[wolfgang]

Conrad has no job ,He spend the whole day watching cars passing the street in front of his apartment.His hobby is to write down there Numbers !and try to find something common between them.These are his conclusions :-

1- the cars pass through at (1min.)interval,one car at a time.

2- each car has a (five digits)number.

3- each second car(i.e the car No. 2,4,6...etc.) has a middle number(3rd.No.)ranging between(4 and 6),i.e.the car No. 2 has No.4 in the middle,the car No. 4 has No. 5 in the middle,the car No. 6 has No.6 in the middle...and again 4,5,6. for the cars 8,10,12

and so on.

4-each 3rd.car has a(4th number) either(0,1 or 2) as described before.

5-each 4th car has a(1st number) either(2,3 or 4),as above.

6- each 5th car has a (last number)either(6,7 or 8).

7-each 6th car has a(2nd number)either(8,9 or 0).

He wrote a car number(71684)at 8.00 am.,then he went to have his breakfast.

exactly ,at 9.00 O`clock am. (after one hour),a car chased by the police went along this sreet.Conrad was able to estimate its number !

Can you?

[k-man]

48618?

[Guest]

70694 assuming 1st-5th is read right to left as in the car # Conrad wrote down at 8 am

[Akriti]

I have drawn a whole table and I have understood that there is only one car whose no. can be framed out with all 5 digits. So the answer is "48618"

[wolfgang]

70694 assuming 1st-5th is read right to left as in the car # Conrad wrote down at 8 am

perfect !!

[Guest]

75654

-the car can only be an even numbered car-but not every 4th, 6th, 8th, or 10 th car.

first digit= 7 because the choices are only 1, 5,7,8, &9 and if you count the 60 th car -starting from 8 -it would be 7

2nd digit- choices- 1-7 only-and count 60th car staring from 2

3rd digit- choices 4-5-6,- and counting 6oth car starting on 4

4th digit- choices- 3,4,5,6,7,8,9- count 60th car starting from 9

5th digit- choices=1,2,3,4,5- count 60th car starting from 5

[wolfgang]

75654

-the car can only be an even numbered car-but not every 4th, 6th, 8th, or 10 th car.

first digit= 7 because the choices are only 1, 5,7,8, &9 and if you count the 60 th car -starting from 8 -it would be 7

2nd digit- choices- 1-7 only-and count 60th car staring from 2

3rd digit- choices 4-5-6,- and counting 6oth car starting on 4

4th digit- choices- 3,4,5,6,7,8,9- count 60th car starting from 9

5th digit- choices=1,2,3,4,5- count 60th car starting from 5

Thanks...see maurice approach...he was right.

[dark_magician_92]

Conrad has no job ,He spend the whole day watching cars passing the street in front of his apartment.His hobby is to write down there Numbers !and try to find something common between them.These are his conclusions :-

1- the cars pass through at (1min.)interval,one car at a time.

2- each car has a (five digits)number.

3- each second car(i.e the car No. 2,4,6...etc.) has a middle number(3rd.No.)ranging between(4 and 6),i.e.the car No. 2 has No.4 in the middle,the car No. 4 has No. 5 in the middle,the car No. 6 has No.6 in the middle...and again 4,5,6. for the cars 8,10,12

and so on.

4-each 3rd.car has a(4th number) either(0,1 or 2) as described before.

5-each 4th car has a(1st number) either(2,3 or 4),as above.

6- each 5th car has a (last number)either(6,7 or 8).

7-each 6th car has a(2nd number)either(8,9 or 0).

He wrote a car number(71684)at 8.00 am.,then he went to have his breakfast.

exactly ,at 9.00 O`clock am. (after one hour),a car chased by the police went along this sreet.Conrad was able to estimate its number !

Can you?

80694 or 49608

[wolfgang]

80694 or 49608

No...please see Maurice answer...thanks

[dark_magician_92]

the car at 8am is the 240th car, isnt it?

so car at 9am is 300th hence last no. shud be 8 only (it is the 60th 5th car). so answer shud be 70694

No...please see Maurice answer...thanks

[Guest]

70694 assuming 1st-5th is read right to left as in the car # Conrad wrote down at 8 am

x mod y = remainder when x/y. There are always 3 numbers in the pattern so the options are 0,1,2. When 0 use the original number. When 1 use the next number after the original number in the cycle. When 2 use the previous number to the original in the cycle.

1- the cars pass through at (1min.)interval,one car at a time

The 8:00 am car was the 0th car. The 8:01 car was the 1st car...the 9:00 car was the 60th car.

2- each car has a (five digits)number (8:00 am was 71684)

3- each second car(i.e the car No. 2,4,6...etc.) has a middle number(3rd.No.)ranging between(4 and 6),i.e.the car No. 2 has No.4 in the middle,the car No. 4 has No. 5 in the middle,the car No. 6 has No.6 in the middle...and again 4,5,6. for the cars 8,10,12

and so on.

60/2 (every 2nd car) = 30 cars in pattern ...30 mod 3 = 0 so use the original number 6.

4-each 3rd.car has a(4th number) either(0,1 or 2) as described before

60/3 (every 3rd car) = 20 cars in the pattern...20 mod 3 = 2 so use the previous number to the original number in the cycle. The 4th number appears to be 8 but this does not fit the original plate so I assumed numbers are read right to left, meaning original "4th" number is 1. The number before 1 in the cycle is 0. So the "4th" number is 0.

5-each 4th car has a(1st number) either(2,3 or 4),as above.

60/4 (every 4th car) = 15 cars in the pattern...15 mod 3 = 0 so use the original number in the cycle. The 1st number appears to be 7 but this does not fit the original plate so I assumed numbers are read right to left, meaning original "1st" number is 4. So the "1st" number is 4.

6- each 5th car has a (last number)either(6,7 or 8).

60/5 (every 5th car) = 12 cars in the pattern...12 mod 3 = 0 so use the original number in the cycle. The last number appears to be 4 but this does not fit the original plate so I assumed numbers are read right to left, meaning original "last" number is 7. So the "last" number is 7.

7-each 6th car has a(2nd number)either(8,9 or 0).

60/6 (every 6th car) = 10 cars in the pattern...10 mod 3 = 1 so use the next number after the original number in the cycle. The 2nd number appears to be 1 but this does not fit the original plate so I assumed numbers are read right to left, meaning original "2nd" number is 8. The number after 8 in the cycle is 9. So the "2nd" number is 9.

So since we're reading right to left I need in order: last, 4th, middle, 2nd , 1st ----> 70694

Edited January 4, 2011 by maurice