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it's what i said it was

i checked on calculator

unless..

maybe you weren't paying attention when you said the answer wasn't 0 or 5 and you meant to say it wasn't 0 or 7 because 5 is the last number in the question so it could be the real answer

Edited by lemonymelon
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7. every 5th power of 7 is seven. pattern=7 9 3 1 7 9 3 1 7...

the 7x7=49 x7=343x7=2401x7=16807x7=117649x7=823543x7=5764801 and so fourth out 25 times so it would be 9 see i even miss counted hahahaha

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but i stil reckon it's what i said originally

i checked with my calculator:

1341068619663964900807

i'm not so sure about my reasoning with the whole 5th power business being a bit silly there

but the 25th unit digit ought to be what i said, right?

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The answer is 7. The digits of the succesion of power of seven produce a periodical succesion which is:7,9,3,1,7,9,3,1... (7,49,343,2401...). Thus, the 25th element of such sucession is 7.

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It is 1341068619663964900807. I am surprised none of you solved it yet. The question was what is the last number in this sequence. The only way it would be 7 is if it was 'digit'.

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Easy way:

7^2 = 7*7 = 49 (ends with 9);

7^4 = 49*49 = A (ends with 1);

7^8 = A*A = B (ends in 1);

7^16 = B*B = C (ends in 1);

7^24 = B*C = D (ends in 1);

7^25 = D*7 = E (ends in 7);

Answer ends in 7.

Edit: I feel like such a tool for ending my lines in a semi colon after a Saturday evening coding session!

Edited by kingofpain
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It is 1341068619663964900807. I am surprised none of you solved it yet. The question was what is the last number in this sequence. The only way it would be 7 is if it was 'digit'.

thats interesting i wonder if thats what the OP meant

well its that or 7

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What is the last number in this math problem 7 to the 25th power

The Last digit is

7

That is because the last digit is cyclic in nature.

The last digits are

7^1, 7^5, 7^09, 7^13, 7^17, 7^21, 7^25 = 7

7^2, 7^6, 7^10, 7^14, 7^18, 7^22 = 9

7^3, 7^7, 7^11, 7^15, 7^19, 7^23 = 3

7^4, 7^8, 7^12, 7^16, 7^20, 7^24 = 1

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What is the last number in this math problem 7 to the 25th power

7

7^2 = 49 (2,6,10,14,18,22)

9 x 7 = 63 (3,7,11,15,19,23)

3 x 7 = 21 (4, 8,12,16,20,24)

1 x 7 = 7 (5,9,13,17,21,25)

7 x 7 = 49 ( ...

Edited by taliesin
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