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A master criminal has broken into a jeweller`s strong room which has the walls lined with several thousand storage boxes protected by individual four digit combination lock codes.. Each storage box contains small bags of precious stones (diamonds etc.) so the total value of all the contents of the locked boxes in this room will be several million of ££s .

Each box is labelled with a letter and four digits and the thief has inside information and knows that the combination lock code for each individual box can be mathematically calculated using the Box Number .He also knows that the only digits used for the code will be 1 , 2 , 3 , 4 and 5.

Eg ...........Box No J 0023 has a Combination Lock Code of 1215

However , each box has its Combination Lock Code engraved on the INSIDE and fortunately several of these boxes are empty and have been left OPEN . This means that the criminal can now list each open Box Number with its own Security Code , and , using this information will attempt to work out the method of calculating any Security Code from its Box Number.

His inside information has told him that there is one particular box containing the master list of what is contained in each box in the strong room...Box J 6383 ... so this is the box to open first.

Here is the list of open BOX numbers with their security CODES engraved on the inside.

Can you work out how the codes can be calculated and explain the method used to determine the combination lock code of Box J 6383 ?

.BOX = CODE..... BOX = CODE..... BOX = CODE

J 0023 = 1215.... E 2182 = 5225.... Z 6163 = 1445

H 0124 = 4441.... Z 2271 = 1552 .... J 6242 = 3545

C 0138 = 4513.... K 2380 = 5322 .... A 6322 = 4525

Y 0209 = 5554.... A 2408 = 4124 .... K 6481 = 3513

E 0215 = 3235.... Z 2494 = 4221 .... J 6519 = 1525

H 0262 = 1234.... Z 2812 = 5332 .... K 6620 = 3341

R 0448 = 5132.... A 2994 = 4425 .... J 6709 = 5355

R 0464 = 2135.... C 3010 = 5414 .... E 6999 = 4515

W 0496 = 2125 .... Z 3229 = 3321 .... A 7238 = 3222

R 0545 = 2545 .... D 3631 = 1152 .... E 7402 = 5454

A 0704 = 5122 .... L 3865 = 2545 .... A 7535 = 3555

A 0859 = 4453.... A 4089 = 4455 .... A 7713 = 5542

R 0871 = 5545 .... Z 4108 = 2414 .... A 7962 = 4431

Y 0926 = 4254 .... E 4111 = 3222 .... U 8056 = 5543

Z 1043 = 4455 .... A 4166 = 3325 .... E 8108 = 2332

V 1044 = 3442 .... K 4431 = 3552 .... E 8121 = 2522

U 1095 = 2245 .... A 4476 = 4343 .... E 8250 = 4531

U 1096 = 1142 .... S 4705 = 4133 .... Z 8596 = 1335

V 1192 = 4521 .... A 4707 = 2455 .... E 8391 = 3232

R 1244 = 1355 .... Z 4725 = 2325 .... A 8844 = 5432

H 1381 = 4255 .... J 5264 = 4524 .... A 8930 = 4545

E 1390 = 4251 .... Z 5271 = 1225 .... A 9024 = 5153

R 1479 = 1523 .... J 5362 = 5535 .... K 9139 = 3443

K 1533 = 5244 .... E 5567 = 3123 .... K 9356 = 2424

J 1853 = 5322 .... Z 5970 = 5452 .... A 9751 = 3242

A 6053 = 3245 .... Z 9800 = 3134

Good luck !

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I wrote a program that uses B2B3B4 to come up with all of the C2C3C4 respectively ... BUT it more then likely is just coincidental that it works.

I used B2B3B4 and either converted it to a base from 2-100(I know you're thinking you can't convert to bases lower then 10 because it doesn't make sense because the box contains digits 0-9 but if we are breaking a code and the code included poor formed base writing the 19 in base 2 can still be 11 in base ten and rewritten 1001) or/and I added multiples of 111 to B2B3B4 and then converted it to one of the bases and then converted it to base 5 and add 111 then checked the last three digits of the new base to match it to C2C3C4. I of course get multiple answers for each box but I didn't use B1 or C1 or the L1 to determine which base to convert it to or which multiple of 111 to add. Of course I haven't found a pattern yet and this could just be coincidental that I was able to generate C2C3C4 from B2B3B4.

