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araver

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  2. Star area

    in New Logic/Math Puzzles

    Posted · Edited by araver

    @LogophobicWhat I meant was:

    Spoiler

    That you can move the up-side down triangle parallel to the base at 6 ft any way left to right and still create a star. The "star" doesn't have to be symmetrical from the OP as far as I read it.

    So IF the area of the star does change when you move it, THEN the OP is obviously ambiguous, one could get a lot of stars with different areas by moving it around a bit (but stopping when the edges of the upside down triangle touch the edges of the base of the upright triangle).

    Hence, it makes sense that the reverse hypothesis is true: the area of the "star" does not change when you move the upside down triangle left-right. I'm not talking about the area of the overlap (be it a hexagon or a parallelogram), the area of the "star" composed of the super-imposed image. It felt easier to compute it in a corner scenario such as this:

    star.png

    I could have messed up the calculations, but if both mine and yours check out, the area is anywhere between those two numbers (and my hypothesis about the orange area being constant is false).

    Edit: my calculations are 6*8 (middle parallelogram with base 8 and height 6ft) + 2*area of the little triangle (up and down in left figure). For the little triangle i get (8-4sqrt(3))^2*sqrt(3)/4 which yields an orange area of 48+56sqrt(3)-96. 

     

  9. Re-ROLLO

    in Games

    Posted

    WRATH

    BACON - 0
    JUICE - 0
    FRUIT - 1
    FOXES - 0
    FRIES - 1 logo +5
    CRAMP - 2
    CHUMP - 0 maurice +5
    BRASH - 3
    CLASP - 1 maurice +5
    GRAPH - 3
    WRATH - 5 maurice +15

    I must be getting predictable :P

    logo +5
    maurice +25
    araver +11

    Maurice  -  340
    Logophobic - 300
    Araver - 214
    Nana -  170
    Marksmanjay - 88
    Plainglazed - 45
    Phaze - 43
    Framm - 34

  21. Re-ROLLO

    in Games

    Posted · Edited by araver
    Hate autocorrect

    BIRCH - if 1 then --N-- because BU--T so not ---C- and BUNCH=3 so N.

    If 2 then ---C- since bunch=3, no I and no H b/c of BU--T and no R b/c BURST=3

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