superprismatic Posted March 24, 2011 Report Share Posted March 24, 2011 Listed below are 20 poker hands. For each of the hands below, assume it was dealt to you from a full shuffled poker deck of 52 cards. You may stay with the hand you are given or discard any number of its cards. Any discarded cards will be replaced by a random draw from the remaining 47 cards. Your goal is to improve the value of your hand as much as possible. List which cards, if any, you should discard from each of the starting hands below: 1: 10♦ A♠ 10♥ 7♥ 8♣ 2: K♠ 8♣ 9♣ 10♠ J♠ 3: 9♣ 8♦ 8♥ 4♠ J♣ 4: 6♥ K♦ A♦ K♥ 4♦ 5: Q♠ 8♣ A♥ 6♦ 7♠ 6: 3♣ K♠ 5♦ 7♦ 3♥ 7: K♠ 7♥ 2♠ 5♠ J♣ 8: J♦ 10♣ 10♥ 8♣ 9♠ 9: 3♦ 6♠ 5♠ 4♠ 5♦ 10: 5♠ 7♠ 5♦ A♠ Q♥ 11: 4♠ 5♠ 6♠ 7♠ 7♣ 12: 2♠ 3♣ 4♣ 5♣ 6♣ 13: 3♠ 2♣ 3♣ 4♣ 5♣ 14: 2♠ 2♣ 3♣ 4♣ 5♣ 15: J♠ K♠ 2♥ 8♦ Q♠ 16: 2♠ 3♠ 4♠ 5♠ 6♣ 17: 3♦ 4♦ 6♦ K♦ 5♠ 18: 2♦ 8♥ 5♥ 9♣ 6♦ 19: 8♠ Q♦ A♠ K♠ 6♠ 20: 3♣ 4♦ J♥ 2♣ 10♥ [/code] Usual poker hand rankings apply. So, for example, "round the corner" straights are not allowed, although an ace may be either high or low card in a straight. Quote Link to comment Share on other sites More sharing options...
0 plainglazed Posted March 24, 2011 Report Share Posted March 24, 2011 Question - is the strategy to better your hand or should one take into consideration what an opponent is likely to have? Quote Link to comment Share on other sites More sharing options...
0 k-man Posted March 24, 2011 Report Share Posted March 24, 2011 I would discard 1: 7♥ 8♣ 2: K♠ 3: 9♣ 4♠ J♣ 4: 6♥ 4♦ 5: Q♠ 8♣ 6♦ 7♠ 6: K♠ 5♦ 7♦ 7: 7♥ J♣ 8: J♦ 8♣ 9♠ 9: 5♦ 10: 7♠ A♠ Q♥ 11: 7♣ 12: 2♠ 13: 3♠ 14: 2♠ 15: 2♥ 8♦ 16: 6♣ 17: 5♠ 18: 2♦ 8♥ 5♥ 9♣ 6♦ 19: Q♦ 20: 3♣ 4♦ J♥ 2♣ 10♥ Quote Link to comment Share on other sites More sharing options...
0 superprismatic Posted March 24, 2011 Author Report Share Posted March 24, 2011 Question - is the strategy to better your hand or should one take into consideration what an opponent is likely to have? There is no opponent. Just you, a dealer, and a pack of cards. Quote Link to comment Share on other sites More sharing options...
0 superprismatic Posted March 24, 2011 Author Report Share Posted March 24, 2011 I would discard 1: 7♥ 8♣ 2: K♠ 3: 9♣ 4♠ J♣ 4: 6♥ 4♦ 5: Q♠ 8♣ 6♦ 7♠ 6: K♠ 5♦ 7♦ 7: 7♥ J♣ 8: J♦ 8♣ 9♠ 9: 5♦ 10: 7♠ A♠ Q♥ 11: 7♣ 12: 2♠ 13: 3♠ 14: 2♠ 15: 2♥ 8♦ 16: 6♣ 17: 5♠ 18: 2♦ 8♥ 5♥ 9♣ 6♦ 19: Q♦ 20: 3♣ 4♦ J♥ 2♣ 10♥ 8 correct. Quote Link to comment Share on other sites More sharing options...
