Given a compass, a straightedge, and a line segment AB of length 3, how could you draw a line segment with a precise length of the square root of 3?

**Edited by BMAD, 28 May 2013 - 10:44 PM.**

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Guest Message by DevFuse

Started by BMAD, May 28 2013 10:43 PM

9 replies to this topic

Posted 28 May 2013 - 10:43 PM

Given a compass, a straightedge, and a line segment AB of length 3, how could you draw a line segment with a precise length of the square root of 3?

**Edited by BMAD, 28 May 2013 - 10:44 PM.**

Posted 29 May 2013 - 12:48 AM

Spoiler for Well...

Posted 29 May 2013 - 10:25 AM

Spoiler for

Posted 29 May 2013 - 03:55 PM

Spoiler for steps

Posted 30 May 2013 - 05:16 AM

I won't spoiler this answer cuz it's offered in jest.

Start instead with a line AB of length 1 and construct a line of length sqrt(1).

Then scale up by factor of three.

Start instead with a line AB of length 1 and construct a line of length sqrt(1).

Then scale up by factor of three.

- Bertrand Russell

Posted 30 May 2013 - 09:36 AM

Spoiler for It seems to be easy one

Posted 30 May 2013 - 11:28 AM

Spoiler for It seems to be easy one

Step 1 would be the problem.

- Bertrand Russell

Posted 30 May 2013 - 01:10 PM

Step 1 would be the problem.Spoiler for It seems to be easy one

Spoiler for step 1

Posted 30 May 2013 - 02:08 PM

Step 1 would be the problem.Spoiler for It seems to be easy one

Spoiler for step 1

Spoiler for Complete reply

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