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Alex's revenge, maybe...

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Alex thought hard before going to Morty's last night after

losing bets two nights in a row.

But go he did, and with an extra swagger, because he had

come up with a challenge that he felt sure no one could meet.

You know those number series, like 1, 4, 9, 16, 25 ...

and the like? he asked, talking to no one in particular.

Well all the ones I've seen are like child's play. Last night

I come up with some numbers that none of ya here can

figure out - not in a month of Sundays.

Then grinning he added, But if anyone should be clever

enough, I'll buy him drinks for a month.

Davey appeared interested and sauntered over. Alex took

out a crumpled sheet of paper and handed it to him. On

it were scrawled, in Alex's dirty red ink, these numbers:

4, 5, 8, 8, 9, 9, 12, 13, 13, 13, 17, 18, ...

Ya see them numbers, do ya? Well, they just go on forever, they

do. And if ya figure out what they are, you'll be able to tell me the

50th, 63rd and 100th terms. And that's what it'll take to win.

With that, he sauntered over to shoot darts with Jamie - but not

before hollering back, Oh, and tell writersblock he's welcome to

give it a try, too.

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Posted · Report post

Hmmm. This one has me stumped... for now.

A question: if we are to give the 50th, 63rd, and 100th terms, are we to assume that the terms given are 1-12 consecutively?

Also, if there are terms stretching to the 100th term, can we safely assume that the sequence is mathmatical in nature and not based on some other finite criterion? I assume it from this

Well, they just go on forever, they

do.

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Posted · Report post

Is the 50th term 43?

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Posted · Report post

Hmmm. This one has me stumped... for now. <!-- s:mrgreen: --><!-- s:mrgreen: -->

A question: if we are to give the 50th, 63rd, and 100th terms, are we to assume that the terms given are 1-12 consecutively?

Also, if there are terms stretching to the 100th term, can we safely assume that the sequence is mathmatical in nature and not based on some other finite criterion? I assume it from this

Well, they just go on forever, they do.

There is a one to one correspondence between the terms in the sequence and the positive integers.

The numbers given correspond to the numbers 1-12.

Is the 50th term 43?
No.

But this may be helpful:

terms 49 and 51 are respectively 58 and 59

terms 62 and 64 are respectively 70 and 73

terms 99 and 101 are respectively 109 and 114

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Posted · Report post

Wow, I capitulate on this one. I can't find any logical connection that make the numbers a sequence.

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Posted · Report post

I think I have it

The 50th term is 55

The 63rd term is 73

The 100th term is 110

Am I right?

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Posted · Report post

If you are, post the reasoning. I couldn't see this one.

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Posted · Report post

I think I have it

The 50th term is 55

The 63rd term is 73

The 100th term is 110

Am I right?

Bartender, pour the man a cold lager.

Wait. Pour him 31 lagers.

subtract N from the Nth term.

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Posted (edited) · Report post

Bartender, pour the man a cold lager.

Wait. Pour him 31 lagers.

subtact N from the Nth term.

ok, so 0-0 =0

1-1 = 0

...

So the series, according to "subtract N from the Nth term" is 0,0,0,0,0,0,0...

Can you post the real formula to calculate the sequence please? This one doesn't make any sense...

d-

Edited by DouglasABaker
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Posted · Report post

ok, so 0-0 =0

1-1 = 0

...

So the series, according to "subtract N from the Nth term" is 0,0,0,0,0,0,0...

Can you post the real formula to calculate the sequence please? This one doesn't make any sense...

d-

The suggestion of subtracting N from the Nth term was a clue.

If you do it, you generate the third column in the following table.

Can you relate the numbers in the third column to N?

If you can, you've solved the puzzle.

N   Nth term [Nth term]-N
= ======== ============
1 4 3
2 5 3
3 8 5
4 8 4
5 9 4
6 9 3
7 12 5
8 13 5
9 13 4
10 13 3
11 17 6
12 18 6
-- -- -
49 58 9
50 55 5
51 59 8
-- -- -
62 70 8
63 73 10
64 73 9
-- -- -
99 109 10
100 110 10
101 114 13[/code]

Edit to remove spoiler for a day or two...

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Posted · Report post

Wow, that's really tricky... even with the code, it took me several minutes to figure out:P

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Posted · Report post

Help, I've been staring at this one for hours and still can't find the relationship between "N" and the "(Nth term) - N".

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Posted · Report post

1 = 3

2 = 3

3 = 5

...

wait

one = 3

two = 3

three = 5

four = 4

....

fifty = 5

...

sixtythree = 10

...

onehundred = 10

...

1 3+1 = 4

2 3+2 = 5

3 5+3 = 8

...

50 5+50 = 55

63 63+10 = 73

100 10+100 = 110

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Posted (edited) · Report post

The suggestion of subtracting N from the Nth term was a clue.

