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# Caliban27

Member Since 24 Oct 2012
Offline Last Active Feb 09 2013 07:03 AM

### In Topic: DOWRY

08 January 2013 - 07:17 AM

Spoiler for stats

### In Topic: Find the missing combination

24 December 2012 - 01:26 AM

Merry Christmas, wolfgang!

Spoiler for it must be

Merry Xmas to you both.

Spoiler for used similar approach but different answer.

### In Topic: Tale of two clocks

14 December 2012 - 12:01 AM

Spoiler for Arthur

Spoiler for Robert

### In Topic: The elusive chord

16 November 2012 - 07:20 AM

I was just pointing out that Bertrand left out that method for choosing a chord. However,

Spoiler for There are more ways to skin a cat

I agree with CaptainEd. Jaynes' solution to the Bertrand paradox shows that random radius (method 2) is the only robust theoretical means of choosing random chord.

### In Topic: easy one

24 October 2012 - 08:12 AM

double the smaller number, add to the larger
7*8 = (2x7) + 8 = 22

That won't work, 'cause 4*9 would be 17 not 21.
A variation to that theme which would work is: if second number is smaller, then [first number] + twice [second number], else, [first number] + twice second number] - 1. That is quite inelegant, and does not solve for instance of both numbers the same. Back to thinking further outside cube.