I know I'm probably wrong, so work with me

[Guest]

a question I think I've seen on this board, (but it might be somewhere else) the question of "how could you poor exactly 1 liter of water into a bowl, without there being a minute difference with just some liquid residue.

easy.

pour 2 liters into a bowl

I haven't gotten you yet, have I?

because, for just one small portion of time, like, a trillionth of a nanosecond, maybe less maybe more

there will be exactly 1 liters worth of water molecules in that bowl.

before more water enters and the amount of water in the bowl grows.

unless 2 molecules enter the bowl at the same time

but what are the chances of 2 molecules entering at the exact same time?

wouldn't there be some minute difference in time?

[unreality]

Seems right to me. If just for a trillionth of a nanosecond, like you said

[Guest]

woo!

I didn't completely screw up!

[unreality]

I guess it depends on if the H2O molecules clump together and go in together and whether their clumpy position was vertical or horizontal... and how you define "inside the bowl" so there can be some leeway. That, coupled with the fact that a liter isnt defined to the molecule, and you're definitely right

[Guest]

oh duh, that's true

liters are for all liquids and all liquids have different densities.

[Guest]

Sorry to attempt to burst your bubble Ploper, but..........

Water molecules are cohesive and have dipoles, which mean one end of the is very slightly poitively charged and the other end is very slightly negatively charged, so because of electrostatic attraction (posh word for opposite charges attract) the molecules are cohesive (posh word for stick together) so the chance of the last nolecule of a litre to be alone and not stuck with another molecule is very small

Sorry

Thanks for reading

[Guest]

aha, no problemo

didn't you just prove me right?

I said that I'm probably wrong

and I was

so I win both ways!

[unreality]

oooh the man thinks ahead!

[Guest]

I've got it all figured out up here