dark_magician_92 Posted October 27, 2011 Report Share Posted October 27, 2011 sorry if this has been posted b4 there are six 1 cent coin, and seven 2 cent coins on a table and you can pick up two coins each turn and replace them with one as follows:- take 1 and 1, replace by 1 take 2 and 2, replace by 1 take 1 and 2, replace by 2 which will be the last coin left? what if 1 more 2 cent coin is added to original question? Quote Link to comment Share on other sites More sharing options...
0 dark_magician_92 Posted October 27, 2011 Author Report Share Posted October 27, 2011 do give explanation for your answers Quote Link to comment Share on other sites More sharing options...
0 Molly Mae Posted October 27, 2011 Report Share Posted October 27, 2011 sorry if this has been posted b4 there are six 1 cent coin, and seven 2 cent coins on a table and you can pick up two coins each turn and replace them with one as follows:- take 1 and 1, replace by 1 take 2 and 2, replace by 1 take 1 and 2, replace by 2 which will be the last coin left? what if 1 more 2 cent coin is added to original question? With even single cent and odd double cent, you'll always end with a 2c coin. EO = 2 OO = 2 EE = 1 OE = 1 Quote Link to comment Share on other sites More sharing options...
0 dark_magician_92 Posted October 27, 2011 Author Report Share Posted October 27, 2011 molly u really nailed it! i know u know how to do this but i still wud like to see the approach. Quote Link to comment Share on other sites More sharing options...
0 Molly Mae Posted October 27, 2011 Report Share Posted October 27, 2011 molly u really nailed it! i know u know how to do this but i still wud like to see the approach. I'm working on an actual proof when I have free time. It's pretty straight-forward after you realise that you can reduce coins down to 1 immediately. The key is actually in the second coin. If it's odd, you're left with 2c (since you'll never be able to get rid of that 2c. If it's even, you'll get rid of all of your 2c and never have a chance to get one back. Quote Link to comment Share on other sites More sharing options...
0 dark_magician_92 Posted October 27, 2011 Author Report Share Posted October 27, 2011 i shudnt be bothering u anywhere!! i will be back soon with few more Quote Link to comment Share on other sites More sharing options...
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dark_magician_92
sorry if this has been posted b4
there are six 1 cent coin, and seven 2 cent coins on a table and you can pick up two coins each turn and replace them with one as follows:-
take 1 and 1, replace by 1
take 2 and 2, replace by 1
take 1 and 2, replace by 2
which will be the last coin left?
what if 1 more 2 cent coin is added to original question?
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