0 Guest Posted March 24, 2011 Report Share Posted March 24, 2011 (edited) 1: 7♥ 8♣ 2: K♠ 3: 9♣ 4♠ J♣ 4: 6♥ 4♦ 5: Q♠ A♥ 6: 5♦ 7♦ 7: 7♥ J♣ 8: 10♣ 9: 3♦ 5♦ 10: 7♠ Q♥ 11: 7♣ 12: None 13: 3♠ 14: 2♠ 15: 2♥ 8♦ 16: 6♣ 17: 5♠ 18: 2♦ 19: Q♦ 20: J♥ 10♥ Edited March 24, 2011 by Balding Eagle Quote Link to comment Share on other sites More sharing options...
0 superprismatic Posted March 24, 2011 Author Report Share Posted March 24, 2011 (edited) 1: 7♥ 8♣ 2: K♠ 3: 9♣ 4♠ J♣ 4: 6♥ 4♦ 5: Q♠ A♥ 6: 5♦ 7♦ 7: 7♥ J♣ 8: 10♣ 9: 3♦ 5♦ 10: 7♠ Q♥ 11: 7♣ 12: None 13: 3♠ 14: 2♠ 15: 2♥ 8♦ 16: 6♣ 17: 5♠ 18: 2♦ 19: Q♦ 20: J♥ 10♥ Your score is 8 correct. Edited March 24, 2011 by superprismatic Quote Link to comment Share on other sites More sharing options...
0 Guest Posted March 24, 2011 Report Share Posted March 24, 2011 (edited) 1: 7♥ 8♣ 2: K♠ 3: 9♣ 4♠ J♣ 4: 6♥ A♦ 4♦ 5: 8♣ 6♦ 7♠ 6: K♠ 5♦ 7♦ 7: K♠ 7♥ 2♠ 5♠ J♣ 8: 10♣ 9: 5♦ 10:7♠ A♠ Q♥ 11:7♣ 12:2♠ 13:3♠ 14:2♠ 15:J♠ K♠ 2♥ 8♦ Q♠ 16:None 17:5♠ 18:2♦ 8♥ 5♥ 9♣ 6♦ 19:Q♦ 20:3♣ 4♦ J♥ 2♣ 10♥ Edited March 24, 2011 by Balding Eagle Quote Link to comment Share on other sites More sharing options...
0 superprismatic Posted March 24, 2011 Author Report Share Posted March 24, 2011 1: 7♥ 8♣ 2: K♠ 3: 9♣ 4♠ J♣ 4: 6♥ A♦ 4♦ 5: 8♣ 6♦ 7♠ 6: K♠ 5♦ 7♦ 7: K♠ 7♥ 2♠ 5♠ J♣ 8: 10♣ 9: 5♦ 10:7♠ A♠ Q♥ 11:7♣ 12:2♠ 13:3♠ 14:2♠ 15:J♠ K♠ 2♥ 8♦ Q♠ 16:None 17:5♠ 18:2♦ 8♥ 5♥ 9♣ 6♦ 19:Q♦ 20:3♣ 4♦ J♥ 2♣ 10♥ 7 correct. Quote Link to comment Share on other sites More sharing options...
0 plainglazed Posted March 25, 2011 Report Share Posted March 25, 2011 (edited) 2: K♠ 8♣ 9♣ 10♠ J♠ 3: 9♣ 4♠ J♣ 4: 6♥ A♦ 4♦ 5: Q♠ 8♣ 6♦ 7♠ 6: K♠ 5♦ 7♦ 7: K♠ 7♥ 2♠ 5♠ J♣ 8: J♦ 8♣ 9♠ 9: 3♦ 6♠ 4♠ 10: 7♠ A♠ Q♥ 11: 4♠ 5♠ 6♠ 12: none 13: 3♠ 2♣ 3♣ 4♣ 5♣ 14: 3♣ 4♣ 5♣ 15: J♠ K♠ 2♥ 8♦ Q♠ 16: none 17: 3♦ 4♦ 6♦ K♦ 5♠ 18: 2♦ 8♥ 5♥ 9♣ 6♦ 19: 8♠ Q♦ K♠ 6♠ 20: 3♣ 4♦ J♥ 2♣ 10♥1: A♠ 7♥ 8♣ Edited March 25, 2011 by plainglazed Quote Link to comment Share on other sites More sharing options...
