[Guest]

You are an explorer hoping to find your way to the coast of an island. You have three maps, X, Y, Z. One was true, two were false. There were five natives, of the two tribes. The Doog always told the truth. The Dab always told lies. They gave him the following advice.

1. X is the correct map.

2. Y is the correct map.

3. 1 and 2 are not both Dabs.

4. Either 1 is a Dab or 2 is a Doog.

5. Either I am a Dab or 3 and 4 are of the same type.(That is both Doogs or both Dabs)

Which Map is the correct map?

[Guest]

why dont you just try each map out... when u try z and see a landmark if its not listed on map its wrong one, try y and then x

then you know which one is right

[Guest]

You are an explorer hoping to find your way to the coast of an island. You have three maps, X, Y, Z. One was true, two were false. There were five natives, of the two tribes. The Doog always told the truth. The Dab always told lies. They gave him the following advice.

1. X is the correct map.

2. Y is the correct map.

3. 1 and 2 are not both Dabs.

4. Either 1 is a Dab or 2 is a Doog.

5. Either I am a Dab or 3 and 4 are of the same type.(That is both Doogs or both Dabs)

Which Map is the correct map?

We know that 3 and 4 are said by the same person since nobody would say that they lie (a dab would be telling the truth and a doog would be lying). If 3 and 4 were said by a dab then neither map was correct (since 1 and 2 are both dabs) creating a paradox. this means that the speaker of 3 and 4 were doogs (truth telling). We now know that only 1 is a doog (since there is a correct map) and 2 cannot be a doog since that would mean that 1 is a dab so both of statement 4 would be correct whereas the statement says "or". We now know that 1 is a doog and henceforth telling the truth

[Guest]

We know that 3 and 4 are said by the same person since nobody would say that they lie (a dab would be telling the truth and a doog would be lying). If 3 and 4 were said by a dab then neither map was correct (since 1 and 2 are both dabs) creating a paradox. this means that the speaker of 3 and 4 were doogs (truth telling). We now know that only 1 is a doog (since there is a correct map) and 2 cannot be a doog since that would mean that 1 is a dab so both of statement 4 would be correct whereas the statement says "or". We now know that 1 is a doog and henceforth telling the truth

So which map do you think it is X, Y, or Z

it's not the last letter of the alphabet

[Guest]

So which map do you think it is X, Y, or Z

it's not the last letter of the alphabet

Number 1 was telling the truth. If you want me to say a letter then X but I though I had made it clear in my last post

[Guest]

ok its ....

5 say is lieing making him a DAb and making 3 and 4 different types if 3 were to truth then that woould go with 4 telling a lie saying that 1 is a dab and 2 is a doog meaning that 2 is telling the truth

but if you switch which was lieing and who was telling the truth

3 lieing and 4 telling the truth then

that would mean taht both 1 and 2 are lieing because 3 states that 1and 2 are Dabs and 4 only states that 1 is a dab or 2 is a doog, which means 1 is a dab not saying wat the other is but because he is telling the truth that means that 2 can not be a doog so 2 is also a dab. which by the end means z is the correct map

there are too many gaps and this does not talk abot map z so it is unsure which map is right

its ether map y or z there is not and statement saying talking about map z

answer is unsure i stated how my reasoning

ether MAP Y OR Z it is unclear

[plasmid]

Interesting, doog and dab are backwards for good and bad.

I came up with a different solution than reaymond, but that's because we had different interpretations of #4's statement. If BOTH 1 is a dab and 2 is a doog, is #4's satement true? I said yes, reaymond said no, so we're probably both correct depending on how you interpret it.

This is going to be a long explanation, but I'm going to explain a way to approach these problems in general that helps me make sure I'm not leaving anything out. First off, we know that one of the three maps is true and the rest are false. I'll denote the three possible situations as

{ X , Y , Z }

Person 1 made a statement that is either true or false. Before I start considering what he actually said, I'll just say that for each of the three possibilities above, #1 might have been either been True or False, giving the possible combinations of

{ X 1T , X 1F , Y 1T , Y 1F , Z 1T , Z 1F }

Now since #1 said that X is the correct map, we can clearly get rid of X 1F , Y 1T , & Z 1T so we're left with

{ X 1T , Y 1F , Z 1F }

Now #2 said that Y is the correct map. Without much difficulty we can see that the possibilities are now

{ X 1T 2F , Y 1F 2T , Z 1F 2F }

Next, #3 said that #1 and #2 are not both dabs; that is, they're not both false. So...