If you do it, you generate the third column in the following table.

Can you relate the numbers in the third column to N?

If you can, you've solved the puzzle.

N   Nth term [Nth term]-N

=   ======== ============

1	   4		 3

2	   5		 3

3	   8		 5

4	   8		 4

5	   9		 4

6	   9		 3

7	  12		 5

8	  13		 5

9	  13		 4

10	 13		 3

11	 17		 6

12	 18		 6

--	 --		 -

49	 58		 9

50	 55		 5

51	 59		 8

--	 --		 -

62	 70		 8

63	 73		10

64	 73		 9

--	 --		 -

99	109		10

100   110		10

101   114		13

Edit to remove spoiler for a day or two...

I got it, brill.

it is xth+n where xth is the number of letters of n, so one is 3, o.n.e. and this + 1 = 4, two is 3, +2 =5, three is 5, +3 = 8, so term sixty three is 63+10=73, term one hundred is 100+10 =110, and the term fifty is 50+5=55, so any term is easy to get.

Edited by munkifisht
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Posted · Report post

1 = 3

2 = 3

3 = 5

...

wait

one = 3

two = 3

three = 5

four = 4

....

fifty = 5

...

sixtythree = 10

...

onehundred = 10

...

1 3+1 = 4

2 3+2 = 5

3 5+3 = 8

...

50 5+50 = 55

63 63+10 = 73

100 10+100 = 110

Sorry, I bit confused in the first part, well till 12th u derived that 18-12=6, how did u derive at 50th->5

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Posted · Report post

Sorry, I bit confused in the first part, well till 12th u derived that 18-12=6, how did u derive at 50th->5

The 50th term is 55.

Their difference is 5 = the number of letters in the word "fifty".

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Posted · Report post

Yeah, you can make the explanation much simpler:

Add the number of characters in the text version of the number to the number itself:

"Fifty" is five (5) characters, plus 50 (the number) = 55.

"Sixty Three": 10 characters + 63 = 73

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Posted (edited) · Report post

Is it possible that you have not gone further than 100 for a reason?

nine hundred and ninety nine thousand nine hundred and ninety nine.

What would you make of that using the same formula?

1.000.015

Back to our friend zero me thinks

Lost in ?????

Edited by Lost in space
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Posted (edited) · Report post

Ok i did some number crunching and realized the pattern is something like this

-2, +3, -1, +1, -3, +2, -(-1), +0, -(-4),etc Also it is like this...

-2, +3, -1, +1, -3, +2, -(-1), +0, -(-4),

I...........I..........I...........I..............I

+1 -2 +4 +3

I dont know what it means though...

(LOL i just went up and read the answer. I was SOOOOOOOOOOO off.)

Edited by Sharpshark
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Posted · Report post

:mellow::P <_< its too hard.
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Is it possible that you have not gone further than 100 for a reason?

nine hundred and ninety nine thousand nine hundred and ninety nine.

What would you make of that using the same formula?

1.000.015

Back to our friend zero me thinks

Lost in ?????

Careful, the word "and" is only used when indicating a decimal point.

Nine hundred ninety nine thousand nine hundred ninety nine would either be:

1,000,049 (excluding spaces)

1,000,057 (including spaces)

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Posted · Report post

I can see where you are coming from, but can you explain the solution again please? :huh:

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I can see where you are coming from, but can you explain the solution again please? :huh:
Add the letter-length to the value of the number.

For the 50th term you get f-i-f-t-y [5 letters] + 50 [value] = 55

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The correct answers are 55, 73 and 110

How do you GET those answers?

Easy.

The first number in the series is 4

You get 4 by counting the letters in the number O-N-E and adding them to the value of the number.

Three letters in the word ONE plus the value of ONE = 3+1 = 4

The next number in the series is 5

T-W-O = 3 plus the value of 2 = 5

The next number is 8

T-H-R-E-E = 5 plus the value of 5 = 8

And so on, and so on, and so on

Really quite simple.

Fifty = 5+50 = 55

Sixty Three = 10+63 = 73

One Hundred = 10 + 100 = 110

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Careful, the word "and" is only used when indicating a decimal point.

Nine hundred ninety nine thousand nine hundred ninety nine would either be:

1,000,049 (excluding spaces)

1,000,057 (including spaces)

AND when you write numbers into words on cheques/checks is it not?

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Posted (edited) · Report post

You just take the number of letters in the written form of it added to the actual numerical value. 100 is 110

(o-n-e-h-u-n-d-r-e-d (10) +100)

50 is 55 and 63 is 73 (f-i-f-t-y(5)+50 and s-i-x-t-y-t-h-r-e-e (10)+50

wow I knew the answer just by looking at it for one minute somehow. I am amazed at myself.

How come no one used spoilers ( now that I look back at other people's answers)

?

Edited by phil
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