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Guest Message by DevFuse

# Drawing the square root of 3

9 replies to this topic

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Posted 28 May 2013 - 10:43 PM

Given a compass, a straightedge, and a line segment AB of length 3, how could you draw a line segment with a precise length of the square root of 3?

Edited by BMAD, 28 May 2013 - 10:44 PM.

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Posted 28 May 2013 - 11:16 PM

Spoiler for

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### #3 Rob_Gandy

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Posted 29 May 2013 - 12:48 AM

Spoiler for Well...

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### #4 phil1882

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Posted 29 May 2013 - 10:25 AM

Spoiler for

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### #5 k-man

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Posted 29 May 2013 - 03:55 PM

Spoiler for steps

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### #6 bonanova

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Posted 30 May 2013 - 05:16 AM

I won't spoiler this answer cuz it's offered in jest.
Start instead with a line AB of length 1 and construct a line of length sqrt(1).
Then scale up by factor of three.
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Vidi vici veni.

### #7 bhramarraj

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Posted 30 May 2013 - 09:36 AM

Spoiler for It seems to be easy one

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### #8 bonanova

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Posted 30 May 2013 - 11:28 AM

Spoiler for It seems to be easy one

Step 1 would be the problem.
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Vidi vici veni.

### #9 bhramarraj

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Posted 30 May 2013 - 01:10 PM

Spoiler for It seems to be easy one

Step 1 would be the problem.

Spoiler for step 1

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### #10 bhramarraj

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Posted 30 May 2013 - 02:08 PM

Spoiler for It seems to be easy one

Step 1 would be the problem.

Spoiler for step 1