{ X 1T 2F 3T , Y 1F 2T 3T , Z 1F 2F 3F }

#4 said that either #1 is False or #2 is True. I'm assuming that #4's statement would be true if both #1 is False and #2 is True; correct me if I'm wrong about that. Anyway, the possibilities are

{ X 1T 2F 3T 4F , Y 1F 2T 3T 4T , Z 1F 2F 3F 4T }

Finally, #5 made a self-referential statement, so I'll take a little longer with that one and consider each of the three possibilities above and whether #5 could be True or False with each of them. First, if X is the right map:

X 1T 2F 3T 4F 5T means that either #3 = #4 or 5F, neither of which works

X 1T 2F 3T 4F 5F means that both #3 not = #4 and 5T, the last part means this doesn't work

Now if Y is the right map:

Y 1F 2T 3T 4T 5T means that either #3 = #4 or 5F. This works because #3 does = #4

Y 1F 2T 3T 4T 5F means that both #3 not = #4 and 5T, neither of which works

And if Z is the right map:

Z 1F 2F 3F 4T 5T means that either #3 = #4 or 5F, neither of which works

Z 1F 2F 3F 4T 5F means that both #3 not = #4 and 5T, the last part means this doesn't work

So the only answer that works is Y 1F 2T 3T 4T 5T, and Y is the right map.

[Guest]

You are an explorer hoping to find your way to the coast of an island. You have three maps, X, Y, Z. One was true, two were false. There were five natives, of the two tribes. The Doog always told the truth. The Dab always told lies. They gave him the following advice.

1. X is the correct map.

2. Y is the correct map.

3. 1 and 2 are not both Dabs.

4. Either 1 is a Dab or 2 is a Doog.

5. Either I am a Dab or 3 and 4 are of the same type.(That is both Doogs or both Dabs)

Which Map is the correct map?

Okay so this puzzle cannot be solved my reasoning is this

If 5 (and it must be because it is a paradox otherwise) is true 3 and 4 contradict whether false or true

meaning 1 and 2 can be neither true nor false else they conflict with 3 and 4

(if 3 is false 1 and 2 conflict with 4 also being false)

(if 3 is true 4 makes 1 and 2 conflict with the puzzle stating that there is only one correct map)

this makes Z an impossibility also because at least one statement must be from the Doog tribe else the puzzle is false

all of this is on the assumption that 5 is true (BUT 5 HAS TO BE TRUE or else the Doog is lying and the Dab is telling the truth)

But if 5 were false then 3 is true and X is the correct map

Edited April 5, 2009 by Raine

[Guest]

You are an explorer hoping to find your way to the coast of an island. You have three maps, X, Y, Z. One was true, two were false. There were five natives, of the two tribes. The Doog always told the truth. The Dab always told lies. They gave him the following advice.

1. X is the correct map.

2. Y is the correct map.

3. 1 and 2 are not both Dabs.

4. Either 1 is a Dab or 2 is a Doog.

5. Either I am a Dab or 3 and 4 are of the same type.(That is both Doogs or both Dabs)

Which Map is the correct map?

Y is the correct map. Working backwards, number 5 must be a Doog. If he was a Dab, the statement \"I am a Dab\" would be true and that would imply that he was a Doog. So since 5 is a Doog, the second part of his statement is true... that 3 and 4 are of the same type.

Lets assume that 3 and 4 are Dabs. Will it make sense? That means 3\'s statements is false: \"1 and 2 ARE both Dabs\". Well that means Z would be the correct map. But then 4 has to be a Dab too. If 4 was a Dab, his statement would be \"1 is a Doog and 2 is a Dab\". Well that contradicts 3 where he says that they are both Dabs.

So since 3 and 4 are obviously not Dabs, they are Doogs. A quick check confirms this. 3 says \"1 and 2 are not both Dabs\" so either X or Y is the correct map. Then 4 says that \"1 is a dab and 2 is a Doog\". So 2 is also a Doog and therefore Y is the correct map.

Edited April 5, 2009 by James T

[Guest]

First- re:Assassinator post: "why not??"

The goal is to figure out which map is correct. If the goal were to get to your destination of "the coast"; your on an island, pick a direction and walk straight.

Second:

I agree with Raine, I believe the puzzle to be a paradox.

My reasoning:

notation:

T = statement is true, speaker is a Doog

F = statement is false, speaker is a Dab

So according to the set up one and only one of the maps is correct.

So after evaluating statements #1 and #2 it just so happens we end up with 3 possibilities each corresponding to a map, I'll label them according to the map they indicate.

