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Pouring water III. - Back to the Water and Weighing Puzzles

Given three bowls: 7, 4 and 3 liters capacity. Only the 7-liter is full. Pouring the water the fewest number of times, make the quantities of 2, 2, and 3 liters.

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Pouring Water III. - solution

Three numerals in each number stand for litres in each bowl:

700 - 340 - 313 - 610 - 601 - 241 - 223 (overspilling 6 times)

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  • 2 months later...
  • 2 weeks later...
Twice: 7 liter into the 3 liter leaving 4 in the 7 liter container. Then pour half of whats left "4" into the last 4 liter container so you have 3-2-2. Thus two pours.

in these puzzles you cant pour a fraction of a bowl...that wouldnt be much of a puzzle now would it?

this is what i got in 5 pours:(using the same 3-digit code)

700-403-133-124-520-223

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how about 700 304 331 601 241 223

Assuming jars are 7 - 3 - 4 based on your first pour, your fourth pour goes out of sequence (which would mean you have 4 in your 3 jar! You would need to pour the 1 in the 4 into the 3. this effectively is the same as the admin's answer.

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i still dont see whats wrong with 700 403 223

You can't pour *half* of the 4 liters into another bowl, because you have no way of accurately measuring a half. You must pour entire bowl-fulls.

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  • 3 weeks later...

I had to register just to post this answer. It is three pours:

From the 7, pour into the 4 and 3 (leaving the 7 empty). Then pour half of the four into the 7, leaving 2 liters in the 7, 2 liters in the 4 and 3 liters in the 3.

700, 340, 043, 223

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  • 2 weeks later...
I had to register just to post this answer. It is three pours:

From the 7, pour into the 4 and 3 (leaving the 7 empty). Then pour half of the four into the 7, leaving 2 liters in the 7, 2 liters in the 4 and 3 liters in the 3.

700, 340, 043, 223

YOU CAN'T POUR HALF OF A BOWL!

Imagine you're Samuel L. Jackson or Bruce Willis in Die Hard. You're trying to diffuse a bomb, and you need an exact amount of water to trigger a scale and turn the bomb off. Pouring "half" of a bowl isn't very exact, and would likely result in you being blown to bits.

How many times does it have to be said that you can't pour half of a bowl?

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  • 4 weeks later...

HA HA! Its interesting that people who can't read are doing logic puzzles on the internet.

But really, what I would do is pour 2/7 of the original into the 3 liter bowl, and then pour 3/5 of remaining into the 4 liter bowl. Then I would diffuse the bomb.

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  • 3 weeks later...
  • 2 months later...
I had to register just to post this answer. It is three pours:

From the 7, pour into the 4 and 3 (leaving the 7 empty). Then pour half of the four into the 7, leaving 2 liters in the 7, 2 liters in the 4 and 3 liters in the 3.

700, 340, 043, 223

As said before the puzzle doesn't allow for half pours. Wouldn't be a point to the puzzle otherwise.

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  • 2 weeks later...

IS SO EASY MAN ITS 6 POURS :P

FIRST U START OFF WITH

7/7

0/4

0/3

1ST POUR

3/7

4/4

0/3

2ND POUR

3/7

1/4

3/3

3RD POUR

6/7

1/4

0/3

4TH POUR

6/7

0/4

1/3

5TH POUR

2/7

4/4

1/3

6TH POUR

2/7

2/4

3/3

VOILA

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  • 2 weeks later...

7-0-0 is original set up

Pour 7 liter into 3 liter..... Leaving 4-0-3

Pour 3 liter to 4 liter.....leaves 4 liter, 3 liter, 0 liter

Pour 7 Liter to 3 liter....leaves 1 liter, 3 liter, 3liter

Pour 3 Liter to 4 liter....Leaves 1 liter, 4 liter, 2 liter

Pour 4 Liter to 7 Liter.....Leaves 5 liter, 0 liter, 2 liter

Pour 3 Liter to 4 liter.....Leaves 5 liter, 2 liter, 0 liter

Pour 7 Liter to 3 Liter.....Leaves 2 liter, 2 liter, 3 liter

7 moves

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  • 3 weeks later...
Pouring water III. - Back to the Water and Weighing Puzzles

Having three bowls: 7, 4 and 3 litres capacity. Only the 7-litre is full. Pouring the fewest times gain the quantity of 2, 2 and 3 litres.

Pouring Water III. - solution

Three numerals in each number stand for litres in each bowl:

700 - 340 - 313 - 610 - 601 - 241 - 223 (overspilling 6 times)

Place the 3 inside the 4. Pour outside the 3 leaving one liter inside the 4. Remove the 3 and pour the one liter from the 4 into the 3. Replace the 3 inside the 4 and again pour outside the 3 leaving one liter inside the 4. Remove the 3 and pour the contents of 3 into the 4. This will leave 2 liters in the four and 5 liters in the 7. Pour the 3 full from the 7 leaving you with two liters in the 7, two liters in the 4 and the 3 is full.

5 pours

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you can't do 133 without doing 430...

i did 700, 403, 430, 133, 142, 520, 223.

Your last 2 pours are wrong. You cannot get 520 directly from 142.

Capacity (<Actual water in bowl>)

142 = 7(1), 4(4), 3(2)

502 = 7(5), 4(0), 3(2)

520 = 7(5), 4(2), 3(0)

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  • 3 weeks later...

I too did this originally in seven steps, as previously stated:

700, 403, 430, 133, 142, 502, 520, 223

Didn't quite get the six. Interesting how these two solutions are quite a bit different from each other.

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