BMAD Posted May 12, 2013 Report Share Posted May 12, 2013 In the sequence : 12345678910111213 . . . what position does 2003 first appear? Quote Link to comment Share on other sites More sharing options...
0 vistaptb Posted May 12, 2013 Report Share Posted May 12, 2013 Positions 6902 to 6905? Quote Link to comment Share on other sites More sharing options...
0 phil1882 Posted May 12, 2013 Report Share Posted May 12, 2013 i'd say 6897. Quote Link to comment Share on other sites More sharing options...
0 BMAD Posted May 12, 2013 Author Report Share Posted May 12, 2013 i'd say 6897. I have a slightly different answer Quote Link to comment Share on other sites More sharing options...
0 bonanova Posted May 12, 2013 Report Share Posted May 12, 2013 numbers 1-9 fill 9 positions numbers 10-99 fill 90x2 = 180 positions numbers 100-999 fill 900x3 = 2700 positions numbers 1000-1999 fill 1000x4 = 4000 positions These sum to 6889 2000 2001 2002 take 12 more, so 2003 begins at position 6902 Quote Link to comment Share on other sites More sharing options...
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BMAD
In the sequence : 12345678910111213 . . . what position does 2003 first appear?
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