[Guest]

A father has 80 apples and share them between his 3 sons such that the eldest get 50 apples, the 2nd 20 and the 3rd 10.He tells to sell the apples such :

a)each and every apple is worth the same;

b)each son should bring the same amount of money home;

c)all apples must be sold, and each son must sell his quota;

d)no sharing of apples or money;

e)no expense of money

How much money is brought home??

[Guest]

Zero. The apples are each worth zero. They're probably thos estupid Granny Smith apples. Seriously, who buys these things, just make a sweet apple and be done. People say they're better in pies because of the texture and that's not true. When was the last time you ate an apple pie and commented on it's lovely texture. Sweet apples, sweet pies, better pies.

[Guest]

If an apple costs x, then the eldest brother will bring home 50x, the 2nd one 20x and the 3rd 10x.

50x = 20x = 10x implies that x = 0, so the apples are worth nothing. Unless there's a trick somewhere that I missed...

[Guest]

the brothers figure out a viable price that will enable them to sell all the apples.

They sell the apples and meet at the local pub. The oldest buy's most of the beers with the middle son chipping in a few rounds, while the youngest son holds onto his coinage.

When they all have approx the same cash left as the youngest son they leave a small tip to normalize to the minimum cash amount and shuffle off home giggling merrily because they are pished.

[Guest]

the brothers figure out a viable price that will enable them to sell all the apples.

They sell the apples and meet at the local pub. The oldest buy's most of the beers with the middle son chipping in a few rounds, while the youngest son holds onto his coinage.

When they all have approx the same cash left as the youngest son they leave a small tip to normalize to the minimum cash amount and shuffle off home giggling merrily because they are pished.

But they can't spend the money.

[Guest]

it is said that the apples cost the same not that they are sold at the same price, so the second and the third son sold it at a profit and got back 50x each home hence bringing a tot sum of 150x, x being price of n apple.

p.s: The solution involving the beer is the one I prefer though

[Guest]

all sons have 50,20,10 apples

50, 20, 10 must be sold. Lets say that the price is X.=>

50x=20x=10x we divide with 10

5x=2x=x

5x-x=2x-x=x-x

5x=x

x=0/5=0 thats the answer

[Guest]

You cant sell something for free.

I think the answer is either from a special deal, buy one get one free, or just

it is said that the apples cost the same not that they are sold at the same price, so the second and the third son sold it at a profit and got back 50x each home hence bringing a tot sum of 150x, x being price of n apple. p.s: The solution involving the beer is the one I prefer though

[Guest]

Good old Dad being generous with his apples bigger boy gets 50, 20 for middle son, and last of all younger son gets 10 which in my eyes equals a Big 0.

[plainglazed]

like some others, figured if all apples are "worth" the same, the two sons with more apples would have to sell theirs at a discount to make the same amount as the youngest one. All then would make 10x so 30x total.

maybe the apples are all worth the same per unit weight. oldest son with 50 little crab apples, middle son with 20 small macintoshes, and youngest son with 10 giant red delicious. If all sons apples weighed the same and worth the same per unit weight, then the total take would be 3 times the weight of each group/price per unit weight.

[Guest]

The ratio of apples distributed among the three scions, oldest to youngest, are 5/8, 2/8 and 1/8. Therefore, the price each son would place on their own apples to sell would be a multiple of the respective inverse of the numerator: 1/5, 1/2 and 1. The least common denominator of these three numbers is 10, therefore, the eldest would sell his apples for 10x/5 = 2x units of currency each, the second oldest would sell his for 10x/2 = 5x units of currency each, and the third oldest would sell his for 10x units of currency each, such that x is a nonnegative integer iff the price must be a nonnegative integer.

The total brought home by the three would be = 300x units of currency = 50*(2x) + 20*(5x) + 10*(10x).

If each price must be identical for every apple sold by the three, the price would need be 0 units of currency (free). But 'free' would not be 'selling' the apples, and with no apple sold, the amount of money brought home would be the empty set, 0, as no son would be returning home.

[Guest]

Zero. The apples are each worth zero. They're probably thos estupid Granny Smith apples. Seriously, who buys these things, just make a sweet apple and be done. People say they're better in pies because of the texture and that's not true. When was the last time you ate an apple pie and commented on it's lovely texture. Sweet apples, sweet pies, better pies.

