The solution I came up with is similar to Cheesner's solution. Stand next to the highest point on the truck, and hold the cig at arms length. Mark the height of the tunnel on the cig with your finger nail. Walk to the tunnel entrance and check the height of the truck against the mark on the cig. This is a twist on a basic artist technique for keeping things to scale.

You are given no way to accurately find the midpoint. So with Cheesner's solution, if you are off from the midpoint, your results will be off.

I don't smoke, but I doubt the exact length of a cig is common knowledge. Dej Mar's calculation method wouldn't work if the cig's length was unknown.

your guess is a smart one also.

Walk to middle point, 75 yards, between truck and tunnel. Hold a cig at arms length. Use it to measure height of truck. Now turn 180 and measure height of tunnel. If its close, just let some air out of the tires.

Very good!!!

He can light a cigarette and measure how much time it takes the smoke to rise to the height of the truck and the height of the tunnel. If the smoke takes longer to reach the ceiling of the tunnel, chances are the truck is shorter.

Of course, he has to hope there aren't any rogue updrafts or strong winds to affect the rise of the smoke.

nope...

Someone stole a truck and wanted to cross the border with it,there is a (one way) tunnel as a short way to the border.

As he was 150 yards away from the tunnel he parked a side because he noticed that there was no traffic sign indicating the height of the tunnel ,moreover he knows nothing about the height of the truck.

If he take a risk and drive,the truck may stuck if the tunnel is too low( he can not drive backwards).

How can he make a rough estimation to know whether this truck can pass through that tunnel or not?

Note : he didn`t have any measuring tools.

( he smoke marlboro...)

she asked for her father to be spared, i think i heard this one before, but instead of the third man being the father, he is the brother of the woman. her reason was that she can get another husband and child but not another father, so the king was pleased with her thinking and spared them all.. im not sure if this is the same riddle we're talking about here.

Yes...that was her choice and her reason..!!!very good

This was a real story,happened about 1300 years ago,and till now,non of the above answers matches the case.

Three men were sentenced to death,but a woman entered infront of the king begging him to be kind to her,she said:your Majesty.. I have only these three persons in this world,the very old man is my father,the other lovely man is my husband and the young handsum one is my son, and if you kill them all,,I`ll die also...please don`t kill them...please.

The king said...well you can choose only one of them to be with you,and the other two will be killed.

It was a very hard time as each one of them looked at her and wanted to be saved..

After a while she decided to save one of them....and she said who.

The king asked her the reason why did she choose him,she gave him a very clever answer which made the king to release all of them and sent them free.

Whom did she choose? and what was her reason?

After the teacher finished describing the beauty of heaven, she asked the children, gently;

And now, my angels ... Which of you wants to go to heaven?

All of them raise their hands except one student,the teacher was surprised,,

Why you don`t want to go to heaven..dear?

I am sorry,he said,but mom told me to come back home after the school..

Lets say pairs are H1W1 (husband, wife), H2w2 and H3W3

Now:

H1H2 -> H1 comes back

H1H3 -> H1 comes back

W2W3 -> H2W2 comes back

W2W1 -> H3 comes back

H1H2 -> W3 comes back

H3W3 ->

good! but you are not the first...lol

4 = (2 + 2)

define a = b = 2, so

4 = (a + b)

4 = (a + b) x 1

4 = (a + b) x (1 / 1)

4 = (a + b) x [ (c - d) / (c - d) ]

note that this would hold regardless of the value of c and d, but to make things simple I'll also make c = d = 2

4 = (a + b) x (c - d) / (c - d)

4 = [ a(c - d) + b(c - d) ] / (c - d)

4 = [ a(c - d) + b(c - d) + 0 ] / (c - d)

4 = [ a(c - d) + b(c - d) + (c - c)] / (c - d)

since c = d we can substitute the last c in the numerator with a d

4 = [ a(c - d) + b(c - d) + (c - d)] / (c - d)

4 = [ (a + b + 1) x (c - d) ] / (c - d)

4 = (a + b + 1) x [ (c - d) / (c - d) ]

4 = (a + b + 1) x [ 1 / 1 ]

4 = a + b + 1

4 = 2 + 2 + 1

4 = 5

edit: put everything in a spoiler, although I'm not exactly sure why given the nature of this riddle

as:

c=d=2

so

c-d=0

and you can not devide on 0

I reach to (ebay)...am I right??

by giving (a)to mu,((b) to phi,(y) to omega,(d) to delta,and (e)to beta

taking the first and second equations,by adding them together we will have:

80e+20b-22a-40y= 797

by removing the numbers,we will get:

ebay

Here's a four:

   /|

   ¯|¯

Take the five line segments which make this figure and arrange them this way:

    _

   |

    ¯|

    ¯

nice...

f. i. v. e.

five out of 4 letters.

well done..

