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Dominoes on a 8x8 board (minus 2 corners)


There is an 8x8 board where two diagonally opposing corners are removed making only 62 squares. You have only 31 dominoes which are 2x1 squares ( or 1x2). How can you place these dominoes so that the board is covered completely?

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It's impossible to cover such board with dominoes.

Take a chess board and remove 2 opposing corners. These corners are of the same color (let's say black), so you have 32 white squares and 30 black squares remaining. Every domino piece must occupy 1 black and 1 white square, so to be able to cover the board entirely with dominoes there must be the same number of black and white squares on the board.

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