rookie1ja Posted March 31, 2007 Report Share Posted March 31, 2007 Crisscross - Back to the Picture & Rebus Puzzles This is a number crossword puzzle. Enter one numeral character into each square. The clue consists of mathematical operations (e. g. "D.6 x 3" means, that the number you are looking for is three times bigger than number D.6). Across: A.1 = D.6 x 3 A.4 = A.7 x A.7 A.5 = (D.3 x 7) - 1 A.6 = A.1 + A.5 A.7 = D.3 Down: D.1 = ? D.2 = A.7 x 6 D.3 = D.6 + 6 D.4 = A.4 - 210 D.6 = (D.2 + 9) x 1/7 This old topic is locked since it was answered many times. You can check solution in the Spoiler below. Pls visit New Puzzles section to see always fresh brain teasers. Crisscross - solution Link to comment Share on other sites More sharing options...
Guest Posted June 15, 2007 Report Share Posted June 15, 2007 That's a great little puzzle! You should think about writing off to a puzzle magazine and submitting it You could be onto a nice little earner there Link to comment Share on other sites More sharing options...
Guest Posted January 26, 2009 Report Share Posted January 26, 2009 I guess I'm missing something. How do I know which square is D.1, A.1, etc? Link to comment Share on other sites More sharing options...
Guest Posted January 26, 2009 Report Share Posted January 26, 2009 I guess I'm missing something. How do I know which square is D.1, A.1, etc? Read it like a cross word. D stands for Down and A stands for across. So D.1 starts with the block with a one in it and goes down. Link to comment Share on other sites More sharing options...
Guest Posted September 27, 2010 Report Share Posted September 27, 2010 Someone please tell me what is wrong here! D.2 should consist of 3 numbers, not 2! D.2 = A.7 x 6 A.7 = D.3 D.3 = D.6 + 6 D.6 = (D.2 + 9) / 7 X = Y x 6 Y = Z + 6 Z = (X + 9) / 7 Y - 6 = (X + 9) / 7 X / 6 - 6 = (X + 9) / 7 X x 7 - 6 = (X + 9) x 6 7X = 6X + 54 - 6 7X = 6X + 48 X = 48 Link to comment Share on other sites More sharing options...
Guest Posted January 4, 2011 Report Share Posted January 4, 2011 Someone please tell me what is wrong here! D.2 should consist of 3 numbers, not 2! D.2 = A.7 x 6 A.7 = D.3 D.3 = D.6 + 6 D.6 = (D.2 + 9) / 7 X = Y x 6 Y = Z + 6 Z = (X + 9) / 7 Y - 6 = (X + 9) / 7 X / 6 - 6 = (X + 9) / 7 X x 7 - 6x6x7 = (X + 9) x 6 7X = 6X + 54 - 6 + 252 7X = 6X + 48 306 X = 48306 Link to comment Share on other sites More sharing options...
Guest Posted March 21, 2011 Report Share Posted March 21, 2011 That was a fun one of which I joyfully solved. Thanks for making my day a bit better. Link to comment Share on other sites More sharing options...
Guest Posted May 31, 2011 Report Share Posted May 31, 2011 (edited) The best way to do this is to set everything equal to D6 we'll call this X. A.1 is easy this is just 3X; A.4 is equal to (A.7)^2 and A.7 is equal to D.3 which is equal to X+6, so A.4 is equal to (X+6)^2 or X^2+ 12X+36. Everything can be set as a variation of X except D.1 which fills itself in Edited May 31, 2011 by harpuzzler Link to comment Share on other sites More sharing options...
Guest Posted May 31, 2011 Report Share Posted May 31, 2011 Let x = D6 x = (D2 + 9)/7 = ((A7 * 6) + 9)/7 <-- substitute (A7 * 6) for D2 = ((D3 * 6) + 9)/7 <-- substitute D3 for A7 = (((x + 6) * 6) + 9)/7 <-- substitute x + 6 {i.e., D6 + 6} for D3 = ((6x + 36) + 9)/7 = (6x + 45)/7 (7/7)x = (6x + 45)/7 7x = 6x + 45 x = 45 A1 = D6 *3 = (45)*3 = 135 D3 = D6 + 6 = (45) + 6 = 51 A7 = D3 = 51 A4 = A7 * A7 = (51)*(51) = 2601 A5 = (D3 * 7) - 1 = (51 * 7) - 1 = 356 A6 = A1 + A5 = (135) + (356) = 491 D2 = A7 * 6 = (51) * 6 = 306 D4 = A4 - 210 = (2601) - 210 = 2391 D6 = (D2 + 9) * 1/7 = ((306) + 9) * 1/7 = 315/7 = 45 __135 _2601 _356_ 491__ 51___ D1 = 1651 Link to comment Share on other sites More sharing options...
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