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I'm not sure if this has been posted before but...here goes!

A community is home to 500 people. The annual community dance just ended last night. The cost of a ticket for a new member is 20 dollars, while the cost of a ticket for longtime memebers is only 14 dollars. All of the longtime members attended the dance, but only 70% of the new members attended.

How much money did the dance staff rake in last night?

7,000 dollars. I'll let you figure out how. It's not that difficult :]

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I'm not sure if this has been posted before but...here goes!

A community is home to 500 people. The annual community dance just ended last night. The cost of a ticket for a new member is 20 dollars, while the cost of a ticket for longtime memebers is only 14 dollars. All of the longtime members attended the dance, but only 70% of the new members attended.

How much money did the dance staff rake in last night?

7,000 dollars. I'll let you figure out how. It's not that difficult :]

Nice riddle, but in future don't write the answer down let us figure it out!!!

Welcome to the Den! :)

Edited by andromeda
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Nice riddle, but in future don't write the answer down let us figure it out!!!

Welcome to the Den! :)

That's why the answer's in a spoiler...So you can still figure it out...Just don't look at the spoiler. That's how a good majority of the puzzles are done. With the puzzle and the answer in the same post but the answer is in a spoiler.

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Taking it to the simplest way to find 70% is 7 out of 10.

Therefore, 7 of the 10 newcomers attended = $140.00

All of the 490 long time members attended = $6860.00

Total raised =$7000.00

You're so close, but I never said there were 10 newcomers and 490 longtimers.

How can you PROVE it is 7000 dollars?

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Taking it to the simplest way to find 70% is 7 out of 10.

Therefore, 7 of the 10 newcomers attended = $140.00

All of the 490 long time members attended = $6860.00

Total raised =$7000.00

How do you know there are only 10 newcomers???

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I'm not sure if this has been posted before but...here goes!

A community is home to 500 people. The annual community dance just ended last night. The cost of a ticket for a new member is 20 dollars, while the cost of a ticket for longtime memebers is only 14 dollars. All of the longtime members attended the dance, but only 70% of the new members attended.

How much money did the dance staff rake in last night?

7,000 dollars. I'll let you figure out how. It's not that difficult :]

its because

it doesent matter how many were new vs how many longtime

all longtime 500*14 = 7000

partial 300 longtime

(300 * 14) + (200 * 20) = 7000

this works with any ratio - try em all if you wish.

the only way this does not work is with a number of newcomers that cannot be evenly divided into 70%

While (492 * 14) + (8 * .7 * 20) does indeed equal 7000 8 * .7 comes to 5.6 so practically in that scenario it would need to be either 5 or 6 newcomers which does not come to 7000. but since the problem stated 70% we can assume that a perfect 70% of newcomers showed up.

Edited by preflop
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I think it's a proof by induction. It has something to do with the fact that 14/20 = 7/10 - If there are no new members and 100% of the people go, the dance brings in 7000 dollars, the same is true if there are 0 long time members and all new members. It also holds true for every number in between. Or maybe this is it:

Let x equal the number of new people in the community and 500 - x equal the long time members, if this is the case, it follows that:

.7(x)(20) + 14(500-x) = y;

14x + 7000 -14x = y (distributive property)

y = 7000. QED

I think that'll do it.

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