[Guest]

Find my system, It's three operations to get the answer. Two extra set numbers are brought into the system to assist with the result. As stated, these two other numbers are static variables. They affect all numbers similarly. Three examples will be given, one added daily. Let's see how this goes.

5 {} 9 = 46.667

10 {} 8 = 60

90 {} 30 = 400

15 {} 30 = ?

[Aaryan]

one question.

for each problem, is it the same operations using the same numbers in the {}?

i.e. a {times b, minus c, plus d (not necessarily those operations) }e= f

and g {times b, minus c, plus d} h=j.

[Guest]

150

a{}b=(a+b)*10/3

[Guest]

150

a{}b=(a+b)*10/3

Yeah, I thought it might be too simple.

[Guest]

I apologize for the simplicity, the next one will be harder.

[Guest]

#include <iostream>

#include <cstdio>

#include <cstdlib>

using namespace std;

int main()

{

string cont = "y";

for(;cont == "y";)//brainden is replacing part of the program formulated with ; followed by ).

{

double one;

double two;

cout << "Input1: ";

cin >> one;

cout << "Input2: ";

cin >> two;

one += two;

one = one * 10;

one = one/3;

cout << one;

cout << endl;

cout << "continue? y/n: ";

cin >> cont;

}

return 0;

}

For anyone who didn't understand the answer, heres the program I wrote to perform the operation. It really is kind of simple.

Edited January 20, 2011 by Darth Legion

[Guest]

It wasn't the simplicity of the formula that gave it away. It was 46.667. I worked backwards from that.

[Guest]

Okay, thanks, I'll be more selective about the examples next time.