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Help Needed – 2
Posted 18 January 2012 - 07:30 PM
Rules of Game:-
"We each get one die, the highest die wins. If we tie, I win, but since you always lose when you roll a one, if you roll a one you can roll again. If you get a one the second time you have to keep it."
What is each person's probability of winning?
What are the probabilities of winning if you can keep rolling until you get something besides a one?
Posted 18 January 2012 - 07:36 PM
Posted 18 January 2012 - 09:26 PM
I still haven't worked out the second question but suspect it's just a hair under 50%
*edit: corrected some typo's
Edited by spamwolf, 18 January 2012 - 09:30 PM.
Posted 18 January 2012 - 09:46 PM
Edited by tonyd, 18 January 2012 - 09:56 PM.
Posted 19 January 2012 - 05:11 AM
I concur the answer you have for #2.Spoiler for ...
Posted 19 January 2012 - 05:31 AM
Your probability of winning given that I have a five is 2/6.
Your probability of winning given that I have a four is 3/6.
Your probability of winning given that I have a three is 4/6.
Your probability of winning given that I have a two is 5/6.
Your probability of winning given that I have a one is X.
Where X is one sixth the sum of the above without the final entry.
That is 15/36= 5/12
Your chances are one sixth the sum of the above with the calculated X (5/12).
That is 5/12 * (1 + 1/6) = 5/12 * 7/6 = 35/72
Well, I'll be darn. Never give a sucker an even break.
Edited by Common Zenz, 19 January 2012 - 05:35 AM.
Posted 19 January 2012 - 03:41 PM
Posted 19 January 2012 - 09:12 PM
For the second part, you can't use a simple grid but what others posted looks good.
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