0 superprismatic Posted March 25, 2011 Author Report Share Posted March 25, 2011 2: K♠ 8♣ 9♣ 10♠ J♠ 3: 9♣ 4♠ J♣ 4: 6♥ A♦ 4♦ 5: Q♠ 8♣ 6♦ 7♠ 6: K♠ 5♦ 7♦ 7: K♠ 7♥ 2♠ 5♠ J♣ 8: J♦ 8♣ 9♠ 9: 3♦ 6♠ 4♠ 10: 7♠ A♠ Q♥ 11: 4♠ 5♠ 6♠ 12: none 13: 3♠ 2♣ 3♣ 4♣ 5♣ 14: 3♣ 4♣ 5♣ 15: J♠ K♠ 2♥ 8♦ Q♠ 16: none 17: 3♦ 4♦ 6♦ K♦ 5♠ 18: 2♦ 8♥ 5♥ 9♣ 6♦ 19: 8♠ Q♦ K♠ 6♠ 20: 3♣ 4♦ J♥ 2♣ 10♥1: A♠ 7♥ 8♣ 8 correct. Quote Link to comment Share on other sites More sharing options...
0 bushindo Posted March 25, 2011 Report Share Posted March 25, 2011 Listed below are 20 poker hands. For each of the hands below, assume it was dealt to you from a full shuffled poker deck of 52 cards. You may stay with the hand you are given or discard any number of its cards. Any discarded cards will be replaced by a random draw from the remaining 47 cards. Your goal is to improve the value of your hand as much as possible. List which cards, if any, you should discard from each of the starting hands below: 1: 10♦ A♠ 10♥ 7♥ 8♣ 2: K♠ 8♣ 9♣ 10♠ J♠ 3: 9♣ 8♦ 8♥ 4♠ J♣ 4: 6♥ K♦ A♦ K♥ 4♦ 5: Q♠ 8♣ A♥ 6♦ 7♠ 6: 3♣ K♠ 5♦ 7♦ 3♥ 7: K♠ 7♥ 2♠ 5♠ J♣ 8: J♦ 10♣ 10♥ 8♣ 9♠ 9: 3♦ 6♠ 5♠ 4♠ 5♦ 10: 5♠ 7♠ 5♦ A♠ Q♥ 11: 4♠ 5♠ 6♠ 7♠ 7♣ 12: 2♠ 3♣ 4♣ 5♣ 6♣ 13: 3♠ 2♣ 3♣ 4♣ 5♣ 14: 2♠ 2♣ 3♣ 4♣ 5♣ 15: J♠ K♠ 2♥ 8♦ Q♠ 16: 2♠ 3♠ 4♠ 5♠ 6♣ 17: 3♦ 4♦ 6♦ K♦ 5♠ 18: 2♦ 8♥ 5♥ 9♣ 6♦ 19: 8♠ Q♦ A♠ K♠ 6♠ 20: 3♣ 4♦ J♥ 2♣ 10♥ Usual poker hand rankings apply. So, for example, "round the corner" straights are not allowed, although an ace may be either high or low card in a straight. Some clarification please. In the bolded passage, what do you mean by "improve the value of the hand as much as possible"? Does it mean discard the hand so as to maximize the chance of drawing a better hand, and that all better hands count equally? E.g. if we have a pair, then an improvement to 2 pairs counts the same as an improvement to a royal flush? Does it mean discard some cards so that we maximize the expected 'value' of the new hand for some payoff scale? If so, what is that payoff scale? Quote Link to comment Share on other sites More sharing options...
0 Guest Posted March 25, 2011 Report Share Posted March 25, 2011 Discard these: 1: 7♥ 8♣ 2: K♠ 3: 9♣ 4♠ J♣ 4: 6♥ 4♦ 5: Q♠ A♥ 6: 5♦ 7♦ 7: 7♥ J♣ 8: 10♣ 9: 5♦ 10: 7♠ A♠ Q♥ 11: 7♣ 12: - 13: 3♠ 14: 2♠ 15: 2♥ 8♦ 16: - 17: K♦ 18: 2♦ 19: Q♦ 20: 3♣ 4♦ 2♣ Quote Link to comment Share on other sites More sharing options...
0 Guest Posted March 25, 2011 Report Share Posted March 25, 2011 I agree with bushindo. Are we weighing risk vs reward? Otherwise you'd just... keep one card in the royal flush range (or more than one if they're suited) and discard the rest hoping for a royal flush every time regardless of the changes of actually getting it. Quote Link to comment Share on other sites More sharing options...
