bonanova Posted October 14, 2007 Report Share Posted October 14, 2007 Alex thought hard before going to Morty's last night after losing bets two nights in a row. But go he did, and with an extra swagger, because he had come up with a challenge that he felt sure no one could meet. You know those number series, like 1, 4, 9, 16, 25 ... and the like? he asked, talking to no one in particular. Well all the ones I've seen are like child's play. Last night I come up with some numbers that none of ya here can figure out - not in a month of Sundays. Then grinning he added, But if anyone should be clever enough, I'll buy him drinks for a month. Davey appeared interested and sauntered over. Alex took out a crumpled sheet of paper and handed it to him. On it were scrawled, in Alex's dirty red ink, these numbers: 4, 5, 8, 8, 9, 9, 12, 13, 13, 13, 17, 18, ... Ya see them numbers, do ya? Well, they just go on forever, they do. And if ya figure out what they are, you'll be able to tell me the 50th, 63rd and 100th terms. And that's what it'll take to win. With that, he sauntered over to shoot darts with Jamie - but not before hollering back, Oh, and tell writersblock he's welcome to give it a try, too. Quote Link to comment Share on other sites More sharing options...
0 Guest Posted October 14, 2007 Report Share Posted October 14, 2007 Hmmm. This one has me stumped... for now. A question: if we are to give the 50th, 63rd, and 100th terms, are we to assume that the terms given are 1-12 consecutively? Also, if there are terms stretching to the 100th term, can we safely assume that the sequence is mathmatical in nature and not based on some other finite criterion? I assume it from this Well, they just go on forever, they do. Quote Link to comment Share on other sites More sharing options...
0 Guest Posted October 14, 2007 Report Share Posted October 14, 2007 Is the 50th term 43? Quote Link to comment Share on other sites More sharing options...
0 bonanova Posted October 15, 2007 Author Report Share Posted October 15, 2007 Hmmm. This one has me stumped... for now. <!-- s:mrgreen: --><!-- s:mrgreen: --> A question: if we are to give the 50th, 63rd, and 100th terms, are we to assume that the terms given are 1-12 consecutively? Also, if there are terms stretching to the 100th term, can we safely assume that the sequence is mathmatical in nature and not based on some other finite criterion? I assume it from this Well, they just go on forever, they do. There is a one to one correspondence between the terms in the sequence and the positive integers. The numbers given correspond to the numbers 1-12. Is the 50th term 43? No. But this may be helpful: terms 49 and 51 are respectively 58 and 59 terms 62 and 64 are respectively 70 and 73 terms 99 and 101 are respectively 109 and 114 Quote Link to comment Share on other sites More sharing options...
0 Guest Posted October 16, 2007 Report Share Posted October 16, 2007 Wow, I capitulate on this one. I can't find any logical connection that make the numbers a sequence. Quote Link to comment Share on other sites More sharing options...
0 Guest Posted October 16, 2007 Report Share Posted October 16, 2007 I think I have it The 50th term is 55 The 63rd term is 73 The 100th term is 110 Am I right? Quote Link to comment Share on other sites More sharing options...
0 Guest Posted October 16, 2007 Report Share Posted October 16, 2007 If you are, post the reasoning. I couldn't see this one. Quote Link to comment Share on other sites More sharing options...
0 bonanova Posted October 16, 2007 Author Report Share Posted October 16, 2007 I think I have it The 50th term is 55 The 63rd term is 73 The 100th term is 110 Am I right? Bartender, pour the man a cold lager. Wait. Pour him 31 lagers.subtract N from the Nth term. Quote Link to comment Share on other sites More sharing options...
0 Guest Posted January 16, 2008 Report Share Posted January 16, 2008 (edited) Bartender, pour the man a cold lager. Wait. Pour him 31 lagers. subtact N from the Nth term. ok, so 0-0 =0 1-1 = 0 ... So the series, according to "subtract N from the Nth term" is 0,0,0,0,0,0,0... Can you post the real formula to calculate the sequence please? This one doesn't make any sense... d- Edited January 16, 2008 by DouglasABaker Quote Link to comment Share on other sites More sharing options...
