BMAD Posted March 1, 2018 Report Share Posted March 1, 2018 Working with lengths that are whole units from 1 - 100, how many obtuse triangles can be formed? Quote Link to comment Share on other sites More sharing options...
0 Pickett Posted March 2, 2018 Report Share Posted March 2, 2018 ...a lot... Spoiler 131883 is the count I get. Quote Link to comment Share on other sites More sharing options...
0 bonanova Posted March 2, 2018 Report Share Posted March 2, 2018 I get fewer ... Spoiler 47308. To avoid double counting, I restricted a <= b <= c. I let a be in [1, 100] and b in [a, 100]. I then counted the integers c in [ sqrt {(a2)+(b2)}, a+b -1 ].I also noticed 52 right triangles (Pythagorean triples) . This is a plot of possible obtuse triangles for each value of a between 1 and 100. When a = 27 the number reaches a maximum of 1166. Quote Link to comment Share on other sites More sharing options...
0 bonanova Posted March 3, 2018 Report Share Posted March 3, 2018 Case by case results, inviting algorithm falsification, while limiting lengths to 10. Spoiler Rows: values of a; Columns: values of b; Elements: triangle counts. OBTUSE 10 0 0 0 0 0 0 0 0 0 0 0 1 1 1 1 1 1 1 1 0 0 0 1 1 2 2 2 2 1 0 0 0 0 2 2 2 2 2 1 0 0 0 0 0 2 3 2 1 0 0 0 0 0 0 0 2 1 0 0 0 0 0 0 0 0 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 Row sums (obtuse triangles for 10 values of a)0 8 11 11 8 3 1 0 0 0 <= showing no possible obtuse triangles when 2> a >7 Total triangles42 More matrices, for maximum lengths of 2-9: Spoiler OBTUSE 2 0 0 0 0 OBTUSE 3 0 0 0 0 1 0 0 0 0 OBTUSE 4 0 0 0 0 0 1 1 0 <= meaning a=b=2 permits (only) one obtuse triangle: c=3 0 0 0 0 0 0 0 0 OBTUSE 5 0 0 0 0 0 0 1 1 1 0 <= meaning a=2 b=4 permits (only) one obtuse triangle: c=5 0 0 1 0 0 <= showing that a=3 b=4 c=5 (right-)triangle was not counted 0 0 0 0 0 0 0 0 0 0 OBTUSE 6 0 0 0 0 0 0 0 1 1 1 1 0 <= counting (only) 223, 234, 245, 256 for a=2 0 0 1 1 1 0 <= indicating a=3 b=4 c=6 obtuse triangle (only) was counted; not c=5,7 0 0 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 OBTUSE 7 0 0 0 0 0 0 0 0 1 1 1 1 1 0 0 0 1 1 2 1 0 0 0 0 2 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 OBTUSE 8 0 0 0 0 0 0 0 0 0 1 1 1 1 1 1 0 0 0 1 1 2 2 1 0 0 0 0 2 2 1 0 0 0 0 0 0 1 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 OBTUSE 9 0 0 0 0 0 0 0 0 0 0 1 1 1 1 1 1 1 0 0 0 1 1 2 2 2 1 0 0 0 0 2 2 2 1 1 0 0 0 0 0 2 2 1 0 0 0 0 0 0 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 Quote Link to comment Share on other sites More sharing options...
Question
BMAD
Working with lengths that are whole units from 1 - 100, how many obtuse triangles can be formed?
Link to comment
Share on other sites
3 answers to this question
Recommended Posts
Join the conversation
You can post now and register later. If you have an account, sign in now to post with your account.