0 superprismatic Posted March 25, 2011 Author Report Share Posted March 25, 2011 Some clarification please. In the bolded passage, what do you mean by "improve the value of the hand as much as possible"? Does it mean discard the hand so as to maximize the chance of drawing a better hand, and that all better hands count equally? E.g. if we have a pair, then an improvement to 2 pairs counts the same as an improvement to a royal flush? Does it mean discard some cards so that we maximize the expected 'value' of the new hand for some payoff scale? If so, what is that payoff scale? What I mean is to make the expected value of the resulting hand as large as possible. Since there are only 7462 different values for poker hands, we can give the worst possible hand a value of 1,the best possible a value of 7462, and all the others appropriate values in between. I hope that's clear. Quote Link to comment Share on other sites More sharing options...
0 superprismatic Posted March 25, 2011 Author Report Share Posted March 25, 2011 Discard these: 1: 7♥ 8♣ 2: K♠ 3: 9♣ 4♠ J♣ 4: 6♥ 4♦ 5: Q♠ A♥ 6: 5♦ 7♦ 7: 7♥ J♣ 8: 10♣ 9: 5♦ 10: 7♠ A♠ Q♥ 11: 7♣ 12: - 13: 3♠ 14: 2♠ 15: 2♥ 8♦ 16: - 17: K♦ 18: 2♦ 19: Q♦ 20: 3♣ 4♦ 2♣ 9 correct. Quote Link to comment Share on other sites More sharing options...
0 plainglazed Posted March 25, 2011 Report Share Posted March 25, 2011 What I mean is to make the expected value of the resulting hand as large as possible. Since there are only 7462 different values for poker hands, we can give the worst possible hand a value of 1,the best possible a value of 7462, and all the others appropriate values in between. I hope that's clear. sorry superprismatic, but am still a little uncertain as to the goal. am thinking we're looking for the discards that result in most likely improving your hand in any way? otherwise, discarding none if the odds are less than 50% that you would impove? Quote Link to comment Share on other sites More sharing options...
0 superprismatic Posted March 25, 2011 Author Report Share Posted March 25, 2011 sorry superprismatic, but am still a little uncertain as to the goal. am thinking we're looking for the discards that result in most likely improving your hand in any way? otherwise, discarding none if the odds are less than 50% that you would impove? With each possible way of discarding, you have some expected value for the hand that result when you replace these cards from the 47 cards remaining in the deck. I wish to find the discard which gives the highest expected value for the resulting hand. Perhaps this will help: How I determine the best draw There are 2.6 million different poker hands but there are only 7,462 different values for those hands. I wrote a program that computes the value of a hand -- using the values 1 to 7,462. That isn't very hard to do. I could have just made a big (2.6 million-long) lookup table, but I wanted to be able to use it on machines with small memories. So, I optimized the thing to do on the order of a million hands a second on one core of a 6-core AMD processor. I tested it a lot, but I could have some small bugs. For this problem, I exhaused on all possible ways to discard (32) and repopulate from 47 cards (about 1.7 million) for each of the hands. I computed the average value of a hand resulting from each of the discard repopulation possibilities. The discard which gives the best average value wins. Quote Link to comment Share on other sites More sharing options...
0 Guest Posted March 25, 2011 Report Share Posted March 25, 2011 1: 10♦ A♠ 10♥ 7♥ 8♣ - discard 7♥ 8♣ 2: K♠ 8♣ 9♣ 10♠ J♠ - K♠ 3: 9♣ 8♦ 8♥ 4♠ J♣ - 9♣ 4♠ J♣ 4: 6♥ K♦ A♦ K♥ 4♦ - 6♥ 4♦ 5: Q♠ 8♣ A♥ 6♦ 7♠ - 8♣ 6♦ 7♠ 6: 3♣ K♠ 5♦ 7♦ 3♥ - 3♣ 5♦ 7♦ 3♥ [my thinking is that it's much more likely to get a high pair by discarding 4 than to get 2 pair by keeping the 3s] 7: K♠ 7♥ 2♠ 5♠ J♣ - 7♥ 2♠ 5♠ J♣ 8: J♦ 10♣ 10♥ 8♣ 9♠ - 10♥ [not sure if this is smart--expected value might be higher for keeping 10s] 9: 3♦ 6♠ 5♠ 4♠ 5♦ - 5♦ 10: 5♠ 7♠ 5♦ A♠ Q♥ - 5♠ 7♠ 5♦ Q♥ 11: 4♠ 5♠ 6♠ 7♠ 7♣ - 7♣ [9/52 chance of getting another spade; 8/52 chance of getting 3 or 8] 12: 2♠ 3♣ 4♣ 5♣ 6♣ - 2♠ [risky, but 2/52 chance of straight flush, 9/52 chance of flush makes it worth it, I think] 13: 3♠ 2♣ 3♣ 4♣ 5♣ - 3♠ 14: 2♠ 2♣ 3♣ 4♣ 5♣ - 2♠ 15: J♠ K♠ 2♥ 8♦ Q♠ - J♠ 2♥ 8♦ Q♠ 16: 2♠ 3♠ 4♠ 5♠ 6♣ - 6♣ 17: 3♦ 4♦ 6♦ K♦ 5♠ - 5♠ 18: 2♦ 8♥ 5♥ 9♣ 6♦ - All? 19: 8♠ Q♦ A♠ K♠ 6♠ - A♠ K♠ 20: 3♣ 4♦ J♥ 2♣ 10♥ - J♥ Quote Link to comment Share on other sites More sharing options...