0 bonanova Posted January 16, 2008 Author Report Share Posted January 16, 2008 ok, so 0-0 =0 1-1 = 0 ... So the series, according to "subtract N from the Nth term" is 0,0,0,0,0,0,0... Can you post the real formula to calculate the sequence please? This one doesn't make any sense... d- The suggestion of subtracting N from the Nth term was a clue. If you do it, you generate the third column in the following table. Can you relate the numbers in the third column to N? If you can, you've solved the puzzle. N Nth term [Nth term]-N = ======== ============ 1 4 3 2 5 3 3 8 5 4 8 4 5 9 4 6 9 3 7 12 5 8 13 5 9 13 4 10 13 3 11 17 6 12 18 6 -- -- - 49 58 9 50 55 5 51 59 8 -- -- - 62 70 8 63 73 10 64 73 9 -- -- - 99 109 10 100 110 10 101 114 13[/code] Edit to remove spoiler for a day or two... Quote Link to comment Share on other sites More sharing options...
0 Guest Posted January 17, 2008 Report Share Posted January 17, 2008 Wow, that's really tricky... even with the code, it took me several minutes to figure out:P Quote Link to comment Share on other sites More sharing options...
0 Guest Posted February 21, 2008 Report Share Posted February 21, 2008 Help, I've been staring at this one for hours and still can't find the relationship between "N" and the "(Nth term) - N". Quote Link to comment Share on other sites More sharing options...
0 Guest Posted February 21, 2008 Report Share Posted February 21, 2008 1 = 3 2 = 3 3 = 5 ... wait one = 3 two = 3 three = 5 four = 4 .... fifty = 5 ... sixtythree = 10 ... onehundred = 10 ... 1 3+1 = 4 2 3+2 = 5 3 5+3 = 8 ... 50 5+50 = 55 63 63+10 = 73 100 10+100 = 110 Quote Link to comment Share on other sites More sharing options...
0 Guest Posted March 3, 2008 Report Share Posted March 3, 2008 (edited) The suggestion of subtracting N from the Nth term was a clue. If you do it, you generate the third column in the following table. Can you relate the numbers in the third column to N? If you can, you've solved the puzzle. N Nth term [Nth term]-N = ======== ============ 1 4 3 2 5 3 3 8 5 4 8 4 5 9 4 6 9 3 7 12 5 8 13 5 9 13 4 10 13 3 11 17 6 12 18 6 -- -- - 49 58 9 50 55 5 51 59 8 -- -- - 62 70 8 63 73 10 64 73 9 -- -- - 99 109 10 100 110 10 101 114 13 Edit to remove spoiler for a day or two... I got it, brill. it is xth+n where xth is the number of letters of n, so one is 3, o.n.e. and this + 1 = 4, two is 3, +2 =5, three is 5, +3 = 8, so term sixty three is 63+10=73, term one hundred is 100+10 =110, and the term fifty is 50+5=55, so any term is easy to get. Edited March 3, 2008 by munkifisht Quote Link to comment Share on other sites More sharing options...
0 Guest Posted March 15, 2008 Report Share Posted March 15, 2008 1 = 3 2 = 3 3 = 5 ... wait one = 3 two = 3 three = 5 four = 4 .... fifty = 5 ... sixtythree = 10 ... onehundred = 10 ... 1 3+1 = 4 2 3+2 = 5 3 5+3 = 8 ... 50 5+50 = 55 63 63+10 = 73 100 10+100 = 110 Sorry, I bit confused in the first part, well till 12th u derived that 18-12=6, how did u derive at 50th->5 Quote Link to comment Share on other sites More sharing options...
0 bonanova Posted March 15, 2008 Author Report Share Posted March 15, 2008 Sorry, I bit confused in the first part, well till 12th u derived that 18-12=6, how did u derive at 50th->5 The 50th term is 55. Their difference is 5 = the number of letters in the word "fifty". Quote Link to comment Share on other sites More sharing options...
0 Guest Posted March 17, 2008 Report Share Posted March 17, 2008 Yeah, you can make the explanation much simpler: Add the number of characters in the text version of the number to the number itself: "Fifty" is five (5) characters, plus 50 (the number) = 55. "Sixty Three": 10 characters + 63 = 73 Quote Link to comment Share on other sites More sharing options...
0 Guest Posted March 17, 2008 Report Share Posted March 17, 2008 (edited) Is it possible that you have not gone further than 100 for a reason? nine hundred and ninety nine thousand nine hundred and ninety nine. What would you make of that using the same formula? 1.000.015 Back to our friend zero me thinks Lost in ????? Edited March 17, 2008 by Lost in space Quote Link to comment Share on other sites More sharing options...
