Given a compass, a straightedge, and a line segment AB of length 3, how could you draw a line segment with a precise length of the square root of 3?

**Edited by BMAD, 28 May 2013 - 10:44 PM.**

Welcome to BrainDen.com - Brain Teasers Forum. Like most online communities you must register to post in our community, but don't worry this is a simple free process. To be a part of BrainDen Forums you may create a new account or sign in if you already have an account. As a member you could start new topics, reply to others, subscribe to topics/forums to get automatic updates, get your own profile and make new friends. Of course, you can also enjoy our collection of amazing optical illusions and cool math games. If you like our site, you may support us by simply clicking Google "+1" or Facebook "Like" buttons at the top. If you have a website, we would appreciate a little link to BrainDen. Thanks and enjoy the Den :-) |

Guest Message by DevFuse

Started by BMAD, May 28 2013 10:43 PM

9 replies to this topic

Posted 28 May 2013 - 10:43 PM

Given a compass, a straightedge, and a line segment AB of length 3, how could you draw a line segment with a precise length of the square root of 3?

**Edited by BMAD, 28 May 2013 - 10:44 PM.**

Posted 29 May 2013 - 12:48 AM

Spoiler for Well...

Posted 29 May 2013 - 10:25 AM

Spoiler for

Posted 29 May 2013 - 03:55 PM

Spoiler for steps

Posted 30 May 2013 - 05:16 AM

I won't spoiler this answer cuz it's offered in jest.

Start instead with a line AB of length 1 and construct a line of length sqrt(1).

Then scale up by factor of three.

Start instead with a line AB of length 1 and construct a line of length sqrt(1).

Then scale up by factor of three.

*Vidi vici veni.*

Posted 30 May 2013 - 09:36 AM

Spoiler for It seems to be easy one

Posted 30 May 2013 - 11:28 AM

Spoiler for It seems to be easy one

Step 1 would be the problem.

*Vidi vici veni.*

Posted 30 May 2013 - 01:10 PM

Step 1 would be the problem.Spoiler for It seems to be easy one

Spoiler for step 1

Posted 30 May 2013 - 02:08 PM

Step 1 would be the problem.Spoiler for It seems to be easy one

Spoiler for step 1

Spoiler for Complete reply

0 members, 0 guests, 0 anonymous users