Guest Posted October 28, 2011 Report Share Posted October 28, 2011 The average weight of some monkeys in a bag is doubled when one giant monkey is added to the four monkeys already in the bag. The ratio of the weight of this giant monkey to the total weight of the other four monkeys is 3:? Quote Link to comment Share on other sites More sharing options...
0 Thalia Posted October 28, 2011 Report Share Posted October 28, 2011 Reveal hidden contents 3? If the weight doubled when you added the giant monkey, that would mean that in terms of weight, 1 giant monkey= 4 smaller monkeys. Quote Link to comment Share on other sites More sharing options...
0 Guest Posted October 28, 2011 Report Share Posted October 28, 2011 [spoiler=]1 Giant monkey=3 times avg weight so giant monkey:4 monkeys= 3:6 (1:2) Quote Link to comment Share on other sites More sharing options...
0 Guest Posted October 28, 2011 Report Share Posted October 28, 2011 Reveal hidden contents 1 giant monkey=5 times avg weight of 3 monkeys so giant monkey : 4 monkeys = 5:8 Quote Link to comment Share on other sites More sharing options...
0 Thalia Posted October 28, 2011 Report Share Posted October 28, 2011 On 10/28/2011 at 7:57 AM, 14.swapnil.14 said: Reveal hidden contents 1 giant monkey=5 times avg weight of 3 monkeys so giant monkey : 4 monkeys = 5:8 Oops. Average isn't total weight. Reveal hidden contents If the average weight of 4 monkeys in the bag before the giant monkey goes in is x, (4x+y)/5 monkeys=2x if y is the big monkey. Solving for y gives 6x. So wouldn't it be giant:4 small = 6:4 or 3:2? Quote Link to comment Share on other sites More sharing options...
0 Guest Posted October 28, 2011 Report Share Posted October 28, 2011 Reveal hidden contents I think it is 3 : 2 Reveal hidden contents If x is the total weight of the four monkeys, the average wt. is x/4. If y is the wt. of the big monkey, then the total wt. becomes x+y, and the average becomes (x+y)/5. As new average is double the original, we get, 2 (x/4) = (x+y)/5 On solving, we get, y/x = 3/2 which is what is asked Quote Link to comment Share on other sites More sharing options...
0 Guest Posted October 28, 2011 Report Share Posted October 28, 2011 Thank you! Very intuitive! Quote Link to comment Share on other sites More sharing options...
0 Guest Posted October 28, 2011 Report Share Posted October 28, 2011 @thalia: Hmm i was wrong twice! Quote Link to comment Share on other sites More sharing options...
0 Guest Posted October 29, 2011 Report Share Posted October 29, 2011 is any of the previous answers the right one? Quote Link to comment Share on other sites More sharing options...
0 Guest Posted October 30, 2011 Report Share Posted October 30, 2011 (edited) On 10/29/2011 at 8:47 PM, Thoth97 said: is any of the previous answers the right one? Reveal hidden contents 2 correct answers so far, post 8 from Thalia & post 9 from SMV On 10/28/2011 at 8:11 AM, Thalia said: Oops. Average isn't total weight. Reveal hidden contents If the average weight of 4 monkeys in the bag before the giant monkey goes in is x, (4x+y)/5 monkeys=2x if y is the big monkey. Solving for y gives 6x. So wouldn't it be giant:4 small = 6:4 or 3:2? On 10/28/2011 at 8:22 AM, SMV said: Reveal hidden contents I think it is 3 : 2 Reveal hidden contents If x is the total weight of the four monkeys, the average wt. is x/4. If y is the wt. of the big monkey, then the total wt. becomes x+y, and the average becomes (x+y)/5. As new average is double the original, we get, 2 (x/4) = (x+y)/5 On solving, we get, y/x = 3/2 which is what is asked Edited October 30, 2011 by thoughtfulfellow Quote Link to comment Share on other sites More sharing options...
Question
Guest
The average weight of some monkeys in a bag is doubled when one giant monkey is
added to the four monkeys already in the bag. The ratio of the weight of this giant monkey
to the total weight of the other four monkeys is 3:?
Link to comment
Share on other sites
9 answers to this question
Recommended Posts
Join the conversation
You can post now and register later. If you have an account, sign in now to post with your account.