0 bushindo Posted March 25, 2011 Report Share Posted March 25, 2011 (edited) This seems fun. Cards to discard 1: 7♥ 8♣ 2: 8♣ 9♣ 10♠ J♠ 3: 9♣ 4♠ 4: 6♥ 4♦ 5: Q♠ 8♣ 6♦ 7♠ 6: 5♦ 7♦ 7: 7♥ 2♠ 5♠ J♣ 8: 8♣ 9♠ 9: 3♦ 6♠ 4♠ 10: 7♠ Q♥ 11: 4♠ 5♠ 6♠ 12: NONE 13: 2♣ 4♣ 5♣ 14: 3♣ 4♣ 5♣ 15: J♠ 2♥ 8♦ Q♠ 16: NONE 17: 3♦ 4♦ 6♦ 5♠ 18: 2♦ 8♥ 5♥ 9♣ 6♦ 19: 8♠ Q♦ K♠ 6♠ 20: 3♣ 4♦ J♥ 2♣ 10♥ Edited March 25, 2011 by bushindo Quote Link to comment Share on other sites More sharing options...
0 Guest Posted March 25, 2011 Report Share Posted March 25, 2011 1: 7♥ 8♣ 2: K♠ 3: 9♣ 4♠ J♣ 4: 6♥ 4♦ 5: Q♠ A♥ 6: 5♦ 7♦ 7: 7♥ J♣ 8: 10♥ 9: 5♦ 10: 7♠ Q♥ 11: 7♣ 12: 2♠ 13: 3♠ 14: 2♠ 15: 2♥ 8♦ 16: 6♣ 17: 5♠ 18: 2♦ 19: Q♦ 20: J♥ 10♥ Quote Link to comment Share on other sites More sharing options...
0 superprismatic Posted March 25, 2011 Author Report Share Posted March 25, 2011 1: 10♦ A♠ 10♥ 7♥ 8♣ - discard 7♥ 8♣ 2: K♠ 8♣ 9♣ 10♠ J♠ - K♠ 3: 9♣ 8♦ 8♥ 4♠ J♣ - 9♣ 4♠ J♣ 4: 6♥ K♦ A♦ K♥ 4♦ - 6♥ 4♦ 5: Q♠ 8♣ A♥ 6♦ 7♠ - 8♣ 6♦ 7♠ 6: 3♣ K♠ 5♦ 7♦ 3♥ - 3♣ 5♦ 7♦ 3♥ [my thinking is that it's much more likely to get a high pair by discarding 4 than to get 2 pair by keeping the 3s] 7: K♠ 7♥ 2♠ 5♠ J♣ - 7♥ 2♠ 5♠ J♣ 8: J♦ 10♣ 10♥ 8♣ 9♠ - 10♥ [not sure if this is smart--expected value might be higher for keeping 10s] 9: 3♦ 6♠ 5♠ 4♠ 5♦ - 5♦ 10: 5♠ 7♠ 5♦ A♠ Q♥ - 5♠ 7♠ 5♦ Q♥ 11: 4♠ 5♠ 6♠ 7♠ 7♣ - 7♣ [9/52 chance of getting another spade; 8/52 chance of getting 3 or 8] 12: 2♠ 3♣ 4♣ 5♣ 6♣ - 2♠ [risky, but 2/52 chance of straight flush, 9/52 chance of flush makes it worth it, I think] 13: 3♠ 2♣ 3♣ 4♣ 5♣ - 3♠ 14: 2♠ 2♣ 3♣ 4♣ 5♣ - 2♠ 15: J♠ K♠ 2♥ 8♦ Q♠ - J♠ 2♥ 8♦ Q♠ 16: 2♠ 3♠ 4♠ 5♠ 6♣ - 6♣ 17: 3♦ 4♦ 6♦ K♦ 5♠ - 5♠ 18: 2♦ 8♥ 5♥ 9♣ 6♦ - All? 19: 8♠ Q♦ A♠ K♠ 6♠ - A♠ K♠ 20: 3♣ 4♦ J♥ 2♣ 10♥ - J♥ 6 correct. Quote Link to comment Share on other sites More sharing options...
