[Guest]

A king made 10 packets containing 10 gold coin in each. the weight of each coin was of 10g except for one of the packet which contains 10 coins of 9g gold.

He gave those packets to their servants ramdomly.. Lets assume the name of the servant to be servant A, servant B, C, D,......J.

Now 9 servant has got 10 gold coin of 10g each and 1 servant has got 10 coin of 9 gram each.

you have been given a electronic weight which tells u the weight of the item that u keep on it.

we have to find out who has got the packets with 9g gold coin.

How will u find it out just by weighing only once.

[Guest]

you have been given a electronic weight which tells u the weight of the item that u keep on it.

How will u find it out just by weighing only once

Easy - place all the bags on the scale and remove them one by one...

[Guest]

you have been given a electronic weight which tells u the weight of the item that u keep on it.

How will u find it out just by weighing only once

Easy - place all the bags on the scale and remove them one by one...

I feel like that is weighing more than once. A better way is to take 1 coin from A -2 coins from B- 3 coins from C etc up to 10 coins from J.then how ever many grams less than an even multiple of 10 tells who had the light bag.

[Aaryan]

Spoiler Title is now mandatory. Edited August 2, 2011 by Aaryan

[Guest]

firstly take one coin 4m each servant n mark them A,B,C...J. accordingly...weight all of them at once..now remove one coin in an order..in that u can find which has less weight...cause of the differece bfore n after removng the coins one can find out easily....hope it is corect

[Guest]

you have got it wrong.. u can only take the reading once..

[Guest]

bob624 has got right....

take 1 coin from A

2 coin from B

3 coin from C

4 coin from D etc..

now the weight should have been 1+2+3+4....+10 = 55 g

but u know that some coin is of lesses weight. so the wight will be less.

Now u can get the person who got the bag with 9 g gold coins. as if the weight is less by 4 g then 4th i.e D has the bag of 9g colg coin.

[Guest]

thanks for clearing that up gaurav_herein I was in a bit of a hurry yesterday and messed up when i said less than a multiple of 10- your right it's less than 55

[bhramarraj]

If the weight of each coin is 10 gm. then the total weight of coins taken --- one coin from A, two coins from B, three coins from C,.... and ten coins from J, will be 10+20+30+......100 = 550 gm.

When weighed on the electronic scale, the weight will be less by the (number of coins) gm' taken from the servant holding the coins with less weight, as rightly said by bobb624.