rocdocmac
-
Posts
433 -
Joined
-
Last visited
-
Days Won
15
Content Type
Profiles
Forums
Events
Gallery
Blogs
Posts posted by rocdocmac
-
-
22 hours ago, TimeSpaceLightForce said:Spoiler
I have identified 7 squares on the board as it is currently. Correct?
There are 19 pieces involved in these 7 squares. Correct?
If you say that only the square corner pieces should be removed, does that mean pieces from only one square?
I think i have identified the four pieces. I can place three of them back without making extra squares, but I am battling placing the last one back! Think I'll go through my process again.
-
Spoiler
Let's assume that all categories with reference to Name, Country and Cache type are correct according to plasmid's interpretation and my three solutions previously posted. Only the number of caches still have to be established for each pitch.
The attached spreadsheet is hopefully self explanatory.
Using all possible combinations for the number of caches with respect to Heidi, Hugo and Frank, solutions 1, 2, 6 and 7 are invalid since the number of Spanish caches are not half of Marie's caches. Three possible solutions are found, but the two solutions that make use of 8 for Heidi and 5 for Hugo (i.e. 10 for Marie) lead to ambiguition (2 or 4 can fit into either pitch #1 or #6).
So I chose solution 3 as my final answer since there is no uncertainty.
Therefore, the number of caches form pitch 1 to 7 = 5, 8, 10, 16, 40, 4, 2, and 10, respectively.
-
Inserting a comma between "door" and "but", i.e. 5) The Chilean, who is not next door, but one to the Belgian, ..., would certainly change the meaning to one tent between the Chilean and Belgian.
-
Spoiler
Dumb question from me! ... I suppose one just has to replace all the pieces with "counters" and follow the rule!
"We still need a lot of education" a la Pink Floyd!
-
Spoiler
Silly question ... why an extra pawn on each advancing side (18 chess pieces in total) or is that just part of the puzzle to work?
-
Spoiler
(5) The Chilean, who is NOT "next door but one to the Belgian" therefore means that there is NOT one pitch between the Chilean and the Belgian.
-
1 hour ago, bonanova said:
My interpretations
-
Country(Pitch2) = France
Fav(USA) = wherigos.
-
Pitch(Marie) + 1 = Pitch(Chile)
Fav(Marie) = multi
Finds(Marie) = 2 Finds(Spain)
Fav(Spain) /= letterbox.
-
Fav(Heidi) = mystery
Finds(Heidi) > Finds(Hugo) > Finds(Frank)
-
Contry(Bridgette) = Germany
Pitch(Bridgette) = Pitch(Frank) - 2
Pitch(Frank) /= 7
Pitch(UK) - Pitch(Bridgette) > 1
-
| Pitch(Chile) - Pitch(Belgium) | /= 1 (*)
Pitch(Chile) > Pitch(Stanley)
Pitch(earth) = 1
(*) Interpret "next door but one" to mean exactly one intervening pitch.
Clue 5 then says this does not apply to Chile and Belgium.
-
Pitch(Juan) = 3
ManX = { Hugo Juan Stanley }
Finds(Manx) = 16
Pitch(Manx) < Pitch(Frank)
-
Pitch(Heidi) = Pitch(USA) + 1
Finds(USA) > Finds(UK)
Finds(Fav = traditional) = 40
Country(40 = Finds) = { Belgium France Germany Spain UK }
I believe gives this solution
- Stanley UK earth 2
- Marie France multi 10
- Juan Chile letterbox 16
- Bridgette Germany traditional 40
- Hugo Spain virtual 5
- Frank USA whereigo 4
- Heidi Belgium mystery 8
SpoilerBonanova's solution corresponds to my first of the three I gave. What would not fit in when considering my 2nd and 3d solutions?
-
Country(Pitch2) = France
-
18 hours ago, plasmid said:
I was thinking that
5) The Chilean, who is not next door but one to the Belgian...
means that there's one pitch between the Chilean and the Belgian. If st3v3n80 is able to ask the friend who gave him the problem these clarification questions, maybe we could sort it out.
SpoilerI think you're right, unless "Belgian" was a typo for "Spaniard". The puzzle was from the OP's friend and retyped on this site, so there may be errors. That's why we'll have to see the original - if st3v3n80's friend can point us to the source. I,since not initially understanding "but one to the Belgian" and therefore ignored this clue completely. If The Spaniard is on pitch 5, the "letterbox" can be deleted from tent 5 and the ambiguity resolved.
