Clue is a rather popular board game that requires deduction and reasoning
For my questions these are the rules to follow:
There are always 6 people playing at the start of the game, you are one of those 6.
There are 6 suspects
Mustard
Scarlet
White
Plum
Green
Peacock
There are 6 weapons
Wrench
Rope
Candlestick
Knife
Pipe
Pistol
There are 9 rooms
Kitchen
Dining Room
Lounge
Hall
Study
Library
Observatory
Spa
Patio
There are cards representing each suspect, weapon, and room
At the start 1 suspect, 1 weapon, and 1 room will be randomly chosen and placed in an envelope
At the start each player recieves 3 random cards, they are not any of the 3 placed in the envelope and they can be any combination of suspects, weapons, and rooms.
Ex. You could get 3 room cards, or you could get 2 suspects and a weapon, etc.
As each person takes his/her turn they will make a guess, of the suspect, weapon, and room.
They will always make exactly one guess each turn.
Then if one of the other 5 people can disprove either of the 3 things guessed they will show the guesser and only the guesser one of the 3 cards guessed.
These are my questions:
1. What are the best 3 cards to get to have the best odds of guessing the 3 cards in the envelope without anyone taking any turns?
2. Is it possible to KNOW the 3 cards in the envelope in one turn (each person guesses once), assume the best case scenario. If not in the best case what is the minimum number of turns required before you KNOW the 3 cards in the envelope?
3. What are the worst 3 cards to start with?
4. Assume the worst case, what is the maximum number of turns that can be taken before you KNOW the contents of the envelope?
5. What are the odds that someone will KNOW the contents of the envelope before YOU KNOW the contents of the envelope?
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Clue is a rather popular board game that requires deduction and reasoning
For my questions these are the rules to follow:
There are always 6 people playing at the start of the game, you are one of those 6.
There are 6 suspects
Mustard
Scarlet
White
Plum
Green
Peacock
There are 6 weapons
Wrench
Rope
Candlestick
Knife
Pipe
Pistol
There are 9 rooms
Kitchen
Dining Room
Lounge
Hall
Study
Library
Observatory
Spa
Patio
There are cards representing each suspect, weapon, and room
At the start 1 suspect, 1 weapon, and 1 room will be randomly chosen and placed in an envelope
At the start each player recieves 3 random cards, they are not any of the 3 placed in the envelope and they can be any combination of suspects, weapons, and rooms.
Ex. You could get 3 room cards, or you could get 2 suspects and a weapon, etc.
As each person takes his/her turn they will make a guess, of the suspect, weapon, and room.
They will always make exactly one guess each turn.
Then if one of the other 5 people can disprove either of the 3 things guessed they will show the guesser and only the guesser one of the 3 cards guessed.
These are my questions:
1. What are the best 3 cards to get to have the best odds of guessing the 3 cards in the envelope without anyone taking any turns?
2. Is it possible to KNOW the 3 cards in the envelope in one turn (each person guesses once), assume the best case scenario. If not in the best case what is the minimum number of turns required before you KNOW the 3 cards in the envelope?
3. What are the worst 3 cards to start with?
4. Assume the worst case, what is the maximum number of turns that can be taken before you KNOW the contents of the envelope?
5. What are the odds that someone will KNOW the contents of the envelope before YOU KNOW the contents of the envelope?
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