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rookie1ja

Crisscross

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Crisscross - Back to the Picture & Rebus Puzzles

This is a number crossword puzzle. Enter one numeral character into each square. The clue consists of mathematical operations (e. g. "D.6 x 3" means, that the number you are looking for is three times bigger than number D.6).

Across:

A.1 = D.6 x 3

A.4 = A.7 x A.7

A.5 = (D.3 x 7) - 1

A.6 = A.1 + A.5

A.7 = D.3

Down:

D.1 = ?

D.2 = A.7 x 6

D.3 = D.6 + 6

D.4 = A.4 - 210

D.6 = (D.2 + 9) x 1/7

post-2-1175339322_thumbgif

This old topic is locked since it was answered many times. You can check solution in the Spoiler below.

Pls visit New Puzzles section to see always fresh brain teasers.

Crisscross - solution

post-2-1175339348_thumbgif

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Guest

That's a great little puzzle!

You should think about writing off to a puzzle magazine and submitting it

You could be onto a nice little earner there

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I guess I'm missing something. How do I know which square is D.1, A.1, etc?

Read it like a cross word. D stands for Down and A stands for across. So D.1 starts with the block with a one in it and goes down.

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Someone please tell me what is wrong here! D.2 should consist of 3 numbers, not 2!

D.2 = A.7 x 6

A.7 = D.3

D.3 = D.6 + 6

D.6 = (D.2 + 9) / 7

X = Y x 6

Y = Z + 6

Z = (X + 9) / 7

Y - 6 = (X + 9) / 7

X / 6 - 6 = (X + 9) / 7

X x 7 - 6 = (X + 9) x 6

7X = 6X + 54 - 6

7X = 6X + 48

X = 48

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Someone please tell me what is wrong here! D.2 should consist of 3 numbers, not 2!

D.2 = A.7 x 6

A.7 = D.3

D.3 = D.6 + 6

D.6 = (D.2 + 9) / 7

X = Y x 6

Y = Z + 6

Z = (X + 9) / 7

Y - 6 = (X + 9) / 7

X / 6 - 6 = (X + 9) / 7

X x 7 - 6x6x7 = (X + 9) x 6

7X = 6X + 54 - 6 + 252

7X = 6X + 48 306

X = 48306

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That was a fun one of which I joyfully solved. Thanks for making my day a bit better.

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The best way to do this is to set everything equal to D6 we'll call this X.

A.1 is easy this is just 3X; A.4 is equal to (A.7)^2 and A.7 is equal to D.3 which is equal to X+6, so A.4 is equal to (X+6)^2 or X^2+ 12X+36. Everything can be set as a variation of X except D.1 which fills itself in

Edited by harpuzzler

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Let x = D6

x = (D2 + 9)/7

= ((A7 * 6) + 9)/7 <-- substitute (A7 * 6) for D2

= ((D3 * 6) + 9)/7 <-- substitute D3 for A7

= (((x + 6) * 6) + 9)/7 <-- substitute x + 6 {i.e., D6 + 6} for D3

= ((6x + 36) + 9)/7

= (6x + 45)/7

(7/7)x = (6x + 45)/7

7x = 6x + 45

x = 45

A1 = D6 *3 = (45)*3 = 135

D3 = D6 + 6 = (45) + 6 = 51

A7 = D3 = 51

A4 = A7 * A7 = (51)*(51) = 2601

A5 = (D3 * 7) - 1 = (51 * 7) - 1 = 356

A6 = A1 + A5 = (135) + (356) = 491

D2 = A7 * 6 = (51) * 6 = 306

D4 = A4 - 210 = (2601) - 210 = 2391

D6 = (D2 + 9) * 1/7 = ((306) + 9) * 1/7 = 315/7 = 45

__135

_2601

_356_

491__

51___

D1 = 1651

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