comment Share on other sites More sharing options...
0 Molly Mae Posted November 2, 2011 Report Share Posted November 2, 2011 This is fun... http://www.drunkmenworkhere.org/170 Holy nice find. Quote Link to comment Share on other sites More sharing options...
0 voider Posted November 3, 2011 Report Share Posted November 3, 2011 All answers to question 1 are wrong. Quote Link to comment Share on other sites More sharing options...
0 curr3nt Posted November 3, 2011 Report Share Posted November 3, 2011 Solved it. That was a mess...but fun. I got a correct answer for #1 Quote Link to comment Share on other sites More sharing options...
0 voider Posted November 4, 2011 Report Share Posted November 4, 2011 If you look closely all answers (including 4 which looks almost the same) have a strike through them regardless. What do you claim your correct answer for question 1 is? Quote Link to comment Share on other sites More sharing options...
0 curr3nt Posted November 4, 2011 Report Share Posted November 4, 2011 The questions will be marked wrong until they are true. #1 can't be A or B. If A then #1 answer would have to be B to be correct. If B then #2 would have to be the first question with the answer B but #1 would actually be the first with the answer B. So it has to be C, D or E. Check one of them and then make the corresponding question a B. You'll see that #1 is now marked true. You could have the correct answer for a question set but it will be flagged incorrect until the related questions have been answered correctly. There are 5 A, 5 B, 7 D and 3 E. This will give you the straight answer to some of the questions and should help you find the rest. Quote Link to comment Share on other sites More sharing options...
0 MissKitten Posted November 6, 2011 Report Share Posted November 6, 2011 Gah! I give up! Quote Link to comment Share on other sites More sharing options...
0 curr3nt Posted November 7, 2011 Report Share Posted November 7, 2011 You want the answers MiKi? Quote Link to comment Share on other sites More sharing options...
0 MissKitten Posted November 7, 2011 Report Share Posted November 7, 2011 Well, the first five or so would be nice, yeah. Quote Link to comment Share on other sites More sharing options...
0 curr3nt Posted November 7, 2011 Report Share Posted November 7, 2011 (edited) I'll give you the answer to #20. 20 - E As said earlier there are 5 A and B, 7 D and 3 E. These numbers give you the answers to the following: 3 - D 4 - B 8 - E 12 - A 14 - B 15 - A 13 - D 18 - A #1 can't be A because then #1 would have to be B or B because then #2 would then be the 2nd B so the next B answer is #4 => 1 - D #5 can't be A, B, C or D => 5 - E #10 and #16 have to be 10 - A and 16 - D since that is the only pairing that works. Since #13 is D; 9 and 11 can't be A so #2 can't be D or E. Since all 3 E's have been used #2 can't be B or C => 2 - A #9 can't be A, C or E, if #9 was B then #11 couldn't be B => 9 - D #6 and #17 have to be B and D or D and B. If #17 was D then #16 = #17 which would make #2 wrong. => 6 - D and 17 - B and 7 - D per #2 11 - B 19 - B to make everything true. and I had to get here without knowing the letter counts in the first place Edited November 7, 2011 by curr3nt Quote Link to comment Share on other sites More sharing options...
0 MissKitten Posted November 10, 2011 Report Share Posted November 10, 2011 W00t! Solved it! Gracias, mi amigo. Quote Link to comment Share on other sites More sharing options...
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