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Determine fewest possible squares in this 4x4 array. Treat them as if their plain sheets of paper that aren't see-through and the lines in the problem represent the edges of said squares.

How low can you go?

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Determine fewest possible squares in this 4x4 array. Treat them as if their plain sheets of paper that aren't see-through and the lines in the problem represent the edges of said squares.

How low can you go?

the least is 8

One square 4X4 on bottom, 2 2x2 on right, 4 1X1 on left and the diamond in the middle

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Other people have smaller numbers but I can't make them work.

10. The top right 1X1 box can be eliminated, as the 'underneath' 4X4 square covers it, but to get all of the lines I think you need 10. The bottom right 'L' shaped one is a 2X2 with a 1X1 on the corner, half of which is covered by the diamond, you need all four down the left edge,

So, 4 down the left, 1 underneath, 2 in the top right, 1 in the bottom right covered by another 1 with 1 on top of that. 10.

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One or zero, depending on what counts. Look at the strip separated by the diamond. Put it on top of the four squares to the left of it, and stick one of the little triangles under the diamond to make it a level surface. Then take the last row, and stick it underneath that one, with the square in the L-shaped thing sticking out. Place the square on top of the third row on top of that. Then place the triangle on top of that. If you count two triangles as a square, then it's a square, otherwise it isn't.

Edited by Izzy

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Determine fewest possible squares in this 4x4 array. Treat them as if their plain sheets of paper that aren't see-through and the lines in the problem represent the edges of said squares.

How low can you go?

8?

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Other people have smaller numbers but I can't make them work.

Your answer fits the requirements. Let's see if others really can give legitimate explanations for this easy puzzle. :)

Remember people: this isn't a test of lateral thinking; this pattern has been created by squares only.

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9 squares:

first one 4x4 square

then one 3x3 square in bottom right position

on it place two 2x2 - one on bottom right and second into upper middle position.

then four 1x1 in positions:

upper row - left column,

upper row - second column from right

second row from bottom - left column,

second row from bottom - second column from right

and finaly central diamond.

I was not successful with 8

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