[Guest]

Not a pack of lies ,

15 cards - one suit Ace to King plus two Jokers. All shuffled and placed on the table in a row. It does not matter if placed left to right or right to left as no card occupies it's original position either way, nor starts or finishes with two jokers. No court card (face card) or joker are at either end, nor in adjacent positions. The jokers have six cards between them. The card on the far left is one higher than on the far right, and is adjacent to a court card. Seven is two places left of two. Three is two places left of the rightmost Joker. The Ace is two places to the right of the King, and two left of the leftmost joker. Ten is two places to the left of five and three to the right of six. The Queen is two left of the Jack and four to the right of the Ace. The four is further left than the seven

Which order is each card if viewed L-R

I put the numbers in wriiten form and ran the whole thing to one paragraph to be awkward. You might want to rearrange it into numbers/names eg A,2,3,4,5, Jo, Ja etc and use seperate lines for each sentance.

I know I hav'nt named all the cards, that would be too EZ.

[Guest]

9 K 4 A 7 JK 2 Q 6 J 3 10 JK 5 8

[bonanova]

It does not matter if placed left to right or right to left as no card occupies it's original position either way, nor starts or finishes with two jokers.

Can you make this two separate sentences?

"no card ... starts or ends with two jokers" doesn't make sense.

[Guest]

Can you make this two separate sentences?

"no card ... starts or ends with two jokers" doesn't make sense.

10 min edit has gone!

But to clarify There are no jokers in position 1,2 or 14,15

I had spent a lot of time edditing but over cooked it!

Barne012 did it so it an't be too bad

Average time is 45 mins on this.

your bttr than average!

[Guest]

Only 9 and 8 were left out.And I found the combination to be

9 K 4 A 7 Jo 2 Q 6 J 3 10 Jo 5 8

[bonanova]

I drew and labeled a 15x15 grid.

Then it took

9 K 4 A 7 Joker 2 Q 6 J 3 10 Joker 5 8

Nice puzzle.