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mewminator

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Posts posted by mewminator

  1. Hey, I'm getting bored, and would like for all noobs to stop what you are doing and sign up immediately b/c it will be the time of your life and you WILL love it. I promise to help as a mentor b/c I was in the beginning. This game will only take minutes from your lifetime.

    If you feel afraid, I can counter that too.

    I agree with slick... it's laughable that there are more mentors than players.

  2. I'm voting with whoever gets me a flame retardant suit.

    thanks to TheChad's reminder

    1. WitchOfDoubt - voting for [ __, __, __ ]

    2. Flamebirde - voting for [MiKi, WOD, curr ]

    3. MiKi - voting for [Burn them all, flame, WOD]

    4. Curr3nt - voting for [Burn them all, __, __ ]

    5. mew- voting for [Burn them all, shoot, stab, run over, or beat to death any remaining survivors(including curr3nt and whoever votes with him), __, __ ]

    As for

    Vote: WOD

    for president of the Forest.

    NEVER!

  3. who was he?

    He can be both the uncle and he nephew.

    The perrfect gentleman was a king, the nephew could not see him as one because he knew a secret thet says otherwise, an action done that reduced him from being a prefect gentleman, like say: killing his brother (the nephew's father) to usurp the throne.... (See Hamlet)

    even though I'm 99.99% sure that it's wrong but whatever

  4. 1. WitchOfDoubt - voting for [ __, __, __ ]

    2. Flamebirde - voting for [MiKi, WOD, curr ]

    3. MiKi - voting for [Burn them all, flame, WOD]

    4. Curr3nt - voting for [Burn them all, __, __ ]

    5. mew- voting for [Burn them all(including curr3nt and whoever votes with him), __, __ ]

    We're not getting any sign ups, we might as well play it this way...

  5. I forgot something the first time let me repeat:

    the 2 fathers, mothers, and sons will cross once,one of the family members will need to cross 3 times and the cheapest individual moving alone is the daghter, in addition to the daughter of the other family, the babies will cross once, putting that in an equation:

    (2 x 5) + (2 x 4) + (2 x 3) + (4 x 2) + (2 x 1) = 34

    I missed something

    I guess I need more than maths to solve this one

    @smith 3 passengers and the money is payed to the driver

    @moningstar $33 is the maximum possible you can pay, otherwise ther would be no riddle

  6. the 2 fathers, mothers, and sons will cross once,one of the family members will need to cross 3 times and the cheapest individual moving alone is the daghter, the baby will cross once, putting that in an equation:

    (2 x 5) + (2 x 4) + (2 x 3) + (3 x 2) + (2 x 1) = 32

    I've yet to make that solution

    @smith

    Both families have a total of 33$.

    not each family has 33$, 33$ is the maximum both families combined can pay.

  7. the number of 9's after the decimal point should decrease by 1, I know infinity-1 is still infinity, but in this case it would be a different value,9.99999 x 10 would be 99.9999,so the 9's after the decimal should decrease, but stay infinity, though I don't know how to achieve that

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