0 superprismatic Posted March 25, 2011 Author Report Share Posted March 25, 2011 This seems fun. Cards to discard 1: 7♥ 8♣ 2: 8♣ 9♣ 10♠ J♠ 3: 9♣ 4♠ 4: 6♥ 4♦ 5: Q♠ 8♣ 6♦ 7♠ 6: 5♦ 7♦ 7: 7♥ 2♠ 5♠ J♣ 8: 8♣ 9♠ 9: 3♦ 6♠ 4♠ 10: 7♠ Q♥ 11: 4♠ 5♠ 6♠ 12: NONE 13: 2♣ 4♣ 5♣ 14: 3♣ 4♣ 5♣ 15: J♠ 2♥ 8♦ Q♠ 16: NONE 17: 3♦ 4♦ 6♦ 5♠ 18: 2♦ 8♥ 5♥ 9♣ 6♦ 19: 8♠ Q♦ K♠ 6♠ 20: 3♣ 4♦ J♥ 2♣ 10♥ 10 correct. Quote Link to comment Share on other sites More sharing options...
0 superprismatic Posted March 25, 2011 Author Report Share Posted March 25, 2011 1: 7♥ 8♣ 2: K♠ 3: 9♣ 4♠ J♣ 4: 6♥ 4♦ 5: Q♠ A♥ 6: 5♦ 7♦ 7: 7♥ J♣ 8: 10♥ 9: 5♦ 10: 7♠ Q♥ 11: 7♣ 12: 2♠ 13: 3♠ 14: 2♠ 15: 2♥ 8♦ 16: 6♣ 17: 5♠ 18: 2♦ 19: Q♦ 20: J♥ 10♥ 7 correct. Quote Link to comment Share on other sites More sharing options...
0 bushindo Posted March 25, 2011 Report Share Posted March 25, 2011 (edited) 1 more time Cards to discard 1: 7♥ 8♣ 2: K♠ 3: 9♣ 4♠ J♣ 4: 6♥ 4♦ 5: Q♠ 8♣ 6♦ 7♠ 6: 5♦ 7♦ 7: 7♥ 2♠ 5♠ J♣ 8: J♦ 8♣ 9♠ 9: 3♦ 6♠ 4♠ 10: 7♠ Q♥ 11: 7♣ 12: NONE 13: 3♠ 14: 2♠ 15: J♠ 2♥ 8♦ Q♠ 16: NONE 17: 5♠ 18: 2♦ 8♥ 5♥ 9♣ 6♦ 19: 8♠ Q♦ K♠ 6♠ 20: 3♣ 4♦ J♥ 2♣ 10♥ Edited March 25, 2011 by bushindo Quote Link to comment Share on other sites More sharing options...
0 superprismatic Posted March 25, 2011 Author Report Share Posted March 25, 2011 1 more time Cards to discard 1: 7♥ 8♣ 2: K♠ 3: 9♣ 4♠ J♣ 4: 6♥ 4♦ 5: Q♠ 8♣ 6♦ 7♠ 6: 5♦ 7♦ 7: 7♥ 2♠ 5♠ J♣ 8: J♦ 8♣ 9♠ 9: 3♦ 6♠ 4♠ 10: 7♠ Q♥ 11: 7♣ 12: NONE 13: 3♠ 14: 2♠ 15: J♠ 2♥ 8♦ Q♠ 16: NONE 17: 5♠ 18: 2♦ 8♥ 5♥ 9♣ 6♦ 19: 8♠ Q♦ K♠ 6♠ 20: 3♣ 4♦ J♥ 2♣ 10♥ 10 correct, having 7 overlaps with your earlier score of 10. Quote Link to comment Share on other sites More sharing options...
Question
superprismatic
Listed below are 20 poker hands.
For each of the hands below, assume
it was dealt to you from a full shuffled
poker deck of 52 cards. You may stay
with the hand you are given or discard
any number of its cards. Any discarded
cards will be replaced by a random draw
from the remaining 47 cards. Your goal
is to improve the value of your hand as
much as possible. List which cards, if
any, you should discard from each of the
starting hands below:
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