Prof. Templeton
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Everything posted by Prof. Templeton
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WWW.BRAINDEN.COM = WOW. CAN BREW MIND.
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As I have seen this riddle before, I'll refrain from answering. But I wanted to let you know I love these, they make you use your head.
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There is every chance that my maths is wrong here somewhere so please feel freee to correct, but it feels as though its about right.... You guys have proven that the bug will indeed reach the scooter regardless of an initial head-start. If the scooter and bug both start at the wall as stated in the OP, than the time it takes is 0. If we give the scooter a head-start of 1 meter, than it will take I apologize for the complicated math, but I thought the question itself would lead to some interesting discussion. I'm glad to see the correct answer posted so quickly.
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Hmmm...I might be able to plot a shorter course on the inside lane, however,maybe there's less centrifugal force in the outside lane. I don't think it more beneficial to chose a track. The inside lane might be the shortest plotable route by taking tangetal lines along the inner track lane boundary, but the angles between lines might slow you down, and centrifugal forces may not be a large factor. Takes pencil out from behind his ear. Ummm, I'll get back to ya.
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Yeah, the scooters a little beat up, but it gets great gas milage. I told Mumbles140 I should have put a headstart in the OP. I don't want people to assume the bug can hang on (especially at the break-neck speed of 1 meter / second).
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I think the OP would be better if I had worded it with a headstart as you pointed out, but I also think the answer may be a lot larger than what you said above.
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Would it matter if the scooter started 1 meter from the wall at time=0. Than the bug would be at the wall and the good Prof. would be 1 meter away.
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After 1 second the Prof. is 1 meter from the wall after 2 seconds he's 2 meters, and so on...while the bug has traveled 1 cm after 1 second and 2 cm after 2 seconds, and so on... So, initially they were at the same spot, but when the timer starts they travels in the same direction. Will they be at the same spot again, and how long from now? Does this clarify at all?
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I edited it to 1 meter. Sorry for the confusion, but that would be one heck of a scooter.
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I bet you could get in more laps that way without the track officials noticing.
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An infinitely stretchable rubber-band has one end attached to the wall and the other end it attached to a scooter being driven Prof. Templeton. The good Prof. drives away from the wall at a constant speed of 1 meter per second. Starting from the wall and walking out onto the rubber-band is a bug. The bug travels at a constant speed of 1 cm per second. Both start moving at the same time in the same direction. The Prof. moves away from the wall perpendicularly and the bug moves along the stretching rubber-band away from the wall toward the Prof. Let’s assume the rubber-band is perpendicular to the wall with no angle of incidence (all along one plane) and the bug is a point on a line initially at distance 0 from the wall. Will the bug ever reach Prof. Templeton, and if so can you tell how long it will take?
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You just bought a new sportscar, and you want to bring it to the racetrack to see how it will perform. The track is very busy and will only allow 2 laps. Since it's your first time at the track you take it easy on the first lap and average 40 Miles per hour. How fast would you have to go on the second lap to end the day with an average of 80 miles per hour?
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20 is not the answer
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That would certainly require a trip to an "analyst", except they can give me the willies. Quite frightening.
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Here's a list of my biggest phobias Apeirophobia Hexakosioihexekontahexaphobia Hippopotomonstrosesquippedaliophobia koumpounophobia Ophthalmophobia Pogonophobia Walloonphobia Zemmiphobia Phobophobia That last one made it hard to make this list.
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Whoops... I thought the diameter was two feet I guess thats why you gotta read these things.
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You are on a gameshow called "Mash-Up". You have to pick one out of three doors. After you pick a door the Host will open up a "losing" door that has prisioners trying on hats while crossing a river. After the "losing" door is opened you can stay with your initial choice or switch doors. Behind each "winning" door are two poles, a red and a black. Half of each pole is in the ground, another third is in the water( not the same water that the prisioners trying on hats are crossing ) and 8 feet are out of the water. The color of the poles are not determined beforehand but are generated when the winning door is opened. The poles have a 50/50 chance of being red or black. Level 1. If the one pole is red, what are the odds of the other one being a 48' red pole if you switched doors. Level 2. What are the odds of it being a 12' red pole if there are an infinite number of doors that are opened one after another in 1 minute; each one opening at half of the time remaining and the host says "VLR TFK FC QEB PQXQBJBKQ QEXQ FP RKABOIFKBA FP CXIPB". Since this isn't a real puzzle I'll post in Other.
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I watch You are what you eat and I tried to watch Torchwood once or twice but it didn't really entice me.
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I believe YouTube has solutions posted for some, and also WikiAnswers and as PG said Yahoo Answers, but it may be easier just to Google "soukoban level X solution".
