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16 replies to this topic

#11 Jkyle1980

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Posted 19 February 2008 - 01:40 AM

WHAT???


Exactly. I rest my case.
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#12 unreality

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Posted 19 February 2008 - 10:38 PM

lol I'm with ya there, jkyle ;D
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#13 bonanova

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Posted 20 February 2008 - 11:30 PM

Yes I do.

0^0 = 0/0

that's a fact. You cant dispute that.

.....

Let me try.

I can easily show that 0/0 can be seven:

7x/x = 7. Let x->0. 7x->0 and x->0. 0/0 = 7.

If 0^0 and 0/0 are identical, then it can be shown that 0^0 can equal 7.
Care to try?
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The greatest challenge to any thinker is stating the problem in a way that will allow a solution.
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#14 niner

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Posted 21 February 2008 - 12:49 AM

Yes I do.

0^0 = 0/0

that's a fact. You cant dispute that.


I agree

0^0 = 0^(1-1)
0^(1-1)=(0^1)(0^-1)
(0^1)(0^-1) = (0/1)(1/0)
(0/1)(1/0)=0/0
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#15 unreality

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Posted 21 February 2008 - 02:05 AM

yep bonanova, 0^0 would be 7 if 0/0 also is 7 :D I did the exact same thing in the topic identical to this in the "Other" section, showing how 0/0 can be anything if you use the multiplicative (or whatever its called) property

nx/x = n

n0/0 = n

0/0 = n

or written another way:

7*0 = 0

reverse it: 7 = 0/0

however to reverse it, you actually have to divide both sides by 0

so it comes out to be:

0/0 = 0/0

which isnt much help :D

lol. But yes, if 0/0 was 7, then 0^0 would be as well ;D
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#16 unreality

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Posted 21 February 2008 - 02:13 AM

I suggest locking this cuz there's two discussions of the same thing :P
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#17 rookie1ja

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Posted 21 February 2008 - 11:11 AM

further discussion on what is 0^0 to be continued in separate thread named ZERO TO THE ZEROTH POWER

this topic is locked
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