8 hours ago, Thalia said:I've interpreted clue 7 to mean the American found more than the Englishman. Do you have an alternative interpretation? That would contradict your 2nd and 3rd solutions. If you swap Spain and Belgium, Marie no longer finds twice as many as the Spaniard. Your first might be the one! The only thing that would make it incorrect is whatever the intention was on the Belgium clue...
Spoiler7) Heidi, ......, and who found more ... I believe Heidi is the "who". Otherwise the "and" should've been dropped to refer to the American.
-
Spoiler
Place the following in the 10 bags:
$1, $2, $4, $8, $16, $32, $64, $128, $256, $489.
Combination of the contents of these bags would give you the correct amount from $1 to $1000.
-
Spoiler
If I exchange Spain and Belgium, plasmid's ambiguity steps in! By the way, the names are typically related to the country of origin.
-
Found three solutions ...
Spoiler
Maybe not correct ...
SpoilerBelgium and Apain may possibly be swapped.
SpoilerI meant a Spain and Belgium swap!
Can't edit - sorry for the spolier outside the box!
-
I think that st3v3n80 should ask his friend that gave the puzzle to him/her, to clarify.
It's relatively easy to sort out names and countries, but the number of caches appears not to have enough given clues.
-
@Thalia
Well done!
-
6 hours ago, st3v3n80 said:
5) The Chilean, who is not next door but one to the Belgian, is further right than Stanley. Pitch one much prefers earth caches.
Wat is meant by "but one to the Belgian"? A word missing?
7 hours ago, st3v3n80 said:4) Brigitte is German. Her tent is two places left of Frank’s
Unclear whether there is one or two tents between them.
-
40 minutes ago, Thalia said:
When it says a student plays 2 sports, that doesn't mean they don't play the 3rd sport. So I think when you subtract 2X, you're subtracting students already accounted for.
SpoilerThe middle section has been counted three times, one for each group, so we must subtract it twice in order to count it once ultimately. What does the Venn diagram for your solution look like?
-
Something is wrong with one or more of the numbers in the OP!
Spoiler
-
Spoiler
I like your answer, but NO! However, you've earned a cigar for that attempt!
-
Spoiler
Male, contemporaneous, former politician/political figure.
-
That's it!
Plainglazed's answer appears to have come in slightly ahead of bonanova's, but both of them are right.
X^2 =C (10^2 = 100)
X^3 = M (10^3 = 1000)
Was a quickie, wasn't it?
-
A bit late now, but here's a revisit.
I told you that I could have chosen a "better" stack! Here's one that actually works. It contains overhanging of bricks, but shows that shifting does not necessarily alter the perimeter.
No more yellow segments, Thalia!
Spoiler -
Spoiler
Still not what I want!
-
Spoiler
Sad to say that things don't work out when one is dealing with "overhanging bricks" at the start.One has to have an eventual stack that's "growing" downward, or at least, the number of bricks in a row should equal the number of bricks above (or below) it. The bottom line is ... when the number of Ls don't match the number of Hs, it's not possible to find an answer.
I now fully agree that it is certain that the perimeter can change when shifting bricks and I duly apologize to all.
Sorry guys, I should've chosen a "better" stack layout!
Still hats off to the Captain for his effort and Thalia for her input.
@Moderator, please declare this question null and void ... everything did look perfect when I posted it!
-
Spoiler
Ed, you've got the answer correct and I'll duly mark yours as best answer. You mathematically came up with 9*345, which also holds for the shifted bricks. Shifting doesn't change the total perimeter (circumference) as the bricks stay in contact and no space is added in between any of them along a horizontal line.
-
Mathematically very well done, Ed! There is a way to "see it" ...
SpoilerShifting all the bricks either to the left or right , one can see that there are 18*L and 18*H, i.e. 9 pairs of L+H. Thus, a quick way to check the answer without having to know the actual L and H values!
Square Free
in New Logic/Math Puzzles
Posted
I have identified 7 squares on the board as it is currently. Correct? Wrong - I now have found 8
There are 19 pieces involved in these 7 squares. Correct? Wrong - 20 pieces involved.