[Guest]

2Q+Q²=4Q

How many different integers can Q be equal to?

Edited November 2, 2010 by matthew laming

[Guest]

2Q+Q²=4Q

How many different integers can Q be equal to?

Q2-2Q = 0

Q(Q-2) = 0

Q = 2 or 0

so 2 integers.

[bonanova]

2Q+Q²=4Q

How many different integers can Q be equal to?

2.

[Guest]

Q2-2Q = 0

Q(Q-2) = 0

Q = 2 or 0

so 2 integers.

2.

yeah you got it.

[Guest]

since it's a quadratic polynomial it's gonna have 2 solutions

[Guest]

since it's a quadratic polynomial it's gonna have 2 solutions

Where I'm from we learn this in 7th or 8th grade. can't believe it's a puzzle

[Guest]

Simple, but lets make it more scientific

2Q + Q^2 = 4Q

Q^2+2Q-4Q = 0

Q^2 - 2Q = 0

α=1

β=-2

γ=0

Δ = (β)² - 4 * α * γ

Δ = (-2)² - 4*1*0

Δ = 4

Q_1,2 = -(β) +- √Δ / 2 α = -(-2) +- √4 /2 = 2 +- 2 /2 ==> 1) 2+2/2 = 4/2 = 2 2) 2-2/2 = 0/2 = 0

Answer:

Q sould be 2 or 0

Indeed:

2*2+2² = 4*2

4+4 = 8

8=8

2*0+0^0 = 4*0

0+0 = 0

Edited November 3, 2010 by Tsopi

[Guest]

This made me wanna ask you if you can prove that x⁰ = 1 it is easy...