[wolfgang]

I love number 14! ...hate (0) ,and feel good with(1)

I used the binary notation(0,1)to write the numbers (1 to 14),like this:

1...1000

2...0100

3...1100

4...0010

5...1010

and so on till 14...0111

Now...I gave the same code to each (AD) century ,thus the first century has the code(1000),

2nd cetury(0100),and so on till the 14th cetury(0111),for the 15th century again(1000).

And to each AD year,day and hour, I did the same.

By joining the codes of (century+year+day+hour)we will have a (16) digits code.

so whenever you see alot of(0) in a code,,means an ominous fate to the earth !!!

When will the nearest disaster happens?.

Note:there should be more than four (0) beside each other in the code.

Forgive me if my english is not good enough...

[superprismatic]

It must be the 29^th century (2801-2900) with code 1000,

the 8^th year with code 0001,

the 15^th day with code 1000,

and the 8^th hour (07) with code 0001.

So, the nearest disaster happens at 7AM on the 15^th day of 2808 with code 1000000110000001.

[Akriti]

It must be the 29^th century (2801-2900) with code 1000,the 8^th year with code 0001,the 15^th day with code 1000,and the 8^th hour (07) with code 0001.So, the nearest disaster happens at 7AM on the 15^th day of 2808 with code 1000000110000001.

Great!!

I agree with you

[wolfgang]

It must be the 29^th century (2801-2900) with code 1000,

the 8^th year with code 0001,

the 15^th day with code 1000,

and the 8^th hour (07) with code 0001.

So, the nearest disaster happens at 7AM on the 15^th day of 2808 with code 1000000110000001.

You did it!!

[Guest]

Perhaps i have not understood the question correctly, but does it not state that more than 4 consecutive zeros are required for a catastrophic event and that the NEAREST event should be predicted? 7AM on the 15th day of 2808 will indeed be unfortunate, the apocolypse perhaps!

You posted this problem on the 28th November 2010 - 10:15 PM (1110)(0101)(0111)(0101) a seemingly fortunate day.

The most proximal catastophic event shall occur in the 21st century on the 16th Dec (this being the 332nd day of the year) 2011 at 3am

The binary representation for this would be:(1110) (0101) (1000) (0010)

1110010110000010

Edited December 1, 2010 by Nathaniel O

[wolfgang]

Perhaps i have not understood the question correctly, but does it not state that more than 4 consecutive zeros are required for a catastrophic event and that the NEAREST event should be predicted? 7AM on the 15th day of 2808 will indeed be unfortunate, the apocolypse perhaps!

You posted this problem on the 28th November 2010 - 10:15 PM (1110)(0101)(0111)(0101) a seemingly fortunate day.

The most proximal catastophic event shall occur in the 21st century on the 16th Dec (this being the 332nd day of the year) 2011 at 3am

The binary representation for this would be:(1110) (0101) (1000) (0010)

1110010110000010

Wooooow...great respect !!