Glycereine
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Everything posted by Glycereine
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Good riddle Sak_Iko but give people a little more time before you post the answer. It's no fun if after a couple people guess the answer is displayed.
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severed manuals divider project
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edit: egads! triple post
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edit: double post
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Yeah the Indy's wincon makes things very interesting and dangerous ><
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seventh cannary cannery slipped parrots
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Oops, I completely missed it! but yeah as soon as you have a number over 10 you have a 0 in the one's place after the factorial.
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I am trying to think of how to prove it but I'm certain that factorials beats the tetration of 9^n. hmm I messed with this post for 30 minutes and ended up deleting all my math but I still stand by my above statement. I was thinking I had proven it already but it seems circular (alot of proofs are )
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castor caster peanut envies salute
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rapper relish siesta
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pocket protea animal cobras
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1. Izzy 2. 3. 4. 5. 6. 7. 8. 9. 10. 11. Glycereine 12. 13. 14.
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Win!
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flights--xo evening--oo thought--o alabama--o reality--xo gumming--xo garages --xo steamed--oo stemmed--oo rumbles--xxoo crumble--oooo bubbles--xxoo freaked--o grieved--o
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flights--xo evening--oo thought--o alabama--o reality--xo gumming--xo garages --xo steamed--oo stemmed--oo rumbles--xxoo crumble--oooo
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interesting...
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flights--xo evening--oo thought--o alabama--o reality--xo gumming--xo garages --xo steamed--oo stemmed--oo
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Unfortunately I think you guys just did someone's homework ><
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by the time I typed mine it was posted
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flights--xo evening--oo thought--o alabama--o reality--xo gumming--xo garages --xo
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my perception of any perceived regulation is off kilter
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flights--xo evening--oo thought--o alabama--o reality--xo gumming--xo
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flights--xo evening--oo thought--o alabama--o
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The problem with the backload method is that its still multiplying each number by 9. So even with backload, the x! is higher than 9^x after 21. x being the permutations that have already happened. If x is the same size in these two cases the factorial still wins (after 21). Since the starting number 9! is far more than 21, 9^x will never catch up to x! even if they used the same number of characters. Since backloading exponents actually uses 4 characters it falls even further behind. so 9^(9^9) is less than 9!!! (we already proved that 9!! is more than 9^9 (same characters)). Since both 9!! and 9^9 are over 21, 9^(9^9) is less than (9^9)! Also 9!! is greater than 9^9, so we wouldnt use that anyways. 9!!! is greater than 9^9!! and still uses one less character.