0 Guest Posted March 29, 2008 Report Share Posted March 29, 2008 (edited) Ok i did some number crunching and realized the pattern is something like this -2, +3, -1, +1, -3, +2, -(-1), +0, -(-4),etc Also it is like this... -2, +3, -1, +1, -3, +2, -(-1), +0, -(-4), I...........I..........I...........I..............I +1 -2 +4 +3 I dont know what it means though... (LOL i just went up and read the answer. I was SOOOOOOOOOOO off.) Edited March 29, 2008 by Sharpshark Quote Link to comment Share on other sites More sharing options...
0 akaslickster Posted April 5, 2008 Report Share Posted April 5, 2008 <_< its too hard. Quote Link to comment Share on other sites More sharing options...
0 Guest Posted April 11, 2008 Report Share Posted April 11, 2008 Is it possible that you have not gone further than 100 for a reason? nine hundred and ninety nine thousand nine hundred and ninety nine. What would you make of that using the same formula? 1.000.015 Back to our friend zero me thinks Lost in ????? Careful, the word "and" is only used when indicating a decimal point. Nine hundred ninety nine thousand nine hundred ninety nine would either be: 1,000,049 (excluding spaces) 1,000,057 (including spaces) Quote Link to comment Share on other sites More sharing options...
0 Guest Posted April 11, 2008 Report Share Posted April 11, 2008 I can see where you are coming from, but can you explain the solution again please? Quote Link to comment Share on other sites More sharing options...
0 bonanova Posted April 11, 2008 Author Report Share Posted April 11, 2008 I can see where you are coming from, but can you explain the solution again please? Add the letter-length to the value of the number. For the 50th term you get f-i-f-t-y [5 letters] + 50 [value] = 55 Quote Link to comment Share on other sites More sharing options...
0 Guest Posted April 17, 2008 Report Share Posted April 17, 2008 The correct answers are 55, 73 and 110 How do you GET those answers? Easy. The first number in the series is 4 You get 4 by counting the letters in the number O-N-E and adding them to the value of the number. Three letters in the word ONE plus the value of ONE = 3+1 = 4 The next number in the series is 5 T-W-O = 3 plus the value of 2 = 5 The next number is 8 T-H-R-E-E = 5 plus the value of 5 = 8 And so on, and so on, and so on Really quite simple. Fifty = 5+50 = 55 Sixty Three = 10+63 = 73 One Hundred = 10 + 100 = 110 Quote Link to comment Share on other sites More sharing options...
0 Guest Posted April 17, 2008 Report Share Posted April 17, 2008 Careful, the word "and" is only used when indicating a decimal point. Nine hundred ninety nine thousand nine hundred ninety nine would either be: 1,000,049 (excluding spaces) 1,000,057 (including spaces) AND when you write numbers into words on cheques/checks is it not? Quote Link to comment Share on other sites More sharing options...
0 Guest Posted December 18, 2008 Report Share Posted December 18, 2008 (edited) You just take the number of letters in the written form of it added to the actual numerical value. 100 is 110 (o-n-e-h-u-n-d-r-e-d (10) +100) 50 is 55 and 63 is 73 (f-i-f-t-y(5)+50 and s-i-x-t-y-t-h-r-e-e (10)+50 wow I knew the answer just by looking at it for one minute somehow. I am amazed at myself. How come no one used spoilers ( now that I look back at other people's answers) ? Edited December 18, 2008 by phil Quote Link to comment Share on other sites More sharing options...
Question
bonanova
Alex thought hard before going to Morty's last night after
losing bets two nights in a row.
But go he did, and with an extra swagger, because he had
come up with a challenge that he felt sure no one could meet.
You know those number series, like 1, 4, 9, 16, 25 ...
and the like? he asked, talking to no one in particular.
Well all the ones I've seen are like child's play. Last night
I come up with some numbers that none of ya here can
figure out - not in a month of Sundays.
Then grinning he added, But if anyone should be clever
enough, I'll buy him drinks for a month.
Davey appeared interested and sauntered over. Alex took
out a crumpled sheet of paper and handed it to him. On
it were scrawled, in Alex's dirty red ink, these numbers:
4, 5, 8, 8, 9, 9, 12, 13, 13, 13, 17, 18, ...
Ya see them numbers, do ya? Well, they just go on forever, they
do. And if ya figure out what they are, you'll be able to tell me the
50th, 63rd and 100th terms. And that's what it'll take to win.
With that, he sauntered over to shoot darts with Jamie - but not
before hollering back, Oh, and tell writersblock he's welcome to
give it a try, too.
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