"Hey guys! could you please lend me 5 bucks??"

Guy 1: "only got 2 bucks."

Guy 2: "I can throw in an extra buck."

Guy 3: "I'll let you borrow 1.50"

Guy 4: "Here's the extra 0.5 that you need."

I got 5 (bucks) out of 4 (guys).

How can you get five out of four?

Let the pairs be named as 1,2 and 3. So the husband and wifes would be H1, W1 and so on. With this Let W1 and H1 go to the other side first. W1 will come back and then W1 and W2 go through.. After this W2 would come back.. Then W2 and W3 would go and H1 would come back. Now H1 and H2 would come. Leaving H2 at other side, H1 would go back to take H3 and come back together and everyone would have crossed.

And i also believe there may be other ways..

when W1 and W2 go through..H2 will kill pair 3.

Couple A goes across. Lady A returns. Men B and C go across. Man A returns. Ladies B and C go across. Couple B returns. Ladies A and B go across. Now with all ladies being across, Man C can return and bring Man B, then return again and bring Man A.

very good...

Lets call the couples A, B, and C

Man A goes across the river with man B. Man A leaves Man B there and returns. Man A then brings Man C over to Man B and leaves him there; Man A returns. Lady B takes Lady C over to her husband and Man B and Lady B return. Man and Lady A go to the side with the C couple where Lady A is dropped off. Man A returns. Man B takes Lady B over and returns. Finally, Man A and B return to the far side.

This is assuming Man A doesn't come out and kill Lady B and Couple C after coming back from dropping off Man B.

he`ll do it...when man A returns to other side where the pair B are alone...he`ll kill them.

Three pairs(3 men and their 3 wives)wanted to cross a river using a boat which can carry maximally 2 persons.

they should use this boat to cross the river, and there is no other boat.

Each pair concider the other pairs as strangers and regards them as enemies.

If :

strength of any man alone is 70.

strength of any woman alone is 10.

the strength of any pair is 40.

so ...if any man(when his wife is not with him) on any side of the river, come in contact with any pair,he will kill them.but he can not attack two pairs( 40+40= 80....80>70).

he can also attack any woman(other than his wife)if she is alone with him .

The same is true if two men (without their wives) can attack any pair.

The pair can not attack any one.

Two men alone on any side will not attack each other.

women will not attack at all.

how can they cross the river safely?

According to my theory....

If Teanchi and Beanchi love each other more than before,they will have a(boy).

but if they stay to this level of (love),they will have another(girl).

What if the word was written using dots, much like a digital LCD display or a dot-matrix printer renders letters. Then adding more dots can completely obliterate the original word.

Very good....!!!!

The paper was devided to very small squares,and the word was written as points(one point in each square),so by adding points to the other empty squares all around,will make it totally impossible to know what was written.

Thank you all....

I said....the word was written in a special way.....

only one answer from all above was nearly close....but still does not fulfill all the O.P. requirements.

It is not allowed to write over it.

and not allowed to cover it,or put anything over it.

moreover...The paper should remain intact.

As an example...let us take the word(left) as a magical word.

You can use any other word ,,,if you want.

The original word was "possible" and now he just added "im" before it and hence the word now is "impossible".

My question is straight forward..had nothing to do with words .

Let me say that the (magical word) was ....LEFT.

so make this word (somehow) disguised,so that no one can read it ,or estimate it( i.e. the chance to find it again will be 0%).

... the word was written in Morse code. He only had to add some dots or dashes in the spaces between every two letters and the original word would have been impossible to find after that.

but I said....each one can read it very easily....

even children in primary school.

You could add more letters to the word to make a different word with a new meaning. For example, if the word was "car" he could change it to "carbon".

but still there will be a possibility to find the word.

try again...thanks