At first, I thought this 35 page long argument was ridiculous, but after reading bona/syon's posts above, I can understand some of the trouble surrounding the ambiguity of the question. This is the way I see it:
There are four possibilities for boy/girl combinations, as mentioned several times by now (I imagine):
BB
BG
GB
GG
Note that this categorization does take into account the order of the children. We are shown that one of the children is a girl, which of course eliminates the first combination.This is the point where people jump to the answer of 1/3, since there only seem to be three combinations remaining. However, as I stated before, order does matter if you look at the problem this way. Therefore, there are still four possibilities:
G1B2
G2B1
G1G2
G2G1
Where the number indicates order. The girl we see can be either the elder (G1) or younger (G2) sister, so we must look at both possibilities equally. Thus, the probability stands at 1/2, regardless of the order of birth.
Another way to look at this is to completely disregard order in all of the cases. The resulting combinations are:
BB
GB (same as BG!)
GG
When BB is eliminated, the probability of GG remains at 1/2.