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Pouring water III.

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Pouring water III. - Back to the Water and Weighing Puzzles

Given three bowls: 7, 4 and 3 liters capacity. Only the 7-liter is full. Pouring the water the fewest number of times, make the quantities of 2, 2, and 3 liters.

This old topic is locked since it was answered many times. You can check solution in the Spoiler below.

Pls visit New Puzzles section to see always fresh brain teasers.

Pouring Water III. - solution

Three numerals in each number stand for litres in each bowl:

700 - 340 - 313 - 610 - 601 - 241 - 223 (overspilling 6 times)

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Twice: 7 liter into the 3 liter leaving 4 in the 7 liter container. Then pour half of whats left "4" into the last 4 liter container so you have 3-2-2. Thus two pours.

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Twice: 7 liter into the 3 liter leaving 4 in the 7 liter container. Then pour half of whats left "4" into the last 4 liter container so you have 3-2-2. Thus two pours.

in these puzzles you cant pour a fraction of a bowl...that wouldnt be much of a puzzle now would it?

this is what i got in 5 pours:(using the same 3-digit code)

700-403-133-124-520-223

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you can't do 133 without doing 430...

i did 700, 403, 430, 133, 142, 520, 223.

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how about 700 304 331 601 241 223

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how about 700 304 331 601 241 223

Assuming jars are 7 - 3 - 4 based on your first pour, your fourth pour goes out of sequence (which would mean you have 4 in your 3 jar! You would need to pour the 1 in the 4 into the 3. this effectively is the same as the admin's answer.

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you can't do 133 without doing 430...

i did 700, 403, 430, 133, 142, 520, 223.

You can't go from 142 to 520. There's a 502 step in between, which makes it seven steps.

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i still dont see whats wrong with 700 403 223

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i still dont see whats wrong with 700 403 223

You can't pour *half* of the 4 liters into another bowl, because you have no way of accurately measuring a half. You must pour entire bowl-fulls.

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I had to register just to post this answer. It is three pours:

From the 7, pour into the 4 and 3 (leaving the 7 empty). Then pour half of the four into the 7, leaving 2 liters in the 7, 2 liters in the 4 and 3 liters in the 3.

700, 340, 043, 223

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I had to register just to post this answer. It is three pours:

From the 7, pour into the 4 and 3 (leaving the 7 empty). Then pour half of the four into the 7, leaving 2 liters in the 7, 2 liters in the 4 and 3 liters in the 3.

700, 340, 043, 223

YOU CAN'T POUR HALF OF A BOWL!

Imagine you're Samuel L. Jackson or Bruce Willis in Die Hard. You're trying to diffuse a bomb, and you need an exact amount of water to trigger a scale and turn the bomb off. Pouring "half" of a bowl isn't very exact, and would likely result in you being blown to bits.

How many times does it have to be said that you can't pour half of a bowl?

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I did it this way in 6 steps:

700-340-313-610-601-241-223

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nice too easy

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HA HA! Its interesting that people who can't read are doing logic puzzles on the internet.

But really, what I would do is pour 2/7 of the original into the 3 liter bowl, and then pour 3/5 of remaining into the 4 liter bowl. Then I would diffuse the bomb.

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Done it in 5 pours (7, 4, 3 Litres respectively)

700 - 340 - 313 - 601 - 241 - 223

No half pours, no steps missed!

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700 - 340 - 313 - 601 - 241 - 223

xxx - xxx - xxx - ???

You missed a step.

You moved the 1 from the middle position of 313 to the end, making 601, but it would really be 610. Sorry.

tiny mind

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it was a good one but it took me while to understand it

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Start by pouring 2.33 into each of the second and third bowl, leaving all three with 2.33.

Then pour .33 from the second and third bowl into the first, leaving 3 in first and 2 in 2nd & 3rd.

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I had to register just to post this answer. It is three pours:

From the 7, pour into the 4 and 3 (leaving the 7 empty). Then pour half of the four into the 7, leaving 2 liters in the 7, 2 liters in the 4 and 3 liters in the 3.

700, 340, 043, 223

As said before the puzzle doesn't allow for half pours. Wouldn't be a point to the puzzle otherwise.

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IS SO EASY MAN ITS 6 POURS :P

FIRST U START OFF WITH

7/7

0/4

0/3

1ST POUR

3/7

4/4

0/3

2ND POUR

3/7

1/4

3/3

3RD POUR

6/7

1/4

0/3

4TH POUR

6/7

0/4

1/3

5TH POUR

2/7

4/4

1/3

6TH POUR

2/7

2/4

3/3

VOILA

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700/403/430/133/142/502/520/223

done

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7-0-0 is original set up

Pour 7 liter into 3 liter..... Leaving 4-0-3

Pour 3 liter to 4 liter.....leaves 4 liter, 3 liter, 0 liter

Pour 7 Liter to 3 liter....leaves 1 liter, 3 liter, 3liter

Pour 3 Liter to 4 liter....Leaves 1 liter, 4 liter, 2 liter

Pour 4 Liter to 7 Liter.....Leaves 5 liter, 0 liter, 2 liter

Pour 3 Liter to 4 liter.....Leaves 5 liter, 2 liter, 0 liter

Pour 7 Liter to 3 Liter.....Leaves 2 liter, 2 liter, 3 liter

7 moves

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Pouring water III. - Back to the Water and Weighing Puzzles

Having three bowls: 7, 4 and 3 litres capacity. Only the 7-litre is full. Pouring the fewest times gain the quantity of 2, 2 and 3 litres.

Pouring Water III. - solution

Three numerals in each number stand for litres in each bowl:

700 - 340 - 313 - 610 - 601 - 241 - 223 (overspilling 6 times)

Place the 3 inside the 4. Pour outside the 3 leaving one liter inside the 4. Remove the 3 and pour the one liter from the 4 into the 3. Replace the 3 inside the 4 and again pour outside the 3 leaving one liter inside the 4. Remove the 3 and pour the contents of 3 into the 4. This will leave 2 liters in the four and 5 liters in the 7. Pour the 3 full from the 7 leaving you with two liters in the 7, two liters in the 4 and the 3 is full.

5 pours

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you can't do 133 without doing 430...

i did 700, 403, 430, 133, 142, 520, 223.

Your last 2 pours are wrong. You cannot get 520 directly from 142.

Capacity (<Actual water in bowl>)

142 = 7(1), 4(4), 3(2)

502 = 7(5), 4(0), 3(2)

520 = 7(5), 4(2), 3(0)

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I too did this originally in seven steps, as previously stated:

700, 403, 430, 133, 142, 502, 520, 223

Didn't quite get the six. Interesting how these two solutions are quite a bit different from each other.

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