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The average weight of some monkeys in a bag is doubled when one giant monkey is

added to the four monkeys already in the bag. The ratio of the weight of this giant monkey

to the total weight of the other four monkeys is 3:?

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1 giant monkey=5 times avg weight of 3 monkeys

so giant monkey : 4 monkeys = 5:8

:duh: Oops. Average isn't total weight.

If the average weight of 4 monkeys in the bag before the giant monkey goes in is x, (4x+y)/5 monkeys=2x if y is the big monkey. Solving for y gives 6x. So wouldn't it be giant:4 small = 6:4 or 3:2?

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I think it is 3 : 2

If x is the total weight of the four monkeys, the average wt. is x/4.

If y is the wt. of the big monkey, then the total wt. becomes x+y, and the average becomes (x+y)/5.

As new average is double the original, we get,

2 (x/4) = (x+y)/5

On solving, we get,

y/x = 3/2 which is what is asked

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is any of the previous answers the right one?

2 correct answers so far, post 8 from Thalia & post 9 from SMV

:duh: Oops. Average isn't total weight.

If the average weight of 4 monkeys in the bag before the giant monkey goes in is x, (4x+y)/5 monkeys=2x if y is the big monkey. Solving for y gives 6x. So wouldn't it be giant:4 small = 6:4 or 3:2?

I think it is 3 : 2

If x is the total weight of the four monkeys, the average wt. is x/4.

If y is the wt. of the big monkey, then the total wt. becomes x+y, and the average becomes (x+y)/5.

As new average is double the original, we get,

2 (x/4) = (x+y)/5

On solving, we get,

y/x = 3/2 which is what is asked

Edited by thoughtfulfellow
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