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so i don't know the answer to this but i have been reading some things on this site so i thought i would join and ask you guys.

we have done quite a few puzzles in the past but they were easier lol so here goes

X+Y

X+Z

XY-YZ+Y

thats it, nothing else

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Whats the question?

if you want to set it equal to zero you can use a system.

From the system you could solve one in terms of the other.

X+Y=0 Y=-X, X=-Y

X+Z=0 X=-Z, Z=-X

XY-YZ+Y=0

(-Z)Y-YZ+Y=0 (-ZY-YZ)= -2YZ+Y=0 Z=(-Y)/(-2Y) Z=1/2

Plug it in and get:

X=-Z, X=-1/2

Y=-X, Y=1/2

Y+X=0, -1/2 + 1/2 =0

X+Z=0, -1/2 + 1/2 =0

XY-ZY+Y=0,

(-1/2)(1/2)= -.25

(1/2)(1/2)=.25

(-.25)-(.25)+.5=0

but that's only valid if you want it equal to zero, if it is asking a different question that i have no clue.

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Whats the question?

if you want to set it equal to zero you can use a system.

From the system you could solve one in terms of the other.

X+Y=0 Y=-X, X=-Y

X+Z=0 X=-Z, Z=-X

XY-YZ+Y=0

(-Z)Y-YZ+Y=0 (-ZY-YZ)= -2YZ+Y=0 Z=(-Y)/(-2Y) Z=1/2

Plug it in and get:

X=-Z, X=-1/2

Y=-X, Y=1/2

Y+X=0, -1/2 + 1/2 =0

X+Z=0, -1/2 + 1/2 =0

XY-ZY+Y=0,

(-1/2)(1/2)= -.25

(1/2)(1/2)=.25

(-.25)-(.25)+.5=0

but that's only valid if you want it equal to zero, if it is asking a different question that i have no clue.

x=y=z=0

See that by inspection or note x=-y, z=y and

y[x-z+1] = 0

y[1-2y]=0

So either y=0 or y=1/2.

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