wolfgang
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Posts posted by wolfgang
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can I ask a silly question?
Do we get the same answer, if we change the three rooms and apples with three positive numbers written on three papers?
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Let him begin with (
larger) for example.
1- If he was right, so for the next hand he should change to ( smaller).
2- If he was wrong, he should stay by ( larger ) for the next hand.
and so on -
1- He should accept the 1st room, because ,in this case he has 2 possibilities.(accept,accept,reject)or(accept,reject,accept).
2-If the apples in the 2nd room >than in the 1st room, he should accept it.
3- If they were less, he should reject it and accept the 3rd room.
Leading to 50% chance of wining. -
Hi dear friends...
1- Draw an equilateral triangle ABC.
2- Make two points on each side to get (ABC+6point= 9 points), with 4 points on each side.
3- Give the numbers( 1 to 9 ) to these points, so that the sum of 4 numbers on each side is the same.
i.e.
A+point1+point2+B= B+point3+point4+C= C+point5+point6+A
have fun
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1- cut sheet longitudinally , to form 2 pieces(2"x8").
2- bend these 2 pieces in the middle making a right angle.
3- welding them together to get an open box, with (4"x4"x2").
So the precast volume will be :32 cubic inches.-
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I do not know who is right-handed, etc. To my question everyone raises the right hand when they say YES. For example, a question for the left-hander: "Will you raise your right hand on the question: "2>1?"?". In normal mode, for "2>1?" he will raise his left hand, in the construction of my question he, as well as the right-hander, raises his right.
Let's see how it works:
1Q to #1: "Will you raise your right hand on the question: "are you A?"?"
Right hand to 1Q - the person is A
2Q tu #2: "Will you raise your right hand on the question: "are you B?"?"
Right hand - the person is B and #3 is C
Left hand - the person is C and #3 is B
Left hand to 1Q - the person is B or C
2Q tu #1: "Will you raise your right hand on the question: "are you B?"?"
Right hand to 2Q - the person is B
3Q tu #2: "Will you raise your right hand on the question: "are you A?"?"
Right hand - the person is A and #3 is C
Left hand - the person is C and #3 is A
Left hand to 2Q- the person is C
3Q tu #2: "Will you raise your right hand on the question: "are you A?"?"
Right hand - the person is A and #3 is B
Left hand - the person is B and #3 is A
What if the 1st person is left handed and he is B?
for the 1st question, he can not raise his right hand because he is not A, neither to raise his left hand which means (yes),and that is not true.
There is no contradiction here. If first person is left handed and he is B, he has to answer the question 'will I raise my right hand for the question "are you A?"?'. Answer is 'Yes, right hand will be raised if the question was "Are you A"'.. Since B is left handed, he will finally raise his left hand to signify "Yes".
I think my approach is essentially the same.
nice trial... but take it in an easier way..
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Wolfgang, have you seen my attempt at this? Is that correct?
I read it.... but it is not correct... because in this case ,for the 3rd question, the 1st person may be A,,, or may not...hmmm...then what?
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I do not know who is right-handed, etc. To my question everyone raises the right hand when they say YES. For example, a question for the left-hander: "Will you raise your right hand on the question: "2>1?"?". In normal mode, for "2>1?" he will raise his left hand, in the construction of my question he, as well as the right-hander, raises his right.
Let's see how it works:
1Q to #1: "Will you raise your right hand on the question: "are you A?"?"
Right hand to 1Q - the person is A
2Q tu #2: "Will you raise your right hand on the question: "are you B?"?"
Right hand - the person is B and #3 is C
Left hand - the person is C and #3 is B
Left hand to 1Q - the person is B or C
2Q tu #1: "Will you raise your right hand on the question: "are you B?"?"
Right hand to 2Q - the person is B
3Q tu #2: "Will you raise your right hand on the question: "are you A?"?"
Right hand - the person is A and #3 is C
Left hand - the person is C and #3 is A
Left hand to 2Q- the person is C
3Q tu #2: "Will you raise your right hand on the question: "are you A?"?"
