Guest Posted June 12, 2010 Report Share Posted June 12, 2010 Determine fewest possible squares in this 4x4 array. Treat them as if their plain sheets of paper that aren't see-through and the lines in the problem represent the edges of said squares. How low can you go? Quote Link to comment Share on other sites More sharing options...
0 Guest Posted June 13, 2010 Report Share Posted June 13, 2010 Determine fewest possible squares in this 4x4 array. Treat them as if their plain sheets of paper that aren't see-through and the lines in the problem represent the edges of said squares. How low can you go? the least is 8 One square 4X4 on bottom, 2 2x2 on right, 4 1X1 on left and the diamond in the middle Quote Link to comment Share on other sites More sharing options...
0 Guest Posted June 13, 2010 Report Share Posted June 13, 2010 9 Quote Link to comment Share on other sites More sharing options...
0 Guest Posted June 13, 2010 Report Share Posted June 13, 2010 zero Quote Link to comment Share on other sites More sharing options...
0 Guest Posted June 13, 2010 Report Share Posted June 13, 2010 ill explain my answer when i get back from dinner but: 1 Quote Link to comment Share on other sites More sharing options...
0 Guest Posted June 13, 2010 Report Share Posted June 13, 2010 Other people have smaller numbers but I can't make them work. 10. The top right 1X1 box can be eliminated, as the 'underneath' 4X4 square covers it, but to get all of the lines I think you need 10. The bottom right 'L' shaped one is a 2X2 with a 1X1 on the corner, half of which is covered by the diamond, you need all four down the left edge, So, 4 down the left, 1 underneath, 2 in the top right, 1 in the bottom right covered by another 1 with 1 on top of that. 10. Quote Link to comment Share on other sites More sharing options...
0 Izzy Posted June 14, 2010 Report Share Posted June 14, 2010 (edited) One or zero, depending on what counts. Look at the strip separated by the diamond. Put it on top of the four squares to the left of it, and stick one of the little triangles under the diamond to make it a level surface. Then take the last row, and stick it underneath that one, with the square in the L-shaped thing sticking out. Place the square on top of the third row on top of that. Then place the triangle on top of that. If you count two triangles as a square, then it's a square, otherwise it isn't. Edited June 14, 2010 by Izzy Quote Link to comment Share on other sites More sharing options...
0 Guest Posted June 14, 2010 Report Share Posted June 14, 2010 (edited) A bit confusing. I'd say 6 squares..... Edited June 14, 2010 by Pat_power Quote Link to comment Share on other sites More sharing options...
0 Guest Posted June 14, 2010 Report Share Posted June 14, 2010 Determine fewest possible squares in this 4x4 array. Treat them as if their plain sheets of paper that aren't see-through and the lines in the problem represent the edges of said squares. How low can you go? 8? Quote Link to comment Share on other sites More sharing options...
0 Guest Posted June 14, 2010 Report Share Posted June 14, 2010 Other people have smaller numbers but I can't make them work. Your answer fits the requirements. Let's see if others really can give legitimate explanations for this easy puzzle. Remember people: this isn't a test of lateral thinking; this pattern has been created by squares only. Quote Link to comment Share on other sites More sharing options...
0 Guest Posted June 15, 2010 Report Share Posted June 15, 2010 9 squares: first one 4x4 square then one 3x3 square in bottom right position on it place two 2x2 - one on bottom right and second into upper middle position. then four 1x1 in positions: upper row - left column, upper row - second column from right second row from bottom - left column, second row from bottom - second column from right and finaly central diamond. I was not successful with 8 Quote Link to comment Share on other sites More sharing options...
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Determine fewest possible squares in this 4x4 array. Treat them as if their plain sheets of paper that aren't see-through and the lines in the problem represent the edges of said squares.
How low can you go?
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