[Guest]

can you get the next term?

1) 1,2,5,7,12,15,22,35,?

2) 5,8,16,42,158,?

3) 2,4,6,9,13,18,24,?

[peace*out]

can you get the next term?

1) 1,2,5,7,12,15,22,35,?

2) 5,8,16,42,158,?

3) 2,4,6,9,13,18,24,?

1)

57

[superprismatic]

can you get the next term?

1) 1,2,5,7,12,15,22,35,?

2) 5,8,16,42,158,?

3) 2,4,6,9,13,18,24,?

1) 40

2) 1894

3) 31

[Guest]

40 is the answer. (sequence (p(n)^2-1)/24)

#3 is also correct, 31 is the answer, though the next number is not 39. (its 40)

hint: use the probability of a number being prime to generate next number.

#2 is wrong.

Edited May 5, 2010 by phillip1882

[superprismatic]

40 is the answer. (sequence (p(n)^2-1)/24)

#3 is also correct, 31 is the answer, though the next number is not 39. (its 40)

hint: use the probability of a number being prime to generate next number.

#2 is wrong.

The answer to #2 is 1894. You can't prove otherwise!

[Guest]

40 is the answer. (sequence (p(n)^2-1)/24)

#3 is also correct, 31 is the answer, though the next number is not 39. (its 40)

hint: use the probability of a number being prime to generate next number.

#2 is wrong.

Could you explain the rule for #1? It doesn't make any sense to me. Thanks.

[Guest]

(5^2 -1)/24 = 1

(7^2 -1)/24 = 2

(11^2 -1)/24 = 5

etc.

[Guest]

(5^2 -1)/24 = 1

(7^2 -1)/24 = 2

(11^2 -1)/24 = 5

etc.

That's not (p(n)^2-1)/24 but rather (p(n+2)^2-1)/24

Thus, you have an obscure starting point.

One would need to know to just ignore 2 and 3.

Of course this can be determined but through more trial and error than perception.

[Guest]

Took me a little while to figure out that p(n) was for primes. Now it makes sense.