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Vishnu Nanilal Panicker

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  1. If the number of apples you'd have to eat were the same from both the bowls, of course anyone would have chosen from the one with the less number of poisonous apples. But here's the case is different. Let's analyse: 1st bowl We can use simple probability. Death happens when both apples you choose are poisonous. If any of the two apples were non poisonous, you'd survive. P(First apple to be poisonous) = 3/5. P(Second apple to be poisonous given first apple was poisonous)= (3/5)*(2/4). =30 % So, there's a 30 pe
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