[Guest]

If A and B are running in a circular track in a direction opposite to that in which C is running who, infact is running at twice and thrice the speed of A and B respectively and on the same track they start running from the same point. It is known that A's average speed is 3m/sec and track is 120m in length. When will B, after start find himself equidistant between A and C for the first time??

[Guest]

Assuming every one starts at the same time. The answer i think is

120/7 seconds.

I can tell you the mathematics behind it. But just let me know first whether i'm right or not.

[Guest]

Assuming every one starts at the same time. The answer i think is

120/7 seconds.

I can tell you the mathematics behind it. But just let me know first whether i'm right or not.

how did you get it..

do explain...

[Guest]

By the data you have given i get that the avg speeds of B and C are 2m/s and 6m/s repectively which is the easy part. Now lets consider the track to be linear with end points X and Y where C is starting from X while A and B starting from Y . Also consider the time at which B is equidistant from A and C is x seconds then its can be easily visualised that C went past A and B and i nearer to point Y. Hence we get the equation 2x - (120 - 6x) = 3x - 2x. The physical meaning of this equation is the difference between the distance of B and C from point Y is same as the difference of dictance between A and B from point Y. Solving this gives you the value of X and the answer of course.

[dark_magician_92]

If A and B are running in a circular track in a direction opposite to that in which C is running who, infact is running at twice and thrice the speed of A and B respectively and on the same track they start running from the same point. It is known that A's average speed is 3m/sec and track is 120m in length. When will B, after start find himself equidistant between A and C for the first time??

well 120/7 seconds is the 2nd time, the 1st time is after 120/9 seconds as A and C will meet after 120/9 seconds and B wud be behind A, equidistant from A and C.

[EDM]

This is supposed to be in the New Math/Logic riddles section.....sorry....

But nice one!!!