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Three Tanks: 7,000,000 gallon, 4,000,000 gallon & 3,000,000 gallon

Only the 7,000,000 gallon tank is full, the other tanks are empty. Not spending too much time or energy, distribute the water to be 2,000,000, 2,000,000 & 3,000,000 gallons per tank.

7 - 0 - 0

(-4, +4, +0)

3 - 4 - 0

(+0, -3, +3)

3 - 1 - 3

(+3, +0, -3)

6 - 1 - 0

(+0, -1, +1)

6 - 0 - 1

(-4, +4, +0)

2 - 4 - 1

(+0, -2, +2)

2 - 2 - 3

Whew! That was a lot of work! I only had a 5 gallon bucket.....

Edited by firepumpguy
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  • 3 weeks later...

guys the admin is wrong here is the solution in plain english

start, 7 0 0

pour #1, pour 7 into the 4

making, 3 4 0

pour #2, pour the 4 into 3

making, 3 1 3

pour #3, pour 3 back into 7

making, 6 1 0

pour #4, pour 4 into 3

making, 6 0 1

pour#5, pour 7 into 4

making, 2 4 1

pour#6, pour 4 into 3

making, 2 2 3

6 moves, I hope you can do simple math.

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correction, the admin is right, I hope everyone can see the solution

guys the admin is wrong here is the solution in plain english

start, 7 0 0

pour #1, pour 7 into the 4

making, 3 4 0

pour #2, pour the 4 into 3

making, 3 1 3

pour #3, pour 3 back into 7

making, 6 1 0

pour #4, pour 4 into 3

making, 6 0 1

pour#5, pour 7 into 4

making, 2 4 1

pour#6, pour 4 into 3

making, 2 2 3

6 moves, I hope you can do simple math.

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may be i am dumb, but why cant you do it like this....

7-0-0

3-4-0

2-4-1

2-2-3

Because on your third step (2-4-1) you have poured exactly 1 litre into a bowl with a 3 litre capacity that was poured from a 7 litre capacity bowl with 3 litres in it. Estimating is not allowed.

or

7-0-0

3-4-0

3-2-2

1-2-3

appreciate any input

On the third step, you have poured 2 litres from a filled 4 litre bowl into a bowl with a 3 litre capacity. (You also mistakenly wrote 1-2-3 for the end result instead of 2-2-3.)

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  • 1 month later...

Damn... I thought 10 was good!

Jugs are named:

A. 7

B. 4

C. 3

0. Start:

7 0 0

1. Pour "A" into "B" (to top):

3 4 0

2. Pour "B" into "C" (to top):

3 1 3

3. Pour all of "A" into "B":

0 4 3

4. Pour all of "B" back into "A":

4 0 3

5. Pour all of "C" into "B":

4 3 0

6. Pour "A" into "C" (to top):

1 3 3

7. Pour "C" into "B" (to top):

1 4 2

8. Pour all of "B" into "A":

5 0 2

9. Pour all of "C" into "B":

5 2 0

10. Pour "A" into "C" (to top):

2 2 3

Edited by pendragon
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  • 2 weeks later...
  • 2 weeks later...

4 steps (excluding initial state):

0: a=7 b=0 c=0

1: 3 4 0 (self-explanatory)

2: 3 3 1 (pour b into c until b=a)

3: 2 4 1 (fill rest of b with a)

4: 2 2 3 (fill rest of c with b)

Edited by five0to180
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Pouring water III. - Back to the Water and Weighing Puzzles

Having three bowls: 7, 4 and 3 litres capacity. Only the 7-litre is full. Pouring the fewest times gain the quantity of 2, 2 and 3 litres.

Pouring Water III. - solution

Three numerals in each number stand for litres in each bowl:

700 - 340 - 313 - 610 - 601 - 241 - 223 (overspilling 6 times)

There is a better solution. See the solution I posted. There is no estimating involved (unless you're really stingy about what "estimate" means).

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There is a better solution. See the solution I posted. There is no estimating involved (unless you're really stingy about what "estimate" means).

Actually, my solution makes the assumption that the bowls are homogeneous, which was not explicitly stated in the problem. If they aren't, then it's not possible to do step 2 without estimating.

Edited by five0to180
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Actually, my solution makes the assumption that the bowls are homogeneous, which was not explicitly stated in the problem. If they aren't, then it's not possible to do step 2 without estimating.

exactly ... that would not work for various shapes ... nevertheless, good thinking

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  • 3 weeks later...
Done it in 5 pours (7, 4, 3 Litres respectively)

700 - 340 - 313 - 601 - 241 - 223

No half pours, no steps missed!

There is a missed step. From 313 to 601 you need to do 313 - 610 - 601

There are of course multiple solutions, but 6 pours is the best solution.

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  • 1 month later...
Pouring water III. - Back to the Water and Weighing Puzzles

Having three bowls: 7, 4 and 3 litres capacity. Only the 7-litre is full. Pouring the fewest times gain the quantity of 2, 2 and 3 litres.

Pouring Water III. - solution

Three numerals in each number stand for litres in each bowl:

700 - 340 - 313 - 610 - 601 - 241 - 223 (overspilling 6 times)

1) Pour 3L from 7L bowl to 3L bowl (4:0:3)

2) Pour this 3L from 3L bowl to 4L bowl (4:3:0)

3) Nw again pour 3L from 7L bowl to 3L bowl (1:3:3)

4) Nw pour frm 3L bowl to 4L bowl till 4L bowl is full i.e. pour 1L (1:4:2)

5) Nw pour whole 4L from 4L bowl to 7L bowl (5:0:2)

6) Nw pour the 2L from 3L bowl to 4L bowl (5:2:0)

7) Nw finally, again pour 3L from 7L bowl to 3L bowl (2:2:3)

Hence done :rolleyes:

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  • 1 year later...

6.

#   7:7 | 4:0 | 3:0

===================

1]  7:3 | 4:4 | 3:0

-------------------

2]  7:3 | 4:1 | 3:3

-------------------

3]  7:6 | 4:1 | 3:0

-------------------

4]  7:6 | 4:0 | 3:1

-------------------

5]  7:2 | 4:4 | 3:1

-------------------

6]  7:2 | 4:2 | 3:3

Edited by MaZa
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  • 6 months later...
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