bonanova

Cute pattern! (If I see it right...) I: Yes.

Q: yes ...!

D: 3/6 Q: 3/7 [ but see prev post.]

J; Yes. Q: Yes - sorry I missed that ...

Adding that the string is of circular cross section which does not deform under compression,

K: Yes.

D: 4/6 Q: 4/7

M: Yes.

Z: Yes. It speeds up [usually] near the end.

Z: 3/7 and 4/7

Your D word [and the OP's D word] have 6 unique letters. So your D word could have worked from that standpoint, just that three of the six were different. Hope the OP words with repeated letters don't make for too much confusion.

D: 3/6 [6 unique letters] Q: 4/7

OK, we're going to the next level. Seven-letter words, no plurals, repeated letters or proper names. Except: The Z-word is plural. The D-word, the K-word and the M-word each have one repeated letter. For one of them, the repeated letter is the initial letter. To get you started, the X-word is listed in the spoiler. It is obscure, the only one I could find that fits the letter pattern for this puzzle. Read about the letter pattern in the spoiler. . A B C D E F G H I J K L M N O P Q R S T U V W X Y Z A . 2 4 2 4 3 3 2 4 3 2 4 2 4 2 2 3 3 3 6 3 2 3 3 5 2 B 2 . 3 3 4 1 1 3 3 3 2 3 4 1 5 1 3 2 3 2 4 3 2 1 2 3 C 4 3 . 2 2 4 1 3 2 2 1 3 3 2 4 4 3 2 5 3 3 1 1 2 3 2 D 2 3 2 . 3 3 3 3 4 1 1 1 2 2 2 2 6 2 3 2 4 3 2 2 1 1 E 4 4 2 3 . 2 3 1 4 2 3 3 2 2 4 2 4 4 3 3 3 3 3 2 3 3 F 3 1 4 3 2 . 3 4 2 1 2 2 1 2 3 5 4 3 5 2 3 2 1 2 1 2 G 3 1 1 3 3 3 . 1 3 1 1 1 0 4 1 1 3 5 3 4 2 4 2 2 3 1 H 2 3 3 3 1 4 1 . 3 3 1 3 2 2 3 3 3 0 3 2 5 2 2 1 1 2 I 4 3 2 4 4 2 3 3 . 3 1 3 2 5 2 1 4 3 3 4 5 4 4 3 3 2 J 3 3 2 1 2 1 1 3 3 . 2 2 1 3 3 0 1 1 2 3 3 3 4 4 2 3 K 2 2 1 1 3 2 1 1 1 2 . 1 0 1 3 3 2 2 1 1 0 3 1 3 1 3 L 4 3 3 1 3 2 1 3 3 2 1 . 3 3 2 2 2 3 2 3 4 0 3 1 4 1 M 2 4 3 2 2 1 0 2 2 1 0 3 . 1 2 1 2 1 2 2 3 0 2 1 2 3 N 4 1 2 2 2 2 4 2 5 3 1 3 1 . 1 1 2 4 2 5 3 4 4 3 4 2 O 2 5 4 2 4 3 1 3 2 3 3 2 2 1 . 3 3 3 5 1 3 3 1 1 1 4 P 2 1 4 2 2 5 1 3 1 0 3 2 1 1 3 . 3 2 3 1 2 1 1 2 2 2 Q 3 3 3 6 4 4 3 3 4 1 2 2 2 2 3 3 . 3 4 2 4 3 2 2 1 1 R 3 2 2 2 4 3 5 0 3 1 2 3 1 4 3 2 3 . 4 3 2 3 3 2 3 2 S 3 3 5 3 3 5 3 3 3 2 1 2 2 2 5 3 4 4 . 2 4 2 1 2 1 2 T 6 2 3 2 3 2 4 2 4 3 1 3 2 5 1 1 2 3 2 . 3 3 4 3 5 2 U 3 4 3 4 3 3 2 5 5 3 0 4 3 3 3 2 4 2 4 3 . 2 3 2 2 1 V 2 3 1 3 3 2 4 2 4 3 3 0 0 4 3 1 3 3 2 3 2 . 2 2 1 3 W 3 2 1 2 3 1 2 2 4 4 1 3 2 4 1 1 2 3 1 4 3 2 . 4 3 2 X 3 1 2 2 2 2 2 1 3 4 3 1 1 3 1 2 2 2 2 3 2 2 4 . 2 2 Y 5 2 3 1 3 1 3 1 3 2 1 4 2 4 1 2 1 3 1 5 2 1 3 2 . 2 Z 2 3 2 1 3 2 1 2 2 3 3 1 3 2 4 2 1 2 2 2 1 3 2 2 2 .

