EventHorizon
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That's right, though it can be simplified to a simple power of a fraction.
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What is the sum of this series equal to in the limit? 2/100, 4/10000, 8/10^6, 16/10^8, 32/10^10, ... Yeah....its a simple geometric series....but it is kinda interesting when you multiply each term by 7 and see what the sum is equal to.
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Looks like a hint is needed.
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What are the next 3 numbers in the sequence? 8, 6, 96, 047, 10803, 424, 878, 3, 9171, 98838, 7240, ?, ?, ? The sequence will go on indefinitely, and I tried to design it to be difficult. Notice "047" kept the leading 0....it is significant/needed. Good Luck
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square roots are valid...right?
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"and the others will vote on it" vs "If half or more of the total pirates alive" So does the pirate giving the proposal vote? Assuming he does.... (e.g., the first pirate only needs 2 other votes to have the first proposal taken). Assuming he does not have a vote.....(the first pirate needs 3 votes to live...and he doesn't get a vote) Okay...how about if a pirate doesn't get a gold piece he would rather be dead (and the pirate giving the proposal gets a vote, and pirates kill unless given an incentive not to) What other combination of assumptions might give interesting results? Am I anywhere close Noct?
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How about this for adding more in..... Jim, where Tim had "had had had had had had had had had had had had had had had had had had had had had had had had had had had had had had had had had had had had had had had had had had had had had had had had had had had had had had had had had had had", had "had." "Had" had a better effect on the teacher. essentially....Tim just went hog wild writing had. Tim is probably a robot and got stuck in a loop until his batteries ran out.
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That is interesting...it makes me think that perhaps there is a very simple lateral thinking way of solving this puzzle. I can't quite seem to figure out what it would be yet. I'll think about it more tomorrow...I should really work on a paper...but have been avoiding it a little too much. It seems I would much rather solve puzzles and watch my team lose (grr!) than work on my paper.
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What I meant was that each valid square orientation pair does not have equal probability.....just thought I would fix my horrible wording....
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just a couple clarification questions... 1. whenever the end would fall outside the board, you can't choose that orientation....right? So one square away diagonally from a corner square (a gray square in all cases) only has 2 valid orientations to choose from just like the corner, etc. 2. is the ruler starting from the center of the chosen square or covering it completely? In other words, once the ruler is down, would 3 or 4 squares have the ruler covering part or all of them? I would assume only 3, but wanted to make sure.
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you can get more bananas to the bazaar than that, but that was a good effort. Question 3 actually asks how far you could travel and not how many bananas you can get to the bazaar.
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here's a method to get 200 bananas to a bazaar 1000 meters away when starting with 1600 bananas.
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looks like talha posted before I clicked reply. put answers in spoiler blocks so other people can look through the posts for any clarification and still be able to figure it out on their own.
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1000 bananas may be a bit much to carry repeatedly. It may also have been in miles when I first heard it. So try to answer these when forced to ride the camel.
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Oops...took a little too long to edit. Let the following be questions 6-9. Question 6: How many bananas would you need to start with to be able to make a return trip from the bazaar in Q5 (with the requirement that while at the bazaar you cannot have any bananas out in the desert)? Question 7: Same a Q6, but you can leave bananas out in the desert. Question 8: If you have a capacity of C and B*C+E bananas (B is a positive integer, 0 <= E <C), how far (one way) can you ride the camel? Question 9: Same as Q8 except you need to return (eg, two way trip)?
