wolfgang
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Posts posted by wolfgang
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16, 4, 20, then, following the pattern on the roulette wheel.
Very good! YES..thats it
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89 steps
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I watched Roulette for the first time...
As I came, Number 18 was the winner, then I observed the next 6 coming numbers, and were as follows:
13, 28, 30, 3, 10, 32
so ...amasingly, they were not coming randomely!
They have a specific pattern....do you get it?
If yes....Tell me the next three numbers successively
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The wise will not lose.
because:
1-F,F,F or T,T,T.......The good will lose
2-F,T,F or T,T,F.......The Lucky will lose
and there is no other combinations-
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Thank you all...Happy new year to you all....I love you
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TBNZH
Assigning each letter its numerical value A=1, B=2, ... Z=26 we get the following square:
24 11 18 5 12 7 19 6 13 25 ? ? ? ? ? 3 15 22 9 21 16 23 10 17 4
Every row adds up to 70. Numbers 20,2,14,26 and 8 complete the magic square making every row, column and diagonal add up to 70. These numbers translate into letters TBNZH.
Yes...thats right....it is the magic sguare
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Dear friends....I`ll explain it again like this:
A..B..C..D..E..F..G..H...I...J..K..L..M..N..O..P..Q..R..S..T...U...V...W...X...Y...Z
1..--..--...--..2..3..--...4...5..--..6..7..8...9...--...--...--..--.--.10..--..11..12..13..14..15
so I gave to each letter having only straight lines(no curves) a number.
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Merry X-mas and happy new year to all of you dear friends...
May be some of you find it easy....but let us give it a try....find the missing combination:
XKREL
GSFMY
.?????.
COVIU
PWJQD
Have a nice time
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Each of them is going to have a different color,so all the three have to write only one color,let us say red.
that means,at least one of them wiil be correct. -
I wrote the letters like this
A,B,C,D,F,G,H.....and so on
now... I numbered the letters having straight lines only (with no curves),beginning from
A=1
F=2
H=3
and so on.....
thats it!
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very good!..thats right!!10
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Hi...
If
.........f= 3
........ h= 4
........n= 9
........y= 14
.......
Find T?
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Wooooow!!...perfect...thanks RainmanSince we have 123456789->594168327 for two steps, we can get to 5th step by applying the same mapping again. 594168327->671582493. Now we have 671582493->369741258 for one step and we can complete the list using this mapping.
1st step: 123456789
2nd step: 918273645
3rd step: 594168327
4th step: 752934816
5th step: 671582493
6th step: 369741258
7th step: 835629174
8th step: 487315962
9th step: 246897531
10th step: 123456789
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I put the numbers 1,2,3,4,5,6,7,8,9
in a sequence of Ten steps, which begins with 123456789 (as 1st step) and ends with 123456789( as 10th step)
If the 3rd step of this sequence is: 594168327
and the 6th step in this sequence is: 369741258
the 8th step is: 487315962
Find the missing steps
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I tried this:
(12-8)-(10-8)=2
(4-4)-(6-4) =-2
(9-6)-(7-6) =2
(11-6)-(13-6)=-2
but this role does not work with 5%15=2
otherwise, the missing number should be =0
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Peter and John challenged each other to a Russian roulette.Each one of them got exactely the same" Six-shooter revolver",with only one bullet in the uper most firing chamber.Peter was right-handed,were as John was left-handed.Each one spins the cylinder exactely(17 turns).They directed the muzzle against the head of each other and began to shot,both together!
Which one will survive? why?
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Yes....thats it....It's a ternary numeral system with the least significant trit on the left, where each trit can have a value of -1, 0 or 1, represented as -, 0 and + respectively.
0 = 0000 = 0*1 + 0*3 + 0*9 + 0*27
1 = +000 = 1*1 + 0*3 + 0*9 + 0*27
2 = -+00 = -1*1 + 1*3 + 0*9 + 0*27
3 = 0+00 = 0*1 + 1*3 + 0*9 + 0*27
4 = ++00 = 1*1 + 1*3 + 0*9 + 0*27
5 = -0+0 = -*1 + 0*3 + 1*9 + 0*27
...
15 = 0--+ = 0*1 - 1*3 - 1*9 + 1*27
...
21 = 0+-+ = 0*1 + 1*3 - 1*9 + 1*27
etc.
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very good!15=0--+
21=0+-+
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If:
10=+0+0
16=+--+
18=00-+
22=++-+
29=-+0+
find,
15 and 21
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you are really......super...!!441
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Find the missing number in this series:
31, 12, 43, 55, 98, ........., 332
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very good!!!1
2 1
2 9 1
2 9
2 1 9
1 9
1 5 9
6 1 5 9
6 1 2 5 9
1 2 5 9
1 2 8 5 9
1 2 8 9
1 2 5 8 9
6 1 2 5 8 9
6 1 2 3 5 8 9
1 2 3 5 8 9
1 2 3 7 5 8 9
1 2 3 7 8 9
1 2 3 6 7 8 9
1 2 3 6 7 8 9 5
1 2 3 6 4 7 8 9 5
1 2 3 4 7 8 9 5
1 2 3 4 6 7 8 9 5
1 2 3 4 6 7 8 9
1 2 3 4 5 6 7 8 9
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you can choose any number you wantWHen you say "choose a number", do you mean that I must grab one randomly, or do you mean that I can decide on which number I want to grab?
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Hi my friends...I`ve prepared a nice puzzle to you..
Here we go:-
Cut 9 pieces of paper,write a number on each one of them,from 1 to 9,put them in a pot,put the pot on a table.
Your aim is to arrenge these numbers on the table in this order: 123456789
according to the following rules:
1- you can choose any number to be the first number, and put it on the table.( for example I choose number 4).
2-take a second number and compare it with the number on the table, if.. 2nd>1st....put it to the left.
if 2nd<1st...put it to the right.( in my example, if I choose 7...I`ll get 74.....but if I choose 3.....will be 43).
3-now whenever you have an even amount of numbers on the table( two numbers,4,6,or 8), you should insert any number you want
between them,just in the middle.(in my example, if I want to choose 5,so I should put it in the middle to get 754,,,or 453).
4- you are allowed to take any number from the table and put it back in your pot. but to put any number again on the table,you should follow the rules.
5-to put the 4th number, you should compare it with the middle number( in my example...with number 5), if the choosen number>than
the middle number....put it to the left, if the choosen number < than the middle number...put it to the right.(in my example, if I choose
number 9,,so 9>5...I`ll get 9754,,,or 9453).
6-as in step 3.
7-whenever you have an odd amount of numbers on the table(one number,3,5,7,or 9),you should compare your choosen number with
the middle number, if your choosen number>the middle number....put it to the left.
if your choosen number<than the middle number.....put it to the right.
Have a nice time
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Yellow,Green,Red,Blue
in New Logic/Math Puzzles
Posted
An unknown number of prisoners( more than 14)were told a day before their execution, that they are going to be blind folded, and a colored paper(either.. yellow,green,red or blue) will be glued on forehead of each one of them( no one can see his own paper), then they should inter a big hall one by one to make 4 raws in this order( Yellow,Green,Red,Blue)i.e. a raw of Yallows, a raw of Greens etc.,each one will be unfolded when he inters the hall.No one of them is allowed to arrenge the others,each one should himslf choose where to stay, once he did,he can not change his place( only the first 2 prisoners can change their minds only once).Any kind of comunication between them is not allowed. If any one of them stands in a wrong raw, all of them will die!
All colores were used.
They should make a plane which saves all of them, can you help them?