A simple multiple-choice test

[bonanova]

1. The first question with B as the correct answer is:

A. 1
B. 4
C. 3
D. 2

2. The answer to Question 4 is:

A. D
B. A
C. B
D. C

3. The answer to Question 1 is:

A. D
B. C
C. B
D. A

4. The number of questions which have D as the correct answer is:

A. 3
B. 2
C. 1
D. 0

5. The number of questions which have B as the correct answer is:

A. 0
B. 2
C. 3
D. 1

[BMAD]

I got (depending on the definition of answer)

C, D, B, C, B

[Pickett]

Agree with BMAD

Explanation:

If 1 = A...that doesn't work, because Question one is not answer B.
If 1 = B...that doesn't work, because Question one is B...
If 1 = D, then 2 = B, which means 4 = A. If that is true, then 3 = D and 5 = D...but that can't be true, since question 1's answer is not A. Therefore 1 != D.
            
So 1 = C. This means 3 = B.
    If 2 = A...Then 4 = D, but that can't be, since 4 is D.
    If 2 = B...Then 4 = A, but that can't be, since there aren't 3 answers left to be D
    If 2 = C...Then 4 = B, but that can't be true, because there aren't 2 answers left to be D
    So 2 = D, This means 4 = C
         If 5 = D, that doesn't work, because now answer 4 is wrong
         If 5 = A, that doesn't work because 3 = B
         If 5 = C, that doesn't work, because there aren't 3 answers that are B
         So 5 = B
                
Final answer: 1=C, 2=D, 3=B, 4=C, 5=B