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Four Letters ROLLO


TheCube
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Score Changes: none yet

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unreality - 37

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mEEster-Michael - 31

Shadow7 - 25

curr3nt - 20

Shakingdavid - 17

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Dej Mar - 5

Edited by WombatBreath
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BREE

If =3 then BRE- as Babe=1, plEa=1, tREe=2 and help=0

If =2 then ---E as babE=1, Plea=1 or plEa=1, trEE=2 or tReE=2, and help=0

If =1 then TAEL as bAbe=1, plEa=1, TrEe=2 and help=0

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????

HELP - 0 

PLEA - 1 

BABE - 1 

TREE - 2 

BREE - 2 


Score Changes: none yet (pending Dej Mar clarification)

Sorry Dej Mar, maybe I'm being thick, but I can't see how what you've provided is a definitive proof. I'm not saying that you are either right or wrong but I can't see any proof provided.

You said "If =2 then ---E as babE=1, Plea=1 or plEa=1, trEE=2 or tReE=2, and help=0"

How are the Bs or A of "babe" disproved?

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????

HELP - 0 

PLEA - 1 

BABE - 1 

TREE - 2 

BREE - 2 


Score Changes: none yet (pending Dej Mar clarification)

Sorry Dej Mar, maybe I'm being thick, but I can't see how what you've provided is a definitive proof. I'm not saying that you are either right or wrong but I can't see any proof provided.

You said "If =2 then ---E as babE=1, Plea=1 or plEa=1, trEE=2 or tReE=2, and help=0"

How are the Bs or A of "babe" disproved?

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If P in Plea=1 and if A in Babe=1

then EE in trEE=2 and the word would be PAEE (not a word)

If P in Plea=1, the 2nd B in baBe<>1 as tReE=2 would indicate that baBE=2 which it isnt

If P in Plea=1, and if the E in babE=1 then the R in tReE=2 or the 1st E in trEE=2

Of the former PR-E and the latter P-EE, there is no word of the form P-EE, thus if

the former PR-E, then only the 2nd E is proven..thus "if BREE=2, then ---E".

If L in pLea=1 and 1st B in Babe=1 then trEE<>2 as BabE would=2

If L in pLea=1 and 2nd B in baBe=1 then TreE<>2 as baBE would=2

If L in pLea=1 and E in babE=1 then either TL-E or -LEE. Of the former, there is

no word TL-E, of the latter there are several possible words, but again BREE would

only =2 and only the 2nd E is proven.

If the E in plEa=1 and the B in Babe=1

then either -RE- or --EE in tree=2, and the word would be of the form BRE- or B-EE.

For B-EE, only two words exists BREE and BLEE, which it can not be BLEE as pLEa<>2.

And BRE- would have BREE=3.

If the E in plEa=1 and the A in bAbe=1 then either the T-E- or --EE in tree=2.

The possible word forms are TAE- and -AEE. There is no valid word of the form -AEE,

and only one word of the form TAE- (TAEL), thus if BREE=1, then TAEL.

If the E in plEa=1 and the E in babE=1 then --EE in trEE=2. But, again, because of

PR-E as a possiblity, only the 2nd E is proven.

If the A in pleA=1 and the 1st B in Babe=1 then -RE- in tREe=2 and the word is BREA, which

is not a valid English word in the given ROLO dictionaries (it is in the Wiktionary as a Spanish

word for tar, pitch; tarpaulin, and West Frisian for bread).

If the A in pleA=1 and the A in bAbe=1 then T-E- in TrEe=2 and the word would be TAEA, which is

not a word.

If the A in pleA=1 and the 2nd B in baBe=1 then TRee=2, but TRBA is not a word.

Therefore,

If =3 then BRE- as Babe=1, plEa=1, tREe=2 and help=0

If =2 then ---E as babE=1, Plea=1 or plEa=1, trEE=2 or tReE=2, and help=0

If =1 then TAEL as bAbe=1, plEa=1, TrEe=2 and help=0

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WHEE (are't we having fun?)

if =3 then GHEE (WHEE and GHEE are the only two words where -HEE or W-EE that has not already been eliminated, i.e. trEE=2 and thus not THEE)

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GHEE

HELP - 0 	AKEE - 2 

PLEA - 1 	PRIE - 1 

BABE - 1 	KNEE - 2 

TREE - 2 	WHEE - 3 

BREE - 2 	EPEE - 2 


Score Changes: Dej Mar +25, WbB +10

TheCube - 315

Molly Mae - 238

WombatBreath - 207

Fabpig - 162

Hidden G - 137

kristmark1 - 93

Aaryan - 60

unreality - 37

Bong - 34

mEEster-Michael - 31

Dej Mar - 30

Shadow7 - 25

curr3nt - 20

Shakingdavid - 17

Quag - 5

Edited by WombatBreath
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