Right hand - the person is A and #3 is B
Left hand - the person is B and #3 is A
What if the 1st person is left handed and he is B?
for the 1st question, he can not raise his right hand because he is not A, neither to raise his left hand which means (yes),and that is not true.
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Three persons( A,B,and C) are not allowed to speak,but to raise a hand refering to ( Yes or No ), you don`t know which hand means Yes,and which means No.
How can you know the persons which is which by asking only three( yes or no) questions.
You may ask one ,two or all of them...as you like.
any question should be asked to a single person.
The solution I propose is based on a certain question configuration:
"Will you raise your right hand on the question: (yes/no question)?"
A positive response in this case - the right hand raising , the negative - left and no matter to whom you addressed the question.
All the rest is not difficult.
now you know one of them,as right handed... what about the two others? and how to confirm their identity?
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This is a challenging puzzle.
If I understand correctly, - I ask someone a question then write "1" on his forehead.
I might ask someone else a question then write "2" on his forehead.
I then write "3" on the last person's forehead.
- If A raises his left hand it might mean No.
If B raises his left hand it might mean Yes.
Similarly for person C.
- After I ask my third question, I will state, for example,
Number 1 is B; Number 2 is C; and Number 3 is A.
Is that the idea?
yes,,,,thats the idea
- I ask someone a question then write "1" on his forehead.
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I guess I need another clarification:
Is the left/right hand meaning of yes/no in some order the SAME for all the robots?
It seems that it must be, but I have to ask.
No,,,,it is not the same
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7 Apples
7/2= 3.5
3.5+0.5=4 apples to the1st one
7-4=3 Rest
3/2= 1.5
1.5+0.5=2 apples to the 2nd
3-2= 1 Rest
1/2=0.5
0.5+0.5=1 apple to the 3rd one
1-1= 0 Rest -
I want their identity. and the letters are instead of names.
so I want to know who is A, who is B, and who is C
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Three persons( A,B,and C) are not allowed to speak,but to raise a hand refering to ( Yes or No ), you don`t know which hand means Yes,and which means No.
How can you know the persons which is which by asking only three( yes or no) questions.
You may ask one ,two or all of them...as you like.
any question should be asked to a single person.
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I didn`t play Kenken before, so may I ask about it...
1- if it is like sudoku, does it mean that each row or column should have the numbers from 1 to 8?
2- in 1st row, there is a single box having number 5, and in 5th row a single box having number 3...shall we put them as such?
3- in case of 3 boxes, is it possible to subtract three numbers?..e.g. 8-5-1
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7.5 Km
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By changing the cards to letters we will get:
f E N J x......with 3 upper case letters
H U p t i.......with 2 upper case letters
G y A W m.....with 3 upper case letters
R p d s G.....with 2 upper case letters
S F f a ( ? )with only 2 upper case letters,
which means the missing letter should be an upper case letter, which is either hearts or diamonds.
If we look at the cards again, we will notice that:-
in 1st row we find 2 diamonds and 1hearts.
2nd row, 1 diamonds and 1 hearts.
3rd row 2 diamonds and 1 hearts.
4th row 1 diamonds and 1 hearts.
so the 5th row should have 2 diamonds...which means the missing card is diamonds.
And because it is un upper case so it is 3 of diamonds( I choose 3 because it is the only missing number among the cards)
and the missing letter is B -
963258147 / 8 = 120407268.375
but these are 9 digits and not 8 , so you should devide the number by 9.
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9632581470
the 5th digit must be 5
Very close, wolfgang, but check out the first eight digits.
I did...and I didn`t find any mistake...
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we make:
98765432 as first number
and 1 as second number
and we will get the largest product -
9632581470
the 5th digit must be 5 -
I think that " amabat hulut a sese sokol " means ( the basic sound of pure water ).
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a start number should be 210 which is factor-rich( 1 to 7)
while the goal number should be a prime number which has the biggest difference between it and the two prime numbers before and after it , and this number is 127.
because,
131-127=4 steps
127-113=14 steps
so to win he should choose 210 as a start number, and 127 as a goal number. -
after one hour there will be 38.90722kg salt in 3300 L water.
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