The beauty of this puzzle - as regards standard maze puzzles - is that it does not fix an exit point. The candidate exit points are as multiplicitous as the initial branching points in a standard maze. But I don't know of a better way to start. It isn't an easy puzzle.

What she said ...

This is correct. Your last step must be the step that takes you outside. The OP did not make that clear.

Shown below is a forest of numbers. Your task is to reach a dot at the edge of the forest. Starting from the central Number 3 you are to walk 3 steps in one of eight directions: N, S, E, W, NE, SE, SW, NW. There you find another number that tells you how many steps to take on the second leg of your journey, again, in one of eight directions. Continue making the indicated series of steps until you come to a number that will take you just one step beyond the grid of numbers. You may then reward yourself with a trip to the kitchen, for you will have solved the puzzle. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 4 7 7 . . . . . . . . . . . . . . . . . 5 4 4 8 3 3 4 6 3 . . . . . . . . . . . . 1 4 5 1 1 1 4 5 1 7 1 3 5 . . . . . . . . . 4 9 4 9 6 7 5 5 5 8 7 6 6 8 5 . . . . . . . 3 7 2 9 8 3 5 6 7 3 9 1 8 7 5 8 5 . . . . . . 1 4 7 8 4 2 0 2 7 1 1 8 2 2 7 6 3 . . . . . 7 2 1 9 5 5 3 1 1 3 1 3 3 4 2 8 6 1 3 . . . . 4 2 6 7 2 5 2 4 2 2 5 4 3 2 8 1 7 7 3 . . . . 4 1 6 5 1 1 1 9 1 4 3 4 4 3 1 9 8 2 7 . . . 4 3 5 2 3 2 2 3 2 4 2 5 3 5 1 1 3 5 5 3 7 . . 2 7 1 5 1 1 3 1 5 3 3 2 4 2 3 7 7 5 4 2 7 . . 2 5 2 2 6 1 2 4 4 6 3 4 1 2 1 2 6 5 1 8 8 . . . 4 3 7 5 1 9 3 4 4 5 2 9 4 1 9 5 7 4 8 . . . . 4 1 6 7 8 3 4 3 4 1 3 1 2 3 2 3 6 2 4 . . . . 7 3 2 6 1 5 3 9 2 3 2 1 5 7 5 8 9 5 4 . . . . . 1 6 7 3 4 8 1 2 1 2 1 2 2 8 9 4 1 . . . . . . 2 5 4 7 8 7 5 6 1 3 5 7 8 7 2 9 3 . . . . . . . 6 5 6 4 6 7 2 5 2 2 6 3 4 7 4 . . . . . . . . . 2 3 1 2 3 3 3 2 1 3 2 1 1 . . . . . . . . . . . . 7 4 4 5 7 3 4 4 7 . . . . . . . . . . . . . . . . . 3 3 4 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . Printing it out and using a pencil might be the best approach to solving it. Have fun escaping. Edit: The last leg of your journey must reach a dot on your final step. Not before.

IDNE - H K N P V W Y Yes S anagram. JBR - O Yes. List is correct except for anagrams of R and S. Of course, anagrams are equally solutions. Nicely done. The clue, aka the pattern, points you to the Y word. Check the spoiler in the OP.

H: Yes

H... Well that was simultaneous...

R: Yes. Very kind of you .... done.

R: No, but 6/6

Hi imran, ltns Is that distribution unique? Not that is has to be, mind you, just wondering.