Hey! I like sour apples!

[Guest]

A father has 80 apples and share them between his 3 sons such that the eldest get 50 apples, the 2nd 20 and the 3rd 10.He tells to sell the apples such :

a)each and every apple is worth the same;

b)each son should bring the same amount of money home;

c)all apples must be sold, and each son must sell his quota;

d)no sharing of apples or money;

e)no expense of money

How much money is brought home??

[Guest]

$9, 50 @ $0.06 each, 20 @ $0.15 each ane 10 @ $0.30 each.

[Guest]

$9, 50 @ $0.06 each, 20 @ $0.15 each ane 10 @ $0.30 each.

If I understood the question correctly (which is rare) I belive Imhere is right.

[Guest]

If the point " Each and every apple is worth the same" means that each apple was bought at same price( but not sold at same price), then , Let x=price for which first one sold an apple , y =price at which second one sold and z =price of each apple sold by third, then, 50x=20y=10z,or y=5/2x and z=5x .We can have as many solutions of this as we want. One would be -> 1st solds each apple for $1, then 2nd solds each for $2.5 and third $5 each. They all would bring $50 each , making a total profit of $150.

[Guest]

SO IS HARJOT!!

[Guest]

SO IS HARJOT!!

its all about maths dear brrr

the price is X

now you must find a way that

50*x=20*x=10*x

the price is the same so do the X is

so the only number is 0 cause

50*0=0

20*0=0

10*0=0

thats the answer look at my solution above

P.S: USE UR BRAIN ALL OF YOU!!!!still waiting the priest brrr

[Guest]

Actually this last answer sounds right. It plays with the interpretations of the rules provided. I just don't know if it's the intended answer. Indeed, if something costs 0 you're not really selling it.

[Guest]

I think that the condition of the apples costing the same applies to each of the brothers-not the entire collection of apples.

So brother A has 50 apples to sell at some fixed cost X. Brother B has 20 apples to sell at some fixed cost Y and brother C has 10 apples at a fixed cost of Z.

50X=20Y=10Z

Brother A sells his for $2/each and makes $100

Brother B sells his for $5/each and makes $100

Brother C sells his for $10/each and makes $100

Total money they make is $300

[Guest]

er, i think u may be missing something

it doesnt say that the brothers cant buy or sell off each other, does it, only that they cant share the apples or the money, so...

the answer is... im too drunk to do the maths right now. but il try. for all bro to have the same amount of apples/to make same amount of £$ they all need 26.666 apples each. (80 apples dont go well into 3, so...

the 1st bro sells 16.666 apples to bro 3, then 6.666 aples to bro 2, then all brothers sell their remaining apples at the same price and hence end up with the same amount of profit, so .... if apples are sold for a price of £1 per apple the amount of money brought home will be £80, but it depends how much you charge for an apple. so the answer is - it depends how much u charge! am I wrong

[Guest]

But the puzzle says they're not allowed to spend money. Unless you consider that they are only not allowed to spend the money they made from the apples, but still, if brother 1 sell some apples to brothers 2 and 3 then sell the other ones to other people, he's still selling 50 and making 50x of money. And brother 2 can sell these extra apples along with the ones he already have, but he bought then with money in the first place, so he goes back home with 20x and so on. It could work, however, if you consider that they already had some money, like brother 1 has $50, 2 has $70, and 3 has $90, and they sell the apples for $1 each. Then they all go back home with $100.

[Guest]

I think they will have to sell different number of apples on different rates on different days keeping same rate on same day.

Only then this is possible to get same amount from different number of apples.

[Guest]

Many solutions are possible.

If they sold apples on two days, They sold 5,8 9 apples out of 50,20,10 apples respectively @ Rs 11 per apples and got Rs 55,88,99 on First day.

On next day, balance apples were rotten and balance 45,12 , 1 apples were sold @ Rs 1 per apple and got Rs 45,12 and 1 on next day.

Total amount got by each son is Rs 100 .

[Guest]

possibly

C sells all 10

B sells 10 and give other 10 as free (1 for 1)

A sells 10 and give other 40 as free (4 for 1)

total selling 30*X