This is just a sort list because it wouldn't let me send the whole thing. EDIT: i forgot to say I added 111 to the new converted base number to have it equal the OP's base of 1-5

Ok so if we could use L1(even though I know we say it's not usable) or B1 or C1(because we're pretty sure we've found its solution) to determine which base and what to add we could come up with a formula to do the rest?....maybe

Edited by PVRoot
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sorry but 19 miswritten in base 2 could be 11 in base 10 and rewitten in base 2 as 1011 sorry for the above conversion I looked at the 9 and wrote it instead of the 11.

anyways... is the above all random or can we somehow determine which base to use and which multiple of 111 using the remaining unused clues or I'm I wasting my time?

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I`ve just been asked if this problem has been fully solved yet.

The answer is "No" ... only C1 has been solved ...and that was right at the beginning.

.

All the theories and ideas so far have not produced any answers...so C2 C3 C4 still waiting for answers

Anyone working on it still or has everyone now given up?

I have been assured that it IS solveable ...but very difficult.

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Been looking at this one on and off for a while but have not come up with anything new.

  On 7/31/2010 at 11:09 PM, redrooster said:

I`ve just been asked if this problem has been fully solved yet.

The answer is "No" ... only C1 has been solved ...and that was right at the beginning.

.

All the theories and ideas so far have not produced any answers...so C2 C3 C4 still waiting for answers

Anyone working on it still or has everyone now given up?

I have been assured that it IS solveable ...but very difficult.

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I am solely focusing on C2 right now and slowly making progress. I have split up the boxes into odds and evens using Box to represent the whole box number not individual digits. If Box is even then I am using INT(Box/41) mod 5. For odd Box numbers I use INT(Box/13) mod 5. INT() is the integer function. I will post more updates soon.

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if been working on this one since yesterday

as C1 has been solved I want to highlight:

E3695=1545

R0545=2545

L3865=2545

J6242=3545

A8930=4545

R0871=5545

the answer for the others should come from here

PS this one sucks

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  On 8/27/2010 at 6:07 PM, Molly Mae said:

I ran this through our Codebreaker in the back yesterday. She's still processing it, but I've never seen her take longer than a few hours to find connections. Especially with so much data...

I think someone's pulling our leg.

What are you saying exactly? Is this a device? Computer? And umm... why would you spoil our fun? :P

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  On 9/3/2010 at 7:50 AM, JTZero said:

What are you saying exactly? Is this a device? Computer? And umm... why would you spoil our fun? :P

  On 9/3/2010 at 1:47 PM, Molly Mae said:

If you take pleasure from trying to find a solution that isn't there, I'm sorry.

I won't give you the final results.

So you imply that you have final results, but again, "what/who is your "codebreaker in the back"? Any machine/computer has fixed limitations on the possiblities it will consider based upon criteria and algorithms that were programmed in. It would not be impossible to devise a code with such obscure formulas and advanced interrelationships between the values that a "codebreaker" couldn't solve it without first being given at least a portion of the algorithm. This would especially be true if the code writer were the developer of the "codebreaker" and knew it's limitations.

The flip side of that is that we've noticed many patterns that seem to develop but either contradict themselves or never fully develop, so is there any possibility that the data we are considering may have gotten corrupted some how?

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Near the beginning of this many claimed that the letters meant nothing in breaking the codes. This assumption was only based off of two boxes with matching numbers and codes. It's very well possible that these letters do play some part in the codebreaking and I haven't ruled them out yet.

  On 9/3/2010 at 1:47 PM, Molly Mae said:

If you take pleasure from trying to find a solution that isn't there, I'm sorry.

I won't give you the final results.

I am assuming your "final results" isn't a solution to this problem. Does your machine compute letters as variables?

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