___| X | Y | Z |

-----------------

#1 | T | F | F |

#2 | F | T | F |

"3. 1 and 2 are not both Dabs." which gives us the following:

___| X | Y | Z |

-----------------

#1 | T | F | F |

#2 | F | T | F |

#3 | T | T | F |

#4 is the Key statement: "4. Either 1 is a Dab or 2 is a Doog." Either/or not both. (to Admin: I hope this doesn't fall under "5. Nit-picking about wording" the wording seems clear to me. Let me know if I'm wrong) So that gives us the following:

___| X | Y | Z |

-----------------

#1 | T | F | F |

#2 | F | T | F |

#3 | T | T | F |

#4 | F | F | T |

"5. Either I am a Dab or 3 and 4 are of the same type.(That is both Doogs or both Dabs)" As many have pointed out 3 and 4 have to be the same type or #5 is a paradox. Since 3 and 4 cannot be the same type #5 is a paradox. Even if you allow a Dab to state a paradox (different conversation) you don't have enough information to solve the puzzle.

So you throw away all three maps, pick a direction and walk because you destination is "the coast" and you are on an island.

Edited April 5, 2009 by the_Utilitariat

[Guest]

5 cannot be that you are a dab, otherwise the entire riddle cannot be trusted. If that is the case then the answer to the riddle is as follows:

Three and four are of the same type. Furthermore three and four cannot both be dab, because if they were, it would be impossible to determine the correct map, thus three and four must be doog statements. If three and four are doog statements, then 2 must be a doog statement.

Y is the correct map.

[Guest]

You are an explorer hoping to find your way to the coast of an island. You have three maps, X, Y, Z. One was true, two were false. There were five natives, of the two tribes. The Doog always told the truth. The Dab always told lies. They gave him the following advice.

1. X is the correct map.

2. Y is the correct map.

3. 1 and 2 are not both Dabs.

4. Either 1 is a Dab or 2 is a Doog.

5. Either I am a Dab or 3 and 4 are of the same type.(That is both Doogs or both Dabs)

Thanks for the great brain teaser! The correct map is Z.

5 is not a paradox. The speaker is a Doog and 3 and 4 are of the same type, both Dabs. 4 is untrue because both are Dabs. Since 3 is a Dab, then both 1 and 2 are untrue. This means Z is the correct map.

[Guest]

Some responders seem to have forgotten that the five statements were made by five different natives belonging to the two tribes. Of the five, only #5 was a Doog. The rest were Dabs.

[Guest]

I withdraw my previous answer. The correct answer is Y

I made an error earlier. #4 cannot be untrue because of the word "either."

#5 cannot be spoken by a Dab. If it was, the Dab would be telling the truth and that cannot happen. This means 3 and 4 are of the same type. 3 and 4 are both Doogs. #4 is the tough one because of the word "either." Strictly speaking you can say "either" when both statements are true. They do not both have to be true but they can be. So the correct answer is Y.

[Guest]

There is no true answer to his riddle because there isn't enough information given and with what information we have all 3 maps have a possibility of being correct, the only true way of finding out which map is correct is to use a compass and other items used to realistically test this. There is no true answer because all 3 maps have a possibility of being correct based on how you order the combination.

Now that there is a possibility that means that all three maps can be correct they all can be of different islands that have the same geological area and measurements, saying this because I'm going into possibilities, so all three could be correct except for small differences that would make one map the "true" map for that island and the others the "false" islands by those small differences.

Also i went back to check the question, and this is a pointless riddle, the explorer is already at the coast of the island the question states that "You have three maps, X, Y, Z. One was true, two were false.", the "was" and "were" means that you already know which ones were right and wrong and that you have already reached the coast because you knew which one was correct.

There is no correct answer because the explorer is already at the coast.

That or he/she is blind.

[Guest]

All those that say it is "unsolveable". It can be solved, for I have done it

[Guest]

Interesting, doog and dab are backwards for good and bad.

I came up with a different solution than reaymond, but that's because we had different interpretations of #4's statement. If BOTH 1 is a dab and 2 is a doog, is #4's satement true? I said yes, reaymond said no, so we're probably both correct depending on how you interpret it.

This is going to be a long explanation, but I'm going to explain a way to approach these problems in general that helps me make sure I'm not leaving anything out. First off, we know that one of the three maps is true and the rest are false. I'll denote the three possible situations as

{ X , Y , Z }

Person 1 made a statement that is either true or false. Before I start considering what he actually said, I'll just say that for each of the three possibilities above, #1 might have been either been True or False, giving the possible combinations of

{ X 1T , X 1F , Y 1T , Y 1F , Z 1T , Z 1F }

Now since #1 said that X is the correct map, we can clearly get rid of X 1F , Y 1T , & Z 1T so we're left with

{ X 1T , Y 1F , Z 1F }

Now #2 said that Y is the correct map. Without much difficulty we can see that the possibilities are now

{ X 1T 2F , Y 1F 2T , Z 1F 2F }

Next, #3 said that #1 and #2 are not both dabs; that is, they're not both false. So...

{ X 1T 2F 3T , Y 1F 2T 3T , Z 1F 2F 3F }

#4 said that either #1 is False or #2 is True. I'm assuming that #4's statement would be true if both #1 is False and #2 is True; correct me if I'm wrong about that. Anyway, the possibilities are

{ X 1T 2F 3T 4F , Y 1F 2T 3T 4T , Z 1F 2F 3F 4T }

Finally, #5 made a self-referential statement, so I'll take a little longer with that one and consider each of the three possibilities above and whether #5 could be True or False with each of them. First, if X is the right map:

X 1T 2F 3T 4F 5T means that either #3 = #4 or 5F, neither of which works

X 1T 2F 3T 4F 5F means that both #3 not = #4 and 5T, the last part means this doesn't work

Now if Y is the right map:

Y 1F 2T 3T 4T 5T means that either #3 = #4 or 5F. This works because #3 does = #4

Y 1F 2T 3T 4T 5F means that both #3 not = #4 and 5T, neither of which works

And if Z is the right map:

Z 1F 2F 3F 4T 5T means that either #3 = #4 or 5F, neither of which works

Z 1F 2F 3F 4T 5F means that both #3 not = #4 and 5T, the last part means this doesn't work

So the only answer that works is Y 1F 2T 3T 4T 5T, and Y is the right map.

you were right it is Y

[Guest]

Well, even assuming the most open boolean logic (meaning or can mean both cases true - as opposed to human or's), there is only one solution:

Y is the correct map.

1. X is the correct map.

2. Y is the correct map.

3. 1 and 2 are not both Dabs.

4. Either 1 is a Dab or 2 is a Doog.

5. Either I am a Dab or 3 and 4 are of the same type.(That is both Doogs or both Dabs)

Native #5 must be a Doog. If he was a Dab he should be lying, but then "Either I am a Dab..." would be true.

Native #3 and #4 are then either both Doogs or both Dabs. They cannot both be lying because if 3 is lying, then #1 and #2 are both Dabs, but then #4 would be telling the truth. Since they must be of the same tribe, they can only be Doogs.

Since we now know that #3, and #4 are both telling the truth, the rest is a simple elimination of possibilities:

1=Dab, 2=Dab : Not possible because of statement 3

1=Dab, 2=Doog : Possible

1=Doog, 2=Dab : Not possible because of statement 4

1=Doog, 2=Doog : Not possible since there is only 1 correct map.

Hence, native #2 is a Doog, and therefore telling the truth - Map Y is the correct map.

Edit:

I said "Well, even assuming the most open boolean logic..."

I should have said: "Only by assuming the most open boolean logic..."

Nice puzzle, Cistone.

Edited April 5, 2009 by uhre

[Guest]

Well, even assuming the most open boolean logic (meaning or can mean both cases true - as opposed to human or's), there is only one solution:

Y is the correct map.

1. X is the correct map.

2. Y is the correct map.

3. 1 and 2 are not both Dabs.

4. Either 1 is a Dab or 2 is a Doog.

5. Either I am a Dab or 3 and 4 are of the same type.(That is both Doogs or both Dabs)

Native #5 must be a Doog. If he was a Dab he should be lying, but then "Either I am a Dab..." would be true.

Native #3 and #4 are then either both Doogs or both Dabs. They cannot both be lying because if 3 is lying, then #1 and #2 are both Dabs, but then #4 would be telling the truth. Since they must be of the same tribe, they can only be Doogs.

Since we now know that #3, and #4 are both telling the truth, the rest is a simple elimination of possibilities:

1=Dab, 2=Dab : Not possible because of statement 3

1=Dab, 2=Doog : Possible

1=Doog, 2=Dab : Not possible because of statement 4

1=Doog, 2=Doog : Not possible since there is only 1 correct map.

Hence, native #2 is a Doog, and therefore telling